91

我正在处理推送通知。我编写了以下代码来获取设备令牌。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {    
    // Override point for customization after application launch.

    // Add the view controller's view to the window and display.
    [self.window addSubview:viewController.view];
    [self.window makeKeyAndVisible];

    NSLog(@"Registering for push notifications...");    
    [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
     (UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];

    return YES;
}

- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken { 
    NSString *str = [NSString stringWithFormat:@"Device Token=%@",deviceToken];
    NSLog(@"This is device token%@", deviceToken);
}

- (void)application:(UIApplication *)app didFailToRegisterForRemoteNotificationsWithError:(NSError *)err { 
    NSString *str = [NSString stringWithFormat: @"Error: %@", err];
    NSLog(@"Error %@",err);    
}

我能够在设备上成功运行应用程序，但无法在控制台上获取设备 ID。

我对认证和配置文件没有任何问题。

4

15 回答 15

165

注意：以下解决方案不再适用于 iOS 13+ 设备 -它会返回垃圾数据。

请改用以下代码：

+ (NSString *)hexadecimalStringFromData:(NSData *)data
{
  NSUInteger dataLength = data.length;
  if (dataLength == 0) {
    return nil;
  }

  const unsigned char *dataBuffer = (const unsigned char *)data.bytes;
  NSMutableString *hexString  = [NSMutableString stringWithCapacity:(dataLength * 2)];
  for (int i = 0; i < dataLength; ++i) {
    [hexString appendFormat:@"%02x", dataBuffer[i]];
  }
  return [hexString copy];
}

在 iOS 13 之前有效的解决方案：

Objective-C

- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken 
{
    NSString *token = [[deviceToken description] stringByTrimmingCharactersInSet: [NSCharacterSet characterSetWithCharactersInString:@"<>"]];
    token = [token stringByReplacingOccurrencesOfString:@" " withString:@""];
    NSLog(@"this will return '32 bytes' in iOS 13+ rather than the token", token);
}

斯威夫特 3.0

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data)
{
    let tokenString = deviceToken.reduce("", {$0 + String(format: "%02X", $1)})
    print("this will return '32 bytes' in iOS 13+ rather than the token \(tokenString)")
}
于 2012-01-10T05:32:25.477 回答
13

要获得令牌设备，您可以通过一些步骤来完成：

1）为开发者认证和分发认证启用APNS（Apple Push Notification Service），然后重新下载这两个文件。

2) 重新下载 Developer Provisioning 和 Distribute Provisioning 文件。

3）在Xcode界面：设置PROJECT和TARGETS的配置有两个文件配置已下载。

4）最后，需要在AppDelegate文件中添加如下代码来获取Token Device（注意：在真机上运行app）。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {    
     [self.window addSubview:viewController.view];
     [self.window makeKeyAndVisible];

     NSLog(@"Registering for push notifications...");    
     [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
 (UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];
     return YES;
}

- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken { 
     NSString *str = [NSString stringWithFormat:@"Device Token=%@",deviceToken];
     NSLog(@"%@", str);
}

- (void)application:(UIApplication *)app didFailToRegisterForRemoteNotificationsWithError:(NSError *)err { 
     NSString *str = [NSString stringWithFormat: @"Error: %@", err];
     NSLog(@"%@",str);
}
于 2013-05-27T03:56:30.357 回答
12

使用description这些答案中的许多建议是错误的方法- 即使你让它工作，它也会在 iOS 13+ 中中断。

相反，您应该确保使用实际的二进制数据，而不仅仅是对其的描述。Andrey Gagan 很好地解决了 Objective C 解决方案，但幸运的是它在 swift 中要简单得多：

Swift 4.2适用于iOS 13+

// credit to NSHipster (see link above)
// format specifier produces a zero-padded, 2-digit hexadecimal representation
let deviceTokenString = deviceToken.map { String(format: "%02x", $0) }.joined()
于 2019-09-17T13:37:22.730 回答
8

