xml - How to access an exact XML node and not the value of it in an XSL stylesheet

Question

Ok,

So in my XML file I have an image node:

<img alt="Green arrow" src="green-arrow-up-icone-5011-48.png"/>

Now I want to display this in my webpage using XSL:

If I use <xsl:value-of select = "//img"/>

(there is only one image), I don't get anything because the "value of" img is nothing as it has no nodes in it. How do I make XSL just take that node as it is and just display it on the webpage?

Answer 1

<xsl:copy-of select="expression"/> 

http://www.w3schools.com/xsl/el_copy-of.asp

Answer 2

分别有xsl:copy-of例如。<xsl:copy-of select="img"/><xsl:template match="img"><xsl:copy-of select="."/></xsl:template>