我找不到如何使用 Apache POI API 删除列。
在这一点上，我将不胜感激示例代码或帮助。
VGS
问问题
30628 次
5 回答
18
邮件列表上的 Alan Williamson写了一个小帮手，用于移除列
package org.alanwilliamson.openbd.plugin.spreadsheet;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.ss.usermodel.Sheet;
/*
* Helper functions to aid in the management of sheets
*/
public class SheetUtility extends Object {
/**
* Given a sheet, this method deletes a column from a sheet and moves
* all the columns to the right of it to the left one cell.
*
* Note, this method will not update any formula references.
*
* @param sheet
* @param column
*/
public static void deleteColumn( Sheet sheet, int columnToDelete ){
int maxColumn = 0;
for ( int r=0; r < sheet.getLastRowNum()+1; r++ ){
Row row = sheet.getRow( r );
// if no row exists here; then nothing to do; next!
if ( row == null )
continue;
// if the row doesn't have this many columns then we are good; next!
int lastColumn = row.getLastCellNum();
if ( lastColumn > maxColumn )
maxColumn = lastColumn;
if ( lastColumn < columnToDelete )
continue;
for ( int x=columnToDelete+1; x < lastColumn + 1; x++ ){
Cell oldCell = row.getCell(x-1);
if ( oldCell != null )
row.removeCell( oldCell );
Cell nextCell = row.getCell( x );
if ( nextCell != null ){
Cell newCell = row.createCell( x-1, nextCell.getCellType() );
cloneCell(newCell, nextCell);
}
}
}
// Adjust the column widths
for ( int c=0; c < maxColumn; c++ ){
sheet.setColumnWidth( c, sheet.getColumnWidth(c+1) );
}
}
/*
* Takes an existing Cell and merges all the styles and forumla
* into the new one
*/
private static void cloneCell( Cell cNew, Cell cOld ){
cNew.setCellComment( cOld.getCellComment() );
cNew.setCellStyle( cOld.getCellStyle() );
switch ( cNew.getCellType() ){
case Cell.CELL_TYPE_BOOLEAN:{
cNew.setCellValue( cOld.getBooleanCellValue() );
break;
}
case Cell.CELL_TYPE_NUMERIC:{
cNew.setCellValue( cOld.getNumericCellValue() );
break;
}
case Cell.CELL_TYPE_STRING:{
cNew.setCellValue( cOld.getStringCellValue() );
break;
}
case Cell.CELL_TYPE_ERROR:{
cNew.setCellValue( cOld.getErrorCellValue() );
break;
}
case Cell.CELL_TYPE_FORMULA:{
cNew.setCellFormula( cOld.getCellFormula() );
break;
}
}
}
}
于 2012-09-25T13:32:10.597 回答
4
cporte 的答案非常好，但恕我直言有点难以阅读。
理念：
对于每一行，删除代表要删除的列的单元格，并将该列右侧的所有单元格向左移动一个。
简化的实现：
//Variables for completeness
Sheet sheet;
int columnToDelete;
for (int rId = 0; rId <= sheet.getLastRowNum(); rId++) {
Row row = sheet.getRow(rId);
for (int cID = columnToDelete; cID < row.getLastCellNum(); cID++) {
Cell cOld = row.getCell(cID);
if (cOld != null) {
row.removeCell(cOld);
}
Cell cNext = row.getCell(cID + 1);
if (cNext != null) {
Cell cNew = row.createCell(cID, cNext.getCellType());
cloneCell(cNew, cNext);
sheet.setColumnWidth(cID, sheet.getColumnWidth(cID + 1));
}
}
}
为了完整性，从另一个答案复制了克隆单元方法：
private static void cloneCell( Cell cNew, Cell cOld ){
