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为什么无论您是否输入验证码，我的联系页面都不会通过电子邮件发送表单中的详细信息。如果您以错误的方式结束验证码，则会显示错误消息但电子邮件仍会发送？我已经坚持了好几天了。

PHP 语法检查器说这段代码有错误：

<?php

if(isset($_POST['email'])) {

    // EDIT THE 2 LINES BELOW AS REQUIRED
    $email_to = "myemail@hotmail.co.uk";
    $email_subject = "Your email subject line";


    function died($error) {
        // your error code can go here
        echo "We are very sorry, but there were error(s) found with the form you submitted. ";
        echo "These errors appear below.<br /><br />";
        echo $error."<br /><br />";
        echo "Please go back and fix these errors.<br /><br />";
        die();
    }

    // validation expected data exists
    if(!isset($_POST['name']) ||
        !isset($_POST['email']) ||
        !isset($_POST['phone']) ||
        !isset($_POST['msg'])) {
        died('We are sorry, but there appears to be a problem with the form you submitted.');      
    }

    $name = $_POST['name']; // required
    $email = $_POST['email']; // required
    $phone = $_POST['phone']; // not required
    $msg = $_POST['msg']; // required

    $error_message = "";
    $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
  if(!preg_match($email_exp,$email)) {
    $error_message .= 'The Email Address you entered does not appear to be valid.<br />';
  }
    $string_exp = "/^[A-Za-z .'-]+$/";
  if(!preg_match($string_exp,$name)) {
    $error_message .= 'The Name you entered does not appear to be valid.<br />';
  }
  if(strlen($msg) < 2) {
    $error_message .= 'The Comments you entered do not appear to be valid.<br />';
  }
  if(strlen($error_message) > 0) {
    died($error_message);
  }
    $email_message = "Form details below.\n\n";

    function clean_string($string) {
      $bad = array("content-type","bcc:","to:","cc:","href");
      return str_replace($bad,"",$string);
    }

    $email_message .= "Name: ".clean_string($name)."\n";
    $email_message .= "Email: ".clean_string($email)."\n";
    $email_message .= "Phone: ".clean_string($phone)."\n";
    $email_message .= "Message: ".clean_string($msg)."\n";


// create email headers
$headers = 'From: '.$email."\r\n".
'Reply-To: '.$email."\r\n" .
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers); 
?>

它说最后一行是问题?>

解析错误：语法错误，第 65 行代码中的意外 $end 解析代码错误

4

1 回答 1

4

您错过了}最外层if声明的结尾：

if (isset($_POST['email'])) {

   // Code

} // This is missing

为了将来参考，unexpected $end很可能意味着您在某处缺少 a}或 a 。;

于 2012-05-15T15:09:56.727 回答