如何在 iPhone 上进行 Base64 编码？
我发现了一些看起来很有希望的例子，但永远无法让它们中的任何一个在电话上工作。
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82660 次
9 回答
61
你可以在这里看到一个例子。
这适用于 iOS7+。
我在这里复制代码，以防万一：
// Create NSData object
NSData *nsdata = [@"iOS Developer Tips encoded in Base64"
dataUsingEncoding:NSUTF8StringEncoding];
// Get NSString from NSData object in Base64
NSString *base64Encoded = [nsdata base64EncodedStringWithOptions:0];
// Print the Base64 encoded string
NSLog(@"Encoded: %@", base64Encoded);
// Let's go the other way...
// NSData from the Base64 encoded str
NSData *nsdataFromBase64String = [[NSData alloc]
initWithBase64EncodedString:base64Encoded options:0];
// Decoded NSString from the NSData
NSString *base64Decoded = [[NSString alloc]
initWithData:nsdataFromBase64String encoding:NSUTF8StringEncoding];
NSLog(@"Decoded: %@", base64Decoded);
于 2014-06-28T15:56:18.207 回答
10
我也很难找到我能理解的 iPhone 工作代码。
我终于写了这个。
-(NSString *)Base64Encode:(NSData *)data;
-(NSString *)Base64Encode:(NSData *)data{
//Point to start of the data and set buffer sizes
int inLength = [data length];
int outLength = ((((inLength * 4)/3)/4)*4) + (((inLength * 4)/3)%4 ? 4 : 0);
const char *inputBuffer = [data bytes];
char *outputBuffer = malloc(outLength+1);
outputBuffer[outLength] = 0;
//64 digit code
static char Encode[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
//Start the count
int cycle = 0;
int inpos = 0;
int outpos = 0;
char temp;
//Pad the last to bytes, the outbuffer must always be a multiple of 4.
outputBuffer[outLength-1] = '=';
outputBuffer[outLength-2] = '=';
/* http://en.wikipedia.org/wiki/Base64
Text content M a n
ASCII 77 97 110
8 Bit pattern 01001101 01100001 01101110
6 Bit pattern 010011 010110 000101 101110
Index 19 22 5 46
Base64-encoded T W F u
*/
while (inpos < inLength){
switch (cycle) {
case 0:
outputBuffer[outpos++] = Encode[(inputBuffer[inpos] & 0xFC) >> 2];
cycle = 1;
break;
case 1:
temp = (inputBuffer[inpos++] & 0x03) << 4;
outputBuffer[outpos] = Encode[temp];
cycle = 2;
break;
case 2:
outputBuffer[outpos++] = Encode[temp|(inputBuffer[inpos]&0xF0) >> 4];
temp = (inputBuffer[inpos++] & 0x0F) << 2;
outputBuffer[outpos] = Encode[temp];
cycle = 3;
break;
case 3:
outputBuffer[outpos++] = Encode[temp|(inputBuffer[inpos]&0xC0) >> 6];
cycle = 4;
break;
case 4:
outputBuffer[outpos++] = Encode[inputBuffer[inpos++] & 0x3f];
cycle = 0;
break;
default:
cycle = 0;
break;
}
}
NSString *pictemp = [NSString stringWithUTF8String:outputBuffer];
free(outputBuffer);
return pictemp;
}
于 2010-08-05T04:01:55.003 回答
10
使用此库对 Base64 进行编码。
它还支持ARC
于 2013-01-07T10:45:12.820 回答
4
试试这个......这对我来说非常有效。创建一个类别 Base64.h 和 Base 64.m，导入到您要使用的任何类并使用单行调用它以进行 base 64 编码。
//
// Base64.h
// CryptTest
// Created by SURAJ K THOMAS on 02/05/2013.