cNew.setCellComment( cOld.getCellComment() );
cNew.setCellStyle( cOld.getCellStyle() );
switch ( cNew.getCellType() ){
case Cell.CELL_TYPE_BOOLEAN:{
cNew.setCellValue( cOld.getBooleanCellValue() );
break;
}
case Cell.CELL_TYPE_NUMERIC:{
cNew.setCellValue( cOld.getNumericCellValue() );
break;
}
case Cell.CELL_TYPE_STRING:{
cNew.setCellValue( cOld.getStringCellValue() );
break;
}
case Cell.CELL_TYPE_ERROR:{
cNew.setCellValue( cOld.getErrorCellValue() );
break;
}
case Cell.CELL_TYPE_FORMULA:{
cNew.setCellFormula( cOld.getCellFormula() );
break;
}
}
}
于 2017-04-28T14:07:08.530 回答
3
codewing 的解决方案对我来说就像一个魅力，有以下细微的变化：
- 当我们克隆单元格时，调用应该是 cloneCell(cNew, cNext)
- 我们应该只为第一行设置列宽。
- 我使用的是 3.17 版的 api，所以有些地方发生了变化（比如 CellType 从 int 变为 enum）。
完整代码如下（为清楚起见）：
private void deleteColumn(Sheet sheet, int columnToDelete) {
for (int rId = 0; rId < sheet.getLastRowNum(); rId++) {
Row row = sheet.getRow(rId);
for (int cID = columnToDelete; cID < row.getLastCellNum(); cID++) {
Cell cOld = row.getCell(cID);
if (cOld != null) {
row.removeCell(cOld);
}
Cell cNext = row.getCell(cID + 1);
if (cNext != null) {
Cell cNew = row.createCell(cID, cNext.getCellTypeEnum());
cloneCell(cNew, cNext);
//Set the column width only on the first row.
//Other wise the second row will overwrite the original column width set previously.
if(rId == 0) {
sheet.setColumnWidth(cID, sheet.getColumnWidth(cID + 1));
}
}
}
}
}
private void cloneCell(Cell cNew, Cell cOld) {
cNew.setCellComment(cOld.getCellComment());
cNew.setCellStyle(cOld.getCellStyle());
if (CellType.BOOLEAN == cNew.getCellTypeEnum()) {
cNew.setCellValue(cOld.getBooleanCellValue());
} else if (CellType.NUMERIC == cNew.getCellTypeEnum()) {
cNew.setCellValue(cOld.getNumericCellValue());
} else if (CellType.STRING == cNew.getCellTypeEnum()) {
cNew.setCellValue(cOld.getStringCellValue());
} else if (CellType.ERROR == cNew.getCellTypeEnum()) {
cNew.setCellValue(cOld.getErrorCellValue());
} else if (CellType.FORMULA == cNew.getCellTypeEnum()) {
cNew.setCellValue(cOld.getCellFormula());
}
}
于 2017-11-18T01:00:55.103 回答
1
我认为您必须访问每个 HSSFRow 并调用 HSSFRow.getCell，然后调用 HSSFRow.removeCell。API 面向行，而不是列，很少有操作在整个列级别进行。
示例代码（未经测试）：
HSSFSheet sheet = ...
int colToRemove = 5;
Iterator rowIter = sheet.iterator();
while (rowIter.hasNext()) {
HSSFRow row = (HSSFRow)rowIter.next();
HSSFCell cell = row.getCell(colToRemove);
row.removeCell(cell);
}
于 2009-07-24T21:39:06.897 回答
0
有一个术语混淆：作者作者想要实现的操作称为列移位它术语 Apache POI 接口。org.apache.poi.ss.usermodel.Sheet接口提供了一个干净的方法来做这样的事情：
sheet.shiftColumns(startRangeIndex, endRangeIndex, directionQuantifier);
例如，将 B 列向左移动一个位置很容易通过调用来实现：
Sheet sheet = loadRequiredSheet();
sheet.shiftColumns(2, 3, -1);
Column A Column B Column C
Data here to be removed <- t should be moved to the left
于 2020-07-31T03:00:07.667 回答