2

我有一个看起来像这样的输入 XML，并希望使用 XSL 转换获得如下所示的所需输出。我一直在浏览博客，但找不到与如何删除仅匹配根元素而不匹配子节点的空标签的任何相关性。

<?xml version="1.0" encoding="UTF-8"?>
<objects xmlns="urn:sobject.partner.soap.sforce.com">
  <Revenue__c/>
  <Revenue__c/>
  <Revenue__c/>
  <Revenue__c>
    <Sales_Org_ID__c>IV</Sales_Org_ID__c>
    <Branch_ID__c>1</Branch_ID__c>
    <Branch_Name__c>TEST</Branch_Name__c>
    <Therapy_Code__c>TEST</Therapy_Code__c>
    <Therapy_Name__c>TEST</Therapy_Name__c>
    <Therapy_Class_Code__c>TEST</Therapy_Class_Code__c>
    <Therapy_Class_Name__c>TEST</Therapy_Class_Name__c>
    <Payor_Type_Name__c>TEST</Payor_Type_Name__c>
    <Calendar_Year_Number__c>2011</Calendar_Year_Number__c>
    <Month_Revenue_Amount__c>100.01</Month_Revenue_Amount__c>
    <Payor_ID__c>TEST</Payor_ID__c>
    <Payor_Name__c/>
    <Payor_Type_Code__c>TEST</Payor_Type_Code__c>
    <MDM_Account_EID__c>66600001</MDM_Account_EID__c>
    <MDM_Physician_EID__c>99900001</MDM_Physician_EID__c>
    <Account__c>001a000001APU5OAAX</Account__c>
    <Contact__c>003a000001RL1EFAA1</Contact__c>
    <Revenue_ID__c>41</Revenue_ID__c>
    <Calendar_Year_Month__c>01</Calendar_Year_Month__c>
  </Revenue__c>
</objects>

这正是我想要的结果：

<?xml version="1.0" encoding="UTF-8"?>
<objects xmlns="urn:sobject.partner.soap.sforce.com">
  <Revenue__c>
    <Sales_Org_ID__c>IV</Sales_Org_ID__c>
    <Branch_ID__c>1</Branch_ID__c>
    <Branch_Name__c>TEST</Branch_Name__c>
    <Therapy_Code__c>TEST</Therapy_Code__c>
    <Therapy_Name__c>TEST</Therapy_Name__c>
    <Therapy_Class_Code__c>TEST</Therapy_Class_Code__c>
    <Therapy_Class_Name__c>TEST</Therapy_Class_Name__c>
    <Payor_Type_Name__c>TEST</Payor_Type_Name__c>
    <Calendar_Year_Number__c>2011</Calendar_Year_Number__c>
    <Month_Revenue_Amount__c>100.01</Month_Revenue_Amount__c>
    <Payor_ID__c>TEST</Payor_ID__c>
    <Payor_Name__c/>
    <Payor_Type_Code__c>TEST</Payor_Type_Code__c>
    <MDM_Account_EID__c>66600001</MDM_Account_EID__c>
    <MDM_Physician_EID__c>99900001</MDM_Physician_EID__c>
    <Account__c>001a000001APU5OAAX</Account__c>
    <Contact__c>003a000001RL1EFAA1</Contact__c>
    <Revenue_ID__c>41</Revenue_ID__c>
    <Calendar_Year_Month__c>01</Calendar_Year_Month__c>
  </Revenue__c>
</objects>

任何建议将不胜感激。

4

2 回答 2

5

这可能是最简单/最短的解决方案，同时完全是“推式”并且最具可扩展性和可维护性——没有硬编码的元素名称，没有文字结果元素，没有命名空间，没有xsl:copy-of：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
 </xsl:template>
 <xsl:template match="/*/*[not(node())]"/>
</xsl:stylesheet>

当此转换应用于提供的 XML 文档时：

<objects xmlns="urn:sobject.partner.soap.sforce.com">
    <Revenue__c/>
    <Revenue__c/>
    <Revenue__c/>
    <Revenue__c>
        <Sales_Org_ID__c>IV</Sales_Org_ID__c>
        <Branch_ID__c>1</Branch_ID__c>
        <Branch_Name__c>TEST</Branch_Name__c>
        <Therapy_Code__c>TEST</Therapy_Code__c>
        <Therapy_Name__c>TEST</Therapy_Name__c>
        <Therapy_Class_Code__c>TEST</Therapy_Class_Code__c>
        <Therapy_Class_Name__c>TEST</Therapy_Class_Name__c>
        <Payor_Type_Name__c>TEST</Payor_Type_Name__c>
        <Calendar_Year_Number__c>2011</Calendar_Year_Number__c>
        <Month_Revenue_Amount__c>100.01</Month_Revenue_Amount__c>
        <Payor_ID__c>TEST</Payor_ID__c>
        <Payor_Name__c/>
        <Payor_Type_Code__c>TEST</Payor_Type_Code__c>
        <MDM_Account_EID__c>66600001</MDM_Account_EID__c>
        <MDM_Physician_EID__c>99900001</MDM_Physician_EID__c>
        <Account__c>001a000001APU5OAAX</Account__c>
        <Contact__c>003a000001RL1EFAA1</Contact__c>
        <Revenue_ID__c>41</Revenue_ID__c>
        <Calendar_Year_Month__c>01</Calendar_Year_Month__c>
    </Revenue__c>
</objects>

