感谢 stackoverflow 的人,他们帮助我实现了使用 Ajax 的功能,但现在我遇到了另一个问题。下面是代码:
if(isset($_POST['site'])){
if($_POST['site'] == NULL)
{
echo "Field cannot be empty";
return;
}
//here we check site validation on server side 
if (!preg_match("~^(?:(?:https?|ftp|telnet)://(?:[a-z0-9_-]{1,32}".
"(?::[a-z0-9_-]{1,32})?@)?)?(?:(?:[a-z0-9-]{1,128}\.)+(?:com|net|".
"org|mil|edu|arpa|gov|biz|info|aero|inc|name|[a-z]{2})|(?!0)(?:(?".
"!0[^.]|255)[0-9]{1,3}\.){3}(?!0|255)[0-9]{1,3})(?:/[a-z0-9.,_@%&".
"?+=\~/-]*)?(?:#[^ '\"&<>]*)?$~i", $_POST['site']))
{
echo "<br/>";
echo "<div id='err'>Oooops!!! Wrong site name</div>";
return;
} 
$homepage = file_get_contents("http://".$_POST['site']);
preg_match('%<meta.*name="keywords".*content="(.*)"\s+/>%U', $homepage, $regs);
if(count($regs))
 {
$myString = implode( '', $regs );  
 echo "<br/>";
 echo "<div id='test'>Keywords:</div>";
 print_r( "<div id='test2'>$myString</div>");
}
else
{
echo "<br/>";
echo "<div id='test'>There is no keywords</div>";
}
}
?>
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>    
<script type="text/javascript">
$(document).ready(function(){
     $('#payment').submit(function(e){
        e.preventDefault();
        var x = $('input[name=site]').val();
       $.ajax({
             type: "POST",
            url: 'test.php',
            //data: $(this).serialize(),
            data: x,
            datatype: 'json',
            success: function(data)
            {
                 $('#metaTags').text(data)
            },
             error:   function(xhr, ajaxOptions, thrownError) { alert(xhr.status);} 
        });
    });
});
</script>
</head>     
<div>
<form id="payment"    method="post" name="forma1">
    <label for=name>ENTER www.bbc.com:</label>
    <input id="name" type=text placeholder="Write here..."         name="site">
    <input type="submit" value="START" name="searchbutton" id="sb">
</form>
<div id="metaTags"></div>
</div>  
</html> 
一切正常,但您可以在此处看到输出: http ://tsite.500mb.net/test.php 用于测试类型,例如:www.bbc.com,您将看到输出结果我需要 otput 将只有元标记,没有源代码。怎么做?我尝试了下一个想法:
var x = $('input[name=site]').val();
 $.ajax({
             type: "POST",
            url: 'test.php',
    data: x,
其中 data = x 和 x - 来自输入文本框的值,但它没有帮助。有任何想法吗?