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我尝试将 2 个矩阵相乘。我尝试使用 R 软件：检查此线程：在 R 中乘以两个矩阵

现在我尝试在 Java 中做同样的事情。

我将 Jama 库用于矩阵。

我的幂函数

public Matrix power(Matrix M, double p) {
    EigenvalueDecomposition evd = M.eig();
    Matrix D = evd.getD();
    for (int i = 0; i < D.getColumnDimension(); i++) {
        D.set(i, i, Math.pow(D.get(i, i), p));
    }

    Matrix V = evd.getV();

    return V.times(D.times(V.transpose()));
}


double[][] matDouble1 = {{0.25, 0.25, 0.25, 0.25}};
double[][] matDouble2 = {{0, 0, 1, 0},
                       {0.333, 0, 0.333, 0.333},
                       {1, 0, 0, 0},
                       {0, 1, 0, 0}};
Matrix mat1 = new Matrix(matDouble1);
Matrix mat2 = new Matrix(matDouble2);
mat2 = power(mat2, 10000);
mat1 = mat1.times(mat2.transpose());

什么时候显示 mat1 我得到：

0.25018740608813655 0.2498123125257854  0.2501874060881363  0.24981231252578548

代替

0.5 0 0.5 0

和我一起做

mpower = function(M,p) {
     A = as.matrix(M)

    if (dim(A)[1] != dim(A)[2]) stop("not a square matrix")

    # M^{-1} = the matrix inverse of M
    if (p==-1) return(solve(A))

    # M^0 = I
    if (p==0) return(diag(1,dim(A)[1],dim(A)[2]))

    # M^1 = M
    if (p==1) return(A)

    if (p < -1) stop("only powers >= -1 allowed")
    if (p != as.integer(p)) stop("only integer powers allowed")

    R = A
    for (i in 2:p) {
        R = R %*% A
    }
    return(R)

}

mat1<-matrix(c(0.25,0.25,0.25,0.25),nrow=1)
mat2<-matrix(c(0,0,1,0,0.3,0,0.3,0.3,1,0,0,0,0,1,0,0),nrow=4)
mat1%*%t(mpower(mat2,10000))

我明白了

[1,] 0.4996252    0 0.4996252    0
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1 回答 1

2

刚刚在 MATLAB 中做了这个：

>> a = [0.25, 0.25, 0.25, 0.25]

a =

    0.2500    0.2500    0.2500    0.2500

>> b= [0 0 1 0; .333 0 .333 .333; 1 0 0 0; 0 1 0 0]

b =

         0         0    1.0000         0
    0.3330         0    0.3330    0.3330
    1.0000         0         0         0
         0    1.0000         0         0

>> c = b^10000

c =

    1.0000         0         0         0
    0.4993         0    0.4993         0
         0         0    1.0000         0
    0.4993         0    0.4993         0

>> a*c'

ans =

    0.2500    0.2496    0.2500    0.2496

Java 代码工作正常。然而：

>> a*c

ans =

    0.4996         0    0.4996         0

因此，您的矩阵在 R 代码中被转置，因为您需要byrow = TRUE在您的as.matrix语句中。

澄清：

mat2<-matrix(c(0,0,1,0,0.3,0,0.3,0.3,1,0,0,0,0,1,0,0),nrow=4)

创建矩阵

     0       0.3         1         0
     0         0         0         1
     1       0.3         0         0
     0       0.3         0         0

你要

mat2<-matrix(c(0,0,1,0,0.3,0,0.3,0.3,1,0,0,0,0,1,0,0),nrow=4,byrow=TRUE)

创建矩阵

     0         0         1         0
   0.3         0       0.3       0.3
     1         0         0         0
     0         1         0         0
于 2012-03-27T19:58:19.650 回答