2

好的，所以我有以下数据库：

CREATE TABLE IF NOT EXISTS `highscores` (
  `lid` int(11) NOT NULL,
  `username` varchar(15) NOT NULL,
  `score` int(16) NOT NULL,
  PRIMARY KEY  (`lid`,`username`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

盖子是级别ID。

假设我在表中有以下值：

lid, username,score

1,sam,15 
1,joe,12
1,sue,6
1,josh,9
2,sam,8
2,joe,16 
2,sue,4
3,sam,65 
4,josh,87 
4,sue,43
5,sam,12
5,sue,28
5,joe,29
and so on.

我将如何创建一个查询（或者如果需要一组查询）来获得以下信息

sam has 3 high scores
joe has 2 high scores
josh has 1 high score

提前致谢。

4

2 回答 2

2

我还没有测试过，但试试下面的查询

select 
    concat(h.username ," has ", count(h.username)," high scores ")
from
    highscores h inner join
    (select lid, max(score) as maxscore
     from highscores group by lid) t on h.lid = t.lid and h.score = t.maxscore
group by h.username
于 2012-04-19T06:12:37.953 回答
2

根据您的描述，此查询将产生您需要的内容

SELECT username,COUNT(*) as num_highscores FROM (
SELECT lid,username
FROM highscores h1
WHERE score=(
    SELECT MAX(score) 
    FROM highscores h2 
    WHERE h2.lid=h1.lid
)
) AS high_scores
GROUP BY username
ORDER BY num_highscores DESC

尽管我从您的样本数据中得到的结果不同：

  • 山姆 2
  • 乔 2
  • 乔希 1
于 2012-04-19T06:13:50.877 回答