iphone - 对 PHP 服务器的 HTTP POST 请求，其中注册详细信息加密为 HTTP 参数

Question

如何使用加密为 HTTP 参数的注册详细信息将 HTTP POST 请求发布到 PHP 服务器。您可以根据我的要求向我发布示例代码吗？

Answer 1

你可以使用ASIHTTPRequest，你可以这样：

ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:someUrl];
[request setRequestMethod:@"POST"];
[request setPostValue:@"..." forKey:@"user"];
[request setPostValue:@"..." forKey:@"password"];
[request setDelegate:self];
[request startAsyncrhonous];

有请求的委托方法，例如请求完成或失败

- (void)requestFinished:(ASIHTTPRequest *)request 
{
   NSLog(@"Response %d ==> %@", request.responseStatusCode, [request responseString]);
}

- (void)requestFailed:(ASIHTTPRequest *)request 
{
   NSLog(@"Response %d ==> %@", request.responseStatusCode, [request responseString]);
}

您可以随时下载ASIHTTPRequest，也可以访问文档以获取更多帮助。

希望这可以帮助！

Answer 2

NSURL *url = [NSURL URLWithString:@"http://xyz"];

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
                                                       cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:30.0];

NSString *req;


    req = [NSString stringWithFormat:@"Name=%@&Password=%@",userName,pass];// userName and pass are string

[request setHTTPMethod:@"POST"];
[request setHTTPBody: [req dataUsingEncoding:NSISOLatin1StringEncoding]];
NSURLConnection *connection = [[NSURLConnection alloc]initWithRequest:request delegate:self];
[connection start];

下面是一个代表，它将带来数据

-(void)connection:(NSURLConnection*)connection didReceiveData:(NSData *)data
{
NSError *erro;
NSDictionary *jsonData = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&erro];

NSLog(@"your data in dictionary is = %@",jsonData);

}

希望对你有帮助 ！！！