php - mysql/php更新语法，传递php变量

Question

我有一个带有列的 mysql 表：名称，活动（活动是 int）。我想将图片上传到服务器，当它们已经在服务器上时，我想让它们处于活动状态，以便它们用作新徽标。（当 active = 1 时，图片是新徽标）我无法弄清楚为什么我的“$query”不起作用。其他一切正常。

$name = $_FILES["file"]["name"]; 
if (file_exists("/home/a1829256/public_html/admin/logo/" .$name)){          //if file already on the server
        echo "file is already on the server";
        echo ". Making it the new logo";
        $deselectlogo = "UPDATE newlogo SET active=0 WHERE active>0";               //deselect old
        $deselectlogoResult = mysql_query($deselectlogo);
        $query = ("UPDATE newlogo SET active=1 WHERE name=" .$name);            // make the new logo active
        $queryResult = mysql_query($query);
        if (!$queryResult){echo "error";}
        if ($queryResult){echo "success";}

Answer 1

   $query = "UPDATE newlogo SET active=1 WHERE name='".$name."'";            // make the new logo active