8

我想将十六进制颜色转换为 RGB 颜色。

我使用了以下代码:

Me.BackColor = RGB("#000000")

但随后它会引发以下异常:

Argument not specified for parameter 'Green' of 'Public Function RGB(Red As Integer, Green As Integer, Blue As Integer) As Integer'

正确的方法是什么?

4

2 回答 2

30

通过颜色翻译:

ColorTranslator.FromHtml("#003399") 

其他方法:

Public Function ConvertToRbg(ByVal HexColor As String) As Color
    Dim Red As String
    Dim Green As String
    Dim Blue As String
    HexColor = Replace(HexColor, "#", "")
    Red = Val("&H" & Mid(HexColor, 1, 2))
    Green = Val("&H" & Mid(HexColor, 3, 2))
    Blue = Val("&H" & Mid(HexColor, 5, 2))
    Return Color.FromArgb(Red, Green, Blue)
End Function

或者:

Public Shared Function HexToColor(ByVal hexColor As String) As Color
    If hexColor.IndexOf("#"c) <> -1 Then
        hexColor = hexColor.Replace("#", "")
    End If
    Dim red As Integer = 0
    Dim green As Integer = 0
    Dim blue As Integer = 0
    If hexColor.Length = 6 Then
        red = Integer.Parse(hexColor.Substring(0, 2), NumberStyles.AllowHexSpecifier)
        green = Integer.Parse(hexColor.Substring(2, 2), NumberStyles.AllowHexSpecifier)
        blue = Integer.Parse(hexColor.Substring(4, 2), NumberStyles.AllowHexSpecifier)
    ElseIf hexColor.Length = 3 Then
        red = Integer.Parse(hexColor(0).ToString() + hexColor(0).ToString(), NumberStyles.AllowHexSpecifier)
        green = Integer.Parse(hexColor(1).ToString() + hexColor(1).ToString(), NumberStyles.AllowHexSpecifier)
        blue = Integer.Parse(hexColor(2).ToString() + hexColor(2).ToString(), NumberStyles.AllowHexSpecifier)
    End If
    Return Color.FromArgb(red, green, blue)
End Function

或者:

    Dim c As String = "#ffffff"
    c = Replace(c, "#", "")
    c = "&H" & c
    ColorTranslator.FromOle(c)

或者:

Public Function hexToRbgNew(ByVal Hex As String) As Color
    Hex = Replace(Hex, "#", "")
    Dim red As String = "&H" & Hex.Substring(0, 2)
    Hex = Replace(Hex, red, "", , 1)
    Dim green As String = "&H" & Hex.Substring(0, 2)
    Hex = Replace(Hex, green, "", , 1)
    Dim blue As String = "&H" & Hex.Substring(0, 2)
    Hex = Replace(Hex, blue, "", , 1)
    Return Color.FromArgb(red, green, blue)
End Function
于 2012-11-13T06:39:30.440 回答
2

这对我有用:(vb.Net)

cell.BackColor = Drawing.Color.FromArgb(&H3399FF)
于 2019-03-06T20:16:49.997 回答