假设我有一个 600x600 的 BitmapData,我想将其缩小到 100x100。
6 回答
这有效:
var scale:Number = 1.0/6.0;
var matrix:Matrix = new Matrix();
matrix.scale(scale, scale);
var smallBMD:BitmapData = new BitmapData(bigBMD.width * scale, bigBMD.height * scale, true, 0x000000);
smallBMD.draw(bigBMD, matrix, null, null, null, true);
var bitmap:Bitmap = new Bitmap(smallBMD, PixelSnapping.NEVER, true);
public function drawScaled(obj:IBitmapDrawable, thumbWidth:Number, thumbHeight:Number):Bitmap {
var m:Matrix = new Matrix();
m.scale(WIDTH / obj.width, HEIGHT / obj.height);
var bmp:BitmapData = new BitmapData(thumbWidth, thumbHeight, false);
bmp.draw(obj, m);
return new Bitmap(bmp);
}
IBitmapDrawable is an interface for DisplayObject and BitmapData.
from: http://www.nightdrops.com/2009/02/quick-reference-drawing-a-scaled-object-in-actionscript/
平滑:
function BitmapScaled(source:IBitmapDrawable, thumbWidth:Number, thumbHeight:Number):BitmapData {
var mat:Matrix = new Matrix();
mat.scale(thumbWidth/source.width, thumbHeight/source.height);
var bmpd_draw:BitmapData = new BitmapData(thumbWidth, thumbHeight, false);
bmpd_draw.draw(source, mat, null, null, null, true);
return bmpd_draw;
}
draw 方法接受IBitmapDrawable,它是 DisplayObject 和 BitmapData 的接口。
无需自己编写代码。我解决这个问题的方法是创建一个所需大小的新 BitmapData 对象,然后使用 bitmap.draw 方法将大的复制到小的。bitmap.draw 方法还接受一个矩阵参数,您可以在复制时使用该参数进行缩放。
使用矩阵缩放的问题在于它不会进行任何抗锯齿或平滑处理 - 如果您确定只会缩小比例,这可能没问题,但更通用的方法是使用 Image 类来调整大小。在 AS3 中,它永远不会被添加到显示列表中,因此只会在“屏幕外”使用。像这样的东西(您的位图数据为“sourceBitmapData”):
var image:Image = new Image();
image.load(new Bitmap(sourceBitmapData, PixelSnapping.NEVER, true));
var scale:uint = 100/600; // this is from your example of 600x600 => 100x100
var scaledWidth:uint = sourceBitmapData.width * scale;
var scaledHeight:uint = sourceBitmapData.height * scale;
image.content.width = scaledWidth;
image.content.height = scaledHeight;
var scaledBitmapData:BitmapData = new BitmapData(scaledWidth, scaledHeight);
scaledBitmapData.draw(image.content);
image = null;
然后,您可以使用“scaledBitmapData”代替“sourceBitmapData”来做任何事情。
这是上面的一个变体,增加了对缩放、拉伸和信箱的支持。它可能不提供剪辑支持。
var newSizeBitmapData:BitmapData = resizeBitmapData(myBitmapData, newWidth, newHeight);
/**
* Resize display object or bitmap data to a new size
**/
public static function resizeBitmapData(bitmapDrawable:IBitmapDrawable, width:Number, height:Number, scaleMode:String="none",
smooth:Boolean = true, transparent:Boolean = true, fillColor:Number = 0x00000000):BitmapData {
var sizedBitmapData:BitmapData;
var matrix:Matrix;
matrix = getSizeByScaleMode(width, height, Object(bitmapDrawable).width, Object(bitmapDrawable).height, scaleMode);
sizedBitmapData = new BitmapData(width, height, transparent, fillColor);
sizedBitmapData.draw(bitmapDrawable, matrix, null, null, null, smooth);
return sizedBitmapData;
}
// Get correct scale. Inspired from code in Apache Flex (license Apache 2.0)
public static function getSizeByScaleMode(maxWidth:int, maxHeight:int,
width:int, height:int,
scaleMode:String="letterbox",
dpi:Number=NaN):Matrix {
var aspectRatio:String = (maxWidth < maxHeight) ? "portrait" : "landscape";
var orientation:String = aspectRatio;
var matrix:Matrix = new Matrix();
var scaleX:Number = 1;
var scaleY:Number = 1;
switch(scaleMode) {
case "zoom":
scaleX = Math.max( maxWidth / width, maxHeight / height);
scaleY = scaleX;
break;
case "letterbox":
scaleX = Math.min( maxWidth / width, maxHeight / height);
scaleY = scaleX;
break;
case "stretch":
scaleX = maxWidth / width;
scaleY = maxHeight / height;
break;
}
if (scaleX != 1 || scaleY != 0) {
width *= scaleX;
height *= scaleY;
matrix.scale(scaleX, scaleY);
}
matrix.translate(-width / 2, -height / 2);
matrix.translate(maxWidth / 2, maxHeight / 2);
return matrix;
}