73

编码:

function updateDashboardData() {
    $.getJSON("includes/system/ajaxDataInterface.php", {recordcount:1}, function(data) {
        $('.stationContainer').each(function(data) {
            var bsID = $(this).attr("id");
            var bsStatus = $(this).children('.stationStatus');
            alert(data[bsID][0].time);
            bsStatus.find('.bs_maxHandsets').text(data[bsID][0].maxHandsets);
            bsStatus.find('.bs_time').text(data[bsID][0].time);
        });
    });
}

对象数据:

{
    "A5A50000": [{
        "bsid": "A5A50000",
        "chanCount": 17,
        "time": "2009-05-27 16:36:45",
        "avgInterference": 1.711765,
        "maxInterference": 4.97,
        "avgHandsets": 205.1176,
        "maxHandsets": 315,
        "avgCalls": 6.4118,
        "maxCalls": 13,
        "avgCBA": 3868.98059,
        "maxCBA": 7463,
        "sumSuccessCBA": 197318,
        "sumTimeoutHandoff": 133,
        "sumAttemptHandoff": 1028,
        "sumDeniedHandoff": 216,
        "sumConfirmHandoff": 679,
        "sumHandoffNetwork": 61873,
        "sumJoinNetwork": 96888,
        "sumLeaveNetwork": 93754,
        "sumRcvdKeepalive": 98773,
        "sumTimeoutKeepalive": 19748,
        "sumAttemptUplink": 93689,
        "sumBlockedUplink": 62453
    }]
}

问题:

alert(data.A5A50000[0].time);正确显示“2009-05-27 16:36:45”。

alert(bsID);正确显示“A5A50000”。

alert(data.bsID[0].time);报告“data.bsID 未定义”。

alert(data[bsID][0].time);报告“数据 [bsID] 未定义”。

我有点不清楚何时评估/不评估变量。也许我忽略了一些愚蠢的事情,但我无法在这里找出我的问题。

4

3 回答 3

178

您可以通过点表示法或括号表示法访问对象属性。

var x = {'test': 'hi'};
alert(x.test); // alerts hi
alert(x['test']); // alerts hi

当你有一个动态值时,你必须使用后者:

var property = 'test';
alert(x.property); // looks for x.property, undefined if it doesn't exist
alert(x[property]); // looks for x['test'], alerts hi

所以你真正想要的是:

alert(data[bsID][0].time);

编辑

不知道你做错了什么,但这在 Firebug 的控制台上对我有用:

var data = {"A5A50000":[{"bsid":"A5A50000","chanCount":17,"time":"2009-05-27 16:36:45","avgInterference":1.711765,"maxInterference":4.97,"avgHandsets":205.1176,"maxHandsets":315,"avgCalls":6.4118,"maxCalls":13,"avgCBA":3868.98059,"maxCBA":7463,"sumSuccessCBA":197318,"sumTimeoutHandoff":133,"sumAttemptHandoff":1028,"sumDeniedHandoff":216,"sumConfirmHandoff":679,"sumHandoffNetwork":61873,"sumJoinNetwork":96888,"sumLeaveNetwork":93754,"sumRcvdKeepalive":98773,"sumTimeoutKeepalive":19748,"sumAttemptUplink":93689,"sumBlockedUplink":62453}]};
var bsID = 'A5A50000';
alert(data[bsID][0].time);
于 2009-05-28T18:55:05.910 回答
4

在 Javascript 中,您可以使用对象或数组样式的表示法来查找属性。以下是等价的:

data.A5A50000
data['A5A50000']

使用第二种语法,您可以使用变量代替对象字符串:

data[bsID][0]
于 2009-05-28T18:56:26.423 回答
0

我在嵌套的 JSON API 响应中遇到了同样的问题:

[
    {
        "bj_code": "2019",
        "BJ_PERIODE": [
            {
                "nummer": 1
            },
            {
                "nummer": 2
            }
        ]
    }
]   

我可以评价:

pm.expect(pm.response.json()[0].BJ_PERIODE[1].nummer).to.eql(2);

但是使用BJ_PERIODEnummer通过变量不起作用。使用括号方法编写它确实有效,即使在这个嵌套的 JSON 中,如下所示:

const periode = "BJ_PERIODE";
const nr = "nummer"; 
pm.expect(pm.response.json()[0][periode][1][nr]).to.eql(2);
于 2022-02-08T10:45:21.923 回答