iphone - 如何使用滚动动作从子视图控制器中获取父视图控制器？

Question

我有两个 UIViewController 命名为ViewControllerA and ViewControllerB. ViewControllerA 是父类，ViewControllerB 是子类，它是[self.navigationController pushViewController:viewControllerB animated:YES];从 ViewControllerA 类中查看的。在 ViewControllerB 类中，我隐藏了 NavigationBar。在按钮操作中，我编码为来自 ViewControllerB 的 ViewControllerA [self.navigationController popViewControllerAnimated:YES];。现在，我想使用交换操作（滚动到上一个屏幕）而不是使用 UIButton 从 ViewControllerB 来 ViewControllerA。我怎样才能做到这一点？谁能给我任何建议或想法？提前致谢。

Answer 1

您可以尝试UISwipeGestureRecognizer在您的子视图上使用执行[self.navigationController popViewControllerAnimated:YES];.

Answer 2

在子控制器中使用它

- (void)viewDidLoad 
{    
    UISwipeGestureRecognizer  *recognizer = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(handleSwipeFrom:)];
    [recognizer setDirection:(UISwipeGestureRecognizerDirectionRight | UISwipeGestureRecognizerDirectionDown | UISwipeGestureRecognizerDirectionLeft | UISwipeGestureRecognizerDirectionUp)];
    [[self view] addGestureRecognizer:recognizer];
    [recognizer release]; 
    [super viewDidLoad];
}

-(void)handleSwipeFrom:(UISwipeGestureRecognizer *)recognizer
 {
    [self.navigationController popViewControllerAnimated:YES];
    NSLog(@"Swipe received.");
 }

根据需要使用方向..

快乐的编码...