下面你可以看到我的代码,它使用 Winsock 在 C++ 中实现了一个非常基本的 UDP 发送器。问题是,无论我运行多少次代码,套接字(listenSocket)都会绑定到不同的 UDP 端口。这有什么具体原因吗?我在我的代码中犯了一些错误吗?
谢谢
#include <cstdlib>
#include <iostream>
#include <windows.h>
#include <winsock2.h>
#include <ws2tcpip.h>
#include <stdio.h>
using namespace std;
int main(int argc, char *argv[])
{
WSADATA wsaData;
SOCKADDR_IN myAddress;
SOCKADDR_IN targetAddress;
int myPort = 60888;
const char *myIP = "192.168.0.1";
int remotePort = 2048;
const char *remoteIP = "192.168.0.2";
SOCKET ListenSocket = INVALID_SOCKET;
SOCKET SendSocket = INVALID_SOCKET;
SOCKET acceptSocket;
char cBuffer[1024] = "Test Buffer";
int nBytesSent = 0;
int nBufSize = strlen(cBuffer);
int iResult;
// Initialize Winsock
if( WSAStartup( MAKEWORD(2, 2), &wsaData ) != NO_ERROR )
{
cerr<<"Socket Initialization: Error with WSAStartup\n";
system("pause");
WSACleanup();
exit(10);
}
ListenSocket = socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP);
SendSocket = socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP);
if (ListenSocket == INVALID_SOCKET or SendSocket == INVALID_SOCKET)
{
cerr<<"Socket Initialization: Error creating socket"<<endl;
system("pause");
WSACleanup();
exit(11);
}
//bind
myAddress.sin_family = AF_INET;
myAddress.sin_addr.s_addr = inet_addr(myIP);
myAddress.sin_port = htons(myPort);
targetAddress.sin_family = AF_INET;
targetAddress.sin_addr.s_addr = inet_addr(remoteIP);
targetAddress.sin_port = htons(remotePort);
if(bind(ListenSocket, (SOCKADDR*) &myAddress, sizeof(myAddress)) == SOCKET_ERROR)
{
cerr<<"ServerSocket: Failed to connect\n";
system("pause");
WSACleanup();
exit(14);
}
else
printf("Server: bind() is OK.\n");
nBytesSent = sendto(SendSocket, cBuffer, nBufSize, 0,
(SOCKADDR *) &targetAddress,
sizeof(SOCKADDR_IN));
printf("Everything is ok\n");
system("PAUSE");
closesocket(ListenSocket);
closesocket(SendSocket);
return EXIT_SUCCESS;
}
编辑:也许我不太清楚。我使用此代码所做的是将一些数据发送到远程 PC。但需要的是 UDP 段应该看起来来自特定端口。如何才能做到这一点?我在这里做错了吗?现在回想起来,我想这确实是错误的。SendSocket 和 ListenSocket 没有任何连接,对吗?那么,如何使 UDP 段看起来来自特定的 UDP 端口?谢谢!