我有一个简单的矩阵，在某些列中有重复值。我需要按名称和周对数据进行分组，并将给定周内每天花费的价格相加。这是示例：
name day week price
John 12 12 200
John 14 12 70
John 25 13 150
John 1 14 10
Ann 13 12 100
Ann 15 12 100
Ann 20 13 50
所需的输出将是：
name week sum
John 12 270
John 13 150
John 14 10
Ann 12 200
Ann 13 50
有什么好的方法吗？我使用了 for 循环，但不确定这是最好的方法：
names= unique(data(:,1)); % getting unique names from data
n=size(names, 1); % number of unique names
m=size(data(:,1),1); % number of total rows
sum=[]; % empty matrix for writing the results
for i = 1:n
temp=[]; % creating temporar matrix
k=1;
for j=1:m
if name(i)==data(j,1) % going through all the rows and getting the rows of
temp(k,:)=data(j,:); % the same name and putting in temporar matrix
k=k+1;
end
end
count=0;
s=1;
for l = 1:size(temp,1)-1 % going through temporar matrix of one name(e.g.John)
if temp(l,3)==temp(l+1,3) % checking if the day of current row is equal to the
count=count+temp(l,4); % date of the next row (the data is sorted by name
else % and date) and then summing the prices 4th column
sum(s, 1:3)=[names(i) temp(l,3) count];
count=0; % if the days are not equal, then writing the answer
s=s+1; % to the output matrix sum
end
end
end