2

我有一个这样的示例 XML:

<rss version="2.0"> 
<channel>
     <title></title>
     <link></link>
     <description></description>
<item>
   <title></title>
   <link></link>
   <description></description>
   <pubDate></pubDate>
   <guid></guid>
</item>

依此类推……我的 obj-c 语法如下所示:

NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

DDXMLDocument *ddDoc = [[DDXMLDocument alloc] initWithData:data options:0 error:&error];

NSArray *xmlItems = [ddDoc nodesForXPath:@"//item" error:&error]; // where ddDoc is your DDXMLDocument
NSMutableArray *returnArray = [[NSMutableArray alloc] initWithCapacity:[xmlItems count]];

for(DDXMLElement* itemElement in xmlItems)
{
    ActiveActivity *activity = [[ActiveActivity alloc] init];

    NSString *itemValueAsString = [[itemElement attributeForName:@"link"]stringValue];


    [returnArray addObject:activity];
}

它没有返回任何价值,谁能告诉我为什么?

4

3 回答 3

4

问题出在这一行:

 NSString *itemValueAsString = [[itemElement attributeForName:@"link"]stringValue];

link不是一个属性,而是一个元素。所以试试这个:

 NSString *itemValueAsString = [[[itemElement elementsForName:@"link"] lastObject] stringValue];
于 2012-02-14T09:27:32.337 回答
0

对于 Swift 3,

let object: DDXMLElement = element.elements(forName: "objectKey").first!
yourModelClass.stringVariable = object.stringValue!
于 2017-12-30T19:37:06.223 回答
-1
NSArray *xmlItems = [[ddDoc rootElement] elementsForName:@"item"];
于 2012-02-14T08:59:57.057 回答