#import <Foundation/Foundation.h>
@interface Base64 : NSObject {
}
+ (void) initialize;
+ (NSString*) encode:(const uint8_t*) input length:(NSInteger) length;
+ (NSString*) encode:(NSData*) rawBytes;
+ (NSData*) decode:(const char*) string length:(NSInteger) inputLength;
+ (NSData*) decode:(NSString*) string;
@end
#import "Base64.h"
@implementation Base64
#define ArrayLength(x) (sizeof(x)/sizeof(*(x)))
static char encodingTable[] =
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
static char decodingTable[128];
+ (void) initialize {
if (self == [Base64 class]) {
memset(decodingTable, 0, ArrayLength(decodingTable));
for (NSInteger i = 0; i < ArrayLength(encodingTable); i++) {
decodingTable[encodingTable[i]] = i;
}
}
}
+ (NSString*) encode:(const uint8_t*) input length:(NSInteger) length {
NSMutableData* data = [NSMutableData dataWithLength:((length + 2) / 3) * 4];
uint8_t* output = (uint8_t*)data.mutableBytes;
for (NSInteger i = 0; i < length; i += 3) {
NSInteger value = 0;
for (NSInteger j = i; j < (i + 3); j++) {
value <<= 8;
if (j < length) {
value |= (0xFF & input[j]);
}
}
NSInteger index = (i / 3) * 4;
output[index + 0] = encodingTable[(value >> 18) & 0x3F];
output[index + 1] = encodingTable[(value >> 12) & 0x3F];
output[index + 2] = (i + 1) < length ? encodingTable[(value >> 6) & 0x3F] : '=';
output[index + 3] = (i + 2) < length ? encodingTable[(value >> 0) & 0x3F] : '=';
}
return [[NSString alloc] initWithData:data
encoding:NSASCIIStringEncoding];
}
+ (NSString*) encode:(NSData*) rawBytes {
return [self encode:(const uint8_t*) rawBytes.bytes length:rawBytes.length];
}
+ (NSData*) decode:(const char*) string length:(NSInteger) inputLength {
if ((string == NULL) || (inputLength % 4 != 0)) {
return nil;
}
while (inputLength > 0 && string[inputLength - 1] == '=') {
inputLength--;
}
NSInteger outputLength = inputLength * 3 / 4;
NSMutableData* data = [NSMutableData dataWithLength:outputLength];
uint8_t* output = data.mutableBytes;
NSInteger inputPoint = 0;
NSInteger outputPoint = 0;
while (inputPoint < inputLength) {
char i0 = string[inputPoint++];
char i1 = string[inputPoint++];
char i2 = inputPoint < inputLength ? string[inputPoint++] : 'A'; /* 'A' will
decode to \0 */
char i3 = inputPoint < inputLength ? string[inputPoint++] : 'A';
output[outputPoint++] = (decodingTable[i0] << 2) | (decodingTable[i1] >> 4);
if (outputPoint < outputLength) {
output[outputPoint++] = ((decodingTable[i1] & 0xf) << 4) |
(decodingTable[i2] >> 2);
}
if (outputPoint < outputLength) {
output[outputPoint++] = ((decodingTable[i2] & 0x3) << 6) |
decodingTable[i3];
}
}
return data;
}
+ (NSData*) decode:(NSString*) string {
return [self decode:[string cStringUsingEncoding:NSASCIIStringEncoding]
length:string.length];
}
@结尾
now import the above category to any class and convert the string like below
NSString *authString = [[NSString stringWithFormat:@"OD0EK819OJFIFT6OJZZXT09Y1YUT1EJ2"]
stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSData *inputData = [authString dataUsingEncoding:NSUTF8StringEncoding];
NSString *finalAuth =[Base64 encode:inputData];
NSLog(@"Encoded string =%@", finalAuth);
于 2013-05-02T06:27:32.003 回答
4
从GitHub下载以下两个文件
Base64.h
Base64.m
将这些文件添加到您的项目中
在所需文件中导入头文件
#import "Base64.h"
并使用 as 进行编码
NSString *plainText = @"Your String";
NSString *base64String = [plainText base64EncodedStringWithWrapWidth:0];
您也可以将其解码为
