0

该程序从文本文件中输入一个字符串,例如:

2 1.0 2.0 3.0 4.0

其中第一个数字是方阵的维数,其他数字是矩阵的元素(以列主要形式存储)。每个数字都用“空格”字符分隔。程序将所有数字添加到单个列上,并乘以这种类型的每个结果。带有此字符串的 IE 结果将是:21.0 问题是:使用此输入,程序的输出将是:

输入字符串为 2 1.0 2.0 3.0 4.0

从字符串中提取 char 类型标记 1.0

从字符串中提取char类型token 2.0

从字符串中提取char类型token 3.0

从字符串中提取char类型token 4.0

将char类型token 1.0转换为float类型

将char类型token 2.0转换为float类型

将char类型token 2.0转换为float类型

将char类型token 3.0转换为float类型

浮点类型的打印矩阵:

1.000000

2.000000

2.000000

3.000000

最终结果是 15.000000

相反,它应该是:输入字符串是 2 1.0 2.0 3.0 4.0

从字符串中提取 char 类型标记 1.0

从字符串中提取char类型token 2.0

从字符串中提取char类型token 3.0

从字符串中提取char类型token 4.0

将 char 类型 token 1.0 转换为 float 类型 将 char 类型 token 2.0 转换为

float 类型 char 类型 token 2.0 转换成 float 类型 Converted

char型token 3.0转成float型

浮点类型的打印矩阵:

1.000000

2.000000

3.000000

4.000000

最终结果是 24.000000

这里的代码

#include <sys/types.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <errno.h>




/* void calculus(char string[], int matrixDimension)
 * Executes the following procedure:
 * 1) it extracts from the string, various char type tokens
 * 2) converts these char type tokens into float types and stores it into "squareMatrix" bidimensional vector
 * 3) does the calculus
 */
void calculus(char string[]);





int main()
{
    FILE* fileToReadFd;
    int nRead;
    char string[500] = {0};
    const char pathNameRead[] = "/home/caterpillar/canc/matrice2.txt";
    if((fileToReadFd = fopen(pathNameRead, "r")) == NULL)
    {
        printf("Ho provato ad aprire %s\n", pathNameRead);
        printf("errore nell'aprire il file\n" "%s\n", strerror(errno));
    }
    nRead=fread(&string[0],sizeof(char),100,fileToReadFd);


    printf("Input string is %s\n", &string[0]);
    calculus(string);
    fclose(fileToReadFd);
    return 0;

}


void calculus(char string[])
{
    int matrixDimension = atoi(&string[0]);

    float finalResult = 1;

    // float type square matrix to be filled
    float squareMatrix[matrixDimension][matrixDimension];

    // stores the result of every column addition
    float columnAddition[matrixDimension];

    /*
     * stores tokens from the string
     * I.E.:
     * token[0] contains "1.0"
     * token[1] contains "2.0"
     * token[2] contains "3.0"
     * token[3] contains "4.0"
     */
    char tokens[matrixDimension * matrixDimension][8];

    /*
     * zero initialize columnAddition vector
     */
    for(int i = 0; i < matrixDimension; i++)
    {
        columnAddition[i] = 0;
    }

    /*
     *  First strtok is necessary to be left alone since it takes away
     *  the first token that is not usefull ( it is the matrix dimension)
     */
    strtok(&string[0], " ");
    for(int i = 0; i < (matrixDimension * matrixDimension); i++)
    {
        strcpy(&tokens[i][0], strtok(NULL, " "));
        printf("Extracted char type token %s from the string\n", &tokens[i][0]);
    }

    for(int i = 0; i < matrixDimension; i++)
    {
        for(int j = 0; j < matrixDimension; j++)
        {
            squareMatrix[i][j] = atof(&tokens[i+j][0]);
            printf("Converted char type token %s into float type\n", &tokens[i+j][0]);
        }
    }
    printf("\nPrinting matrix of float types:\n");
    for(int i = 0; i < matrixDimension; i++)
    {
        for(int j = 0; j < matrixDimension; j++)
        {
            printf("%f\n", squareMatrix[i][j]);
        }
    }
    // does calculus
    for(int j = 0; j < matrixDimension; j++)
    {
        for(int i = 0; i < matrixDimension; i++)
        {

            columnAddition[j] = columnAddition[j] + squareMatrix[i][j];
        }
    }
    for(int i = 0; i < matrixDimension; i++)
    {
        finalResult = finalResult * columnAddition[i];
    }
    printf("Final result is %f\n", finalResult);
}
4

1 回答 1

3

我相信这是问题所在:

squareMatrix[i][j] = atof(&tokens[i+j][0]);
printf("Converted char type token %s into float type\n", &tokens[i+j][0]);

因为这将为 (i=0, j=1) 和 (i=1, j=0) 引用相同的标记,因为 1+0 = 1 和 0+1 = 1

它应该是

squareMatrix[i][j] = atof(&tokens[i*matrixDimension+j][0]);
printf("Converted char type token %s into float type\n", &tokens[i*matrixDimension+j][0]);
于 2012-07-14T14:22:29.650 回答