产生了想要的正确结果：

<objects xmlns="urn:sobject.partner.soap.sforce.com">
   <Revenue__c>
      <Sales_Org_ID__c>IV</Sales_Org_ID__c>
      <Branch_ID__c>1</Branch_ID__c>
      <Branch_Name__c>TEST</Branch_Name__c>
      <Therapy_Code__c>TEST</Therapy_Code__c>
      <Therapy_Name__c>TEST</Therapy_Name__c>
      <Therapy_Class_Code__c>TEST</Therapy_Class_Code__c>
      <Therapy_Class_Name__c>TEST</Therapy_Class_Name__c>
      <Payor_Type_Name__c>TEST</Payor_Type_Name__c>
      <Calendar_Year_Number__c>2011</Calendar_Year_Number__c>
      <Month_Revenue_Amount__c>100.01</Month_Revenue_Amount__c>
      <Payor_ID__c>TEST</Payor_ID__c>
      <Payor_Name__c/>
      <Payor_Type_Code__c>TEST</Payor_Type_Code__c>
      <MDM_Account_EID__c>66600001</MDM_Account_EID__c>
      <MDM_Physician_EID__c>99900001</MDM_Physician_EID__c>
      <Account__c>001a000001APU5OAAX</Account__c>
      <Contact__c>003a000001RL1EFAA1</Contact__c>
      <Revenue_ID__c>41</Revenue_ID__c>
      <Calendar_Year_Month__c>01</Calendar_Year_Month__c>
   </Revenue__c>
</objects>

说明：

  1. 身份规则“按原样”复制选择此模板执行的任何节点。

  2. 对于作为顶部元素的子元素且没有子元素的任何元素，都有一个模板覆盖标识模板。这个模板没有正文（不产生任何输出），它有效地“删除”了匹配的节点。

于 2012-10-04T11:34:03.050 回答
1

应该这样做 - 它apply-templates仅用于具有子节点的收入节点，然后copy-of复制非空的收入树。

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:x="urn:sobject.partner.soap.sforce.com"
                exclude-result-prefixes="x">
  <xsl:output method="xml" indent="yes" omit-xml-declaration="no"/>

  <xsl:template match="/x:objects">
    <objects xmlns="urn:sobject.partner.soap.sforce.com">
      <xsl:apply-templates select="x:Revenue__c[*]" />
    </objects>
  </xsl:template>

  <xsl:template match="x:Revenue__c">
    <xsl:copy-of select="."/>
  </xsl:template>
</xsl:stylesheet>

输出

<?xml version="1.0" encoding="utf-8"?>
<objects xmlns="urn:sobject.partner.soap.sforce.com">
  <Revenue__c>
    <Sales_Org_ID__c>IV</Sales_Org_ID__c>
    <Branch_ID__c>1</Branch_ID__c>
    <Branch_Name__c>TEST</Branch_Name__c>
    <Therapy_Code__c>TEST</Therapy_Code__c>
    <Therapy_Name__c>TEST</Therapy_Name__c>
    <Therapy_Class_Code__c>TEST</Therapy_Class_Code__c>
    <Therapy_Class_Name__c>TEST</Therapy_Class_Name__c>
    <Payor_Type_Name__c>TEST</Payor_Type_Name__c>
    <Calendar_Year_Number__c>2011</Calendar_Year_Number__c>
    <Month_Revenue_Amount__c>100.01</Month_Revenue_Amount__c>
    <Payor_ID__c>TEST</Payor_ID__c>
    <Payor_Name__c />
    <Payor_Type_Code__c>TEST</Payor_Type_Code__c>
    <MDM_Account_EID__c>66600001</MDM_Account_EID__c>
    <MDM_Physician_EID__c>99900001</MDM_Physician_EID__c>
    <Account__c>001a000001APU5OAAX</Account__c>
    <Contact__c>003a000001RL1EFAA1</Contact__c>
    <Revenue_ID__c>41</Revenue_ID__c>
    <Calendar_Year_Month__c>01</Calendar_Year_Month__c>
  </Revenue__c>
</objects>

编辑- 可以简化：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:x="urn:sobject.partner.soap.sforce.com"
                exclude-result-prefixes="x">
  <xsl:output method="xml" indent="yes" omit-xml-declaration="no"/>

  <xsl:template match="/x:objects">
    <objects xmlns="urn:sobject.partner.soap.sforce.com">
      <xsl:copy-of select="x:Revenue__c[*]" />
    </objects>
  </xsl:template>
</xsl:stylesheet>
于 2012-10-04T05:34:20.210 回答