NSString *plainText = [base64String base64DecodedString];
于 2013-09-23T10:47:32.140 回答
3
NSString *plainString = @"foo";
编码
NSData *plainData = [plainString dataUsingEncoding:NSUTF8StringEncoding];
NSString *base64String = [plainData base64EncodedStringWithOptions:0];
NSLog(@"%@", base64String); // Zm9v
解码
NSData *decodedData = [[NSData alloc] initWithBase64EncodedString:base64String options:0];
NSString *decodedString = [[NSString alloc] initWithData:decodedData encoding:NSUTF8StringEncoding];
NSLog(@"%@", decodedString); // foo
于 2016-08-31T20:29:50.793 回答
2
似乎从 iOS 7 开始，您不再需要任何库以使用 Base64 进行编码。NSData上的以下方法可用于 Base64 编码：
- base64EncodedDataWithOptions: – base64EncodedStringWithOptions:
于 2014-02-04T20:31:50.580 回答
0
NSData类别中的方法
- (NSString*)encodeBase64 {
static char* alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";
unsigned int length = self.length;
unsigned const char* rawData = self.bytes;
//empty data = empty output
if (length == 0) {
return @"";
}
unsigned int outputLength = (((length + 2) / 3) * 4);
//let's allocate buffer for the output
char* rawOutput = malloc(outputLength + 1);
//with each step we get 3 bytes from the input and write 4 bytes to the output
for (unsigned int i = 0, outputIndex = 0; i < length; i += 3, outputIndex += 4) {
BOOL triple = NO;
BOOL quad = NO;
//get 3 bytes (or only 1 or 2 when we have reached the end of input)
unsigned int value = rawData[i];
value <<= 8;
if (i + 1 < length) {
value |= rawData[i + 1];
triple = YES;
}
value <<= 8;
if (i + 2 < length) {
value |= rawData[i + 2];
quad = YES;
}
//3 * 8 bits written as 4 * 6 bits (indexing the 64 chars of the alphabet)
//write = if end of input reached
rawOutput[outputIndex + 3] = (quad) ? alphabet[value & 0x3F] : '=';
value >>= 6;
rawOutput[outputIndex + 2] = (triple) ? alphabet[value & 0x3F] : '=';
value >>= 6;
rawOutput[outputIndex + 1] = alphabet[value & 0x3F];
value >>= 6;
rawOutput[outputIndex] = alphabet[value & 0x3F];
}
rawOutput[outputLength] = 0;
NSString* output = [NSString stringWithCString:rawOutput encoding:NSASCIIStringEncoding];
free(rawOutput);
return output;
}
于 2013-01-07T10:55:33.373 回答
0
我做了自己的实现，其中已删除循环内的所有检查。因此，在大量数据上，它的工作速度更快。您可以将其作为自己解决方案的基础。
static char *alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
+ (NSString *)encodeString:(NSString *)data
{
const char *input = [data cStringUsingEncoding:NSUTF8StringEncoding];
unsigned long inputLength = [data length];
unsigned long modulo = inputLength % 3;
unsigned long outputLength = (inputLength / 3) * 4 + (modulo ? 4 : 0);
unsigned long j = 0;
// Do not forget about trailing zero
unsigned char *output = malloc(outputLength + 1);
output[outputLength] = 0;
// Here are no checks inside the loop, so it works much faster than other implementations
for (unsigned long i = 0; i < inputLength; i += 3) {
output[j++] = alphabet[ (input[i] & 0xFC) >> 2 ];
output[j++] = alphabet[ ((input[i] & 0x03) << 4) | ((input[i + 1] & 0xF0) >> 4) ];
output[j++] = alphabet[ ((input[i + 1] & 0x0F)) << 2 | ((input[i + 2] & 0xC0) >> 6) ];
output[j++] = alphabet[ (input[i + 2] & 0x3F) ];
}
// Padding in the end of encoded string directly depends of modulo
if (modulo > 0) {
output[outputLength - 1] = '=';
if (modulo == 1)
output[outputLength - 2] = '=';
}
NSString *s = [NSString stringWithUTF8String:(const char *)output];
free(output);
return s;
}
于 2013-04-18T09:28:20.967 回答