16

我想知道如何使用 Spring Security 通过 IP 过滤用户对我的 Web 应用程序的访问。我应该扩展AbstractAuthenticationProcessingFilter或类似的东西并以我自己的方式覆盖它的方法吗？如果是这样，您能否举一个这样的扩展示例和过滤器描述示例web.xml？提前致谢。

PS 在我的应用程序中，我也有 Spring Security 支持（使用 default org.springframework.web.filter.DelegatingFilterProxy），但我希望它不仅检查用户凭据，还检查他们的 IP。

4

2 回答 2

15

一种方法是使用 Spring Security 的Web Security Expressions。例如：

<http use-expressions="true">
    <intercept-url pattern="/admin*"
        access="hasRole('admin') and hasIpAddress('192.168.1.0/24')"/>
    ...
</http>
于 2012-10-08T17:06:14.100 回答
1

Anshu 的回答是通过 ip 对用户进行身份验证是一个好主意，但它可能不适用于 cas 身份验证。我有另一种解决方案，使用过滤器更适合这种情况。

public class IPAuthenticationFilter extends AbstractAuthenticationProcessingFilter {
    private AuthenticationUserDetailsService<CasAssertionAuthenticationToken> authenticationUserDetailsService;
    private static Set<String> ipWhitelist;

    @Autowired
    private AppProperty appProperty;

    @PostConstruct
    public void init() {
        ipWhitelist = new HashSet<>(Arrays.asList(appProperty.getIpWhitelist()));
        setAuthenticationSuccessHandler(new AuthenticationSuccessHandler() {
            @Override
            public void onAuthenticationSuccess(
                    HttpServletRequest httpServletRequest,
                    HttpServletResponse httpServletResponse,
                    Authentication authentication) throws IOException, ServletException {
                // do nothing
            }
        });
    }

    public IPAuthenticationFilter() {
        super("/");
    }

    public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response)
            throws AuthenticationException, IOException {
        String userName = request.getHeader(appProperty.getHeaderCurUser());
        Assertion assertion = new AssertionImpl(userName);
        CasAssertionAuthenticationToken token = new CasAssertionAuthenticationToken(assertion, "");
        UserDetails userDetails = authenticationUserDetailsService.loadUserDetails(token);

        CasAuthenticationToken result = new CasAuthenticationToken(
                "an-id-for-ip-auth",
                userDetails,
                request.getRemoteAddr(),
                userDetails.getAuthorities(),
                userDetails,
                assertion
        );
        return result;
    }

    protected boolean requiresAuthentication(HttpServletRequest request, HttpServletResponse response) {
        String userName = request.getHeader(appProperty.getHeaderCurUser());
        return ipWhitelist.contains(request.getRemoteAddr()) && !StringUtils.isEmpty(userName);
    }

    protected void successfulAuthentication(
            HttpServletRequest request,
            HttpServletResponse response,
            FilterChain chain,
            Authentication authResult) throws IOException, ServletException {
        super.successfulAuthentication(request, response, chain, authResult);
        chain.doFilter(request, response);
    }

    public AuthenticationUserDetailsService<CasAssertionAuthenticationToken> getAuthenticationUserDetailsService() {
        return authenticationUserDetailsService;
    }

    public void setAuthenticationUserDetailsService(
            AuthenticationUserDetailsService<CasAssertionAuthenticationToken> authenticationUserDetailsService) {
        this.authenticationUserDetailsService = authenticationUserDetailsService;
    }
}

您可以在 cas 之前添加此过滤器，如下所示：

http.addFilterBefore(ipAuthenticationFilter(), CasAuthenticationFilter.class)
于 2017-12-26T10:02:57.557 回答