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我正在尝试从相机或画廊加载图像（不是 URL）并将其保存到全局类。（目前我正在尝试获取图像，尚未定义类）。

所以我认为相机正确返回图像，并将其放入捆绑包中，如果可能的话，我喜欢对画廊使用相同的方法。

所以我有：

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    // TODO Auto-generated method stub
    super.onActivityResult(requestCode, resultCode, data);
    if(resultCode==RESULT_OK){
        Bundle extras = data.getExtras();
        bmp = (Bitmap) extras.get("data");

    }
}

而这两个选择，显然我在画廊做错了什么：

public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3) {
    // TODO Auto-generated method stub
    switch(arg2){
    case 0:
        i = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
        startActivityForResult(i, cameraData);
        break;
    case 1:

        Intent intent = new Intent( Intent.ACTION_GET_CONTENT );
        intent.setType( "image/*" );

        //i = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
        startActivityForResult(intent, 10); 
        break;
    }

我收到失败的结果：资源上的空指针异常：dat=content://media/external/images/media/23

所以我想我做错了什么。

Idea is similar to behavior seen in Instagram, take photo or select existing one, and when selected it should be stored in some singletone object, as I'll have 3 more options that can be selected before image is shown again within my app.

我不确定这是否是处理图像的最佳方式，所以这里也欢迎任何建议。

肿瘤坏死因子

4

1 回答 1

1

onActivityResult，试试这个代码。

InputStream in = getContentResolver().openInputStream(data.getData());
// get picture size.
BitmapFactory.Options options = new BitmapFactory.Options();
options.inJustDecodeBounds = true;
BitmapFactory.decodeStream(in, null, options);
in.close();
// resize the picture for memory.
int width = options.outWidth / displayWidth + 1;
int height = options.outHeight / displayHeight + 1;
int sampleSize = Math.max(width, height);
options.inSampleSize = sampleSize;
options.inJustDecodeBounds = false;
in = getContentResolver().openInputStream(data.getData());
// convert to bitmap with declared size.
Bitmap bitmap = BitmapFactory.decodeStream(in, null, options);
in.close();
于 2012-09-19T09:32:30.367 回答