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当用户触摸屏幕时，我想向下滚动屏幕。我在我的 vc 中实现了 touchesBegan:withEvent: 方法，这就是我想出的。

 -(void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event{
       UIScrollView *scrollView=[[UIScrollView alloc]initWithFrame:CGRectMake(0,0,self.view.frame.size.width, self.view.frame.size.height)];
       scrollView.contentSize=CGSizeMake(self.view.frame.size.width, self.view.frame.size.height);
       [self.view addSubview:scrollView];
       [scrollView scrollRectToVisible:CGRectMake(0,100,self.view.frame.size.width,self.view.frame.size.height) animated:YES];

}
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1 回答 1

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哦，当我将矩形滚动到可见时，我需要确保我的大小保持不变

于 2012-11-06T04:46:45.937 回答