我遇到了一个问题，最简单的解决方案是在 mysql 中添加一个跨多个表的唯一索引。这可能吗？
为了这个问题的目的，我将有三个表格；status,tracks和events. 和表都有一个自动递增的 ID（status或） 。来自它们的信息通过触发器添加到表中。问题是 和 中可能有相同的自动递增 ID ，这意味着它们在 中可能不止一次是相同的 ID 。tracksT_IDS_IDeventstracksstatusevents
tracks;
CREATE TABLE `tracks` (
`ID` int(11) NOT NULL,
`url` varchar(200) COLLATE latin1_general_ci NOT NULL,
`name` varchar(100) COLLATE latin1_general_ci NOT NULL,
`timestamp` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00' ON UPDATE CURRENT_TIMESTAMP,
`T_ID` int(11) NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`T_ID`),
UNIQUE KEY `url` (`url`),
UNIQUE KEY `T_ID` (`T_ID`),
KEY `ID` (`ID`),
CONSTRAINT `tracks_ibfk_1` FOREIGN KEY (`ID`) REFERENCES `members` (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=9 DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci
status
CREATE TABLE `status` (
`ID` int(11) NOT NULL,
`status` varchar(300) COLLATE latin1_general_ci NOT NULL,
`timestamp` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00' ON UPDATE CURRENT_TIMESTAMP,
`S_ID` int(11) NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`S_ID`),
UNIQUE KEY `S_ID` (`S_ID`),
KEY `ID` (`ID`),
CONSTRAINT `status_ibfk_1` FOREIGN KEY (`ID`) REFERENCES `artists` (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=13 DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci
events
CREATE TABLE `events` (
`ID` int(11) NOT NULL,
`action` varchar(100) COLLATE latin1_general_ci NOT NULL,
`timestamp` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00' ON UPDATE CURRENT_TIMESTAMP,
`E_ID` int(11) NOT NULL,
KEY `ID` (`ID`),
CONSTRAINT `events_ibfk_1` FOREIGN KEY (`ID`) REFERENCES `members` (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci COMMENT='This table shows what the artist has done and is used feed'