适用于 iOS 13+ 的 Objective C，由 Wasif Saood 的回答提供

将以下代码复制并粘贴到 AppDelegate.m 以打印设备 APN 令牌。

- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken
{
  NSUInteger dataLength = deviceToken.length;
  if (dataLength == 0) {
    return;
  }
  const unsigned char *dataBuffer = (const unsigned char *)deviceToken.bytes;
  NSMutableString *hexString  = [NSMutableString stringWithCapacity:(dataLength * 2)];
  for (int i = 0; i < dataLength; ++i) {
    [hexString appendFormat:@"%02x", dataBuffer[i]];
  }
  NSLog(@"APN token:%@", hexString);
}
于 2019-09-28T19:59:18.643 回答
5

以下代码用于检索设备令牌。

    // Prepare the Device Token for Registration (remove spaces and < >)
    NSString *devToken = [[[[deviceToken description] 
                            stringByReplacingOccurrencesOfString:@"<"withString:@""] 
                           stringByReplacingOccurrencesOfString:@">" withString:@""] 
                          stringByReplacingOccurrencesOfString: @" " withString: @""];


    NSString *str = [NSString 
                     stringWithFormat:@"Device Token=%@",devToken];
    UIAlertView *alertCtr = [[[UIAlertView alloc] initWithTitle:@"Token is " message:devToken delegate:self cancelButtonTitle:nil otherButtonTitles: nil] autorelease];
    [alertCtr show];
    NSLog(@"device token - %@",str);
于 2012-01-10T04:58:32.873 回答
5

Wasif 答案的 Swift 版本：

斯威夫特 2.x

var token = deviceToken.description.stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "<>"))
token = token.stringByReplacingOccurrencesOfString(" ", withString: "")
print("Token is \(token)")

Swift 3 更新

let deviceTokenString = deviceToken.map { String(format: "%02.2hhx", $0) }.joined()
于 2016-08-30T12:33:31.317 回答
5

从 iOS 13 开始，Apple 更改了[deviceToken description]输出。现在是这样的，这{length=32,bytes=0x0b8823aec3460e1724e795cba45d22e8...af8c09f971d0dabc}对于设备令牌是不正确的。

我建议使用此代码段来解决问题：

+ (NSString *)stringFromDeviceToken:(NSData *)deviceToken {
    NSUInteger length = deviceToken.length;
    if (length == 0) {
        return nil;
    }
    const unsigned char *buffer = deviceToken.bytes;
    NSMutableString *hexString  = [NSMutableString stringWithCapacity:(length * 2)];
    for (int i = 0; i < length; ++i) {
        [hexString appendFormat:@"%02x", buffer[i]];
    }
    return [hexString copy];
}

它适用于 iOS13 及更低版本。

于 2019-09-10T07:21:19.693 回答
4

如果您仍然没有获得设备令牌，请尝试输入以下代码，以便为您的设备注册推送通知。

它也适用于 ios8 或更高版本。

#if __IPHONE_OS_VERSION_MAX_ALLOWED >= 80000

    if ([UIApplication respondsToSelector:@selector(registerUserNotificationSettings:)]) {
        UIUserNotificationSettings *settings = [UIUserNotificationSettings settingsForTypes:UIUserNotificationTypeBadge|UIUserNotificationTypeAlert|UIUserNotificationTypeSound
                                                                                 categories:nil];
        [[UIApplication sharedApplication] registerUserNotificationSettings:settings];
        [[UIApplication sharedApplication] registerForRemoteNotifications];
    } else {
        [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
         UIRemoteNotificationTypeBadge |
         UIRemoteNotificationTypeAlert |
         UIRemoteNotificationTypeSound];

    }
#else
    [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
     UIRemoteNotificationTypeBadge |
     UIRemoteNotificationTypeAlert |
     UIRemoteNotificationTypeSound];

#endif
于 2015-04-10T09:50:57.937 回答
1

在您的 AppDelegate 中，在didRegisterForRemoteNotificationsWithDeviceToken方法中：

为 Swift 更新：

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
    print("\(deviceToken.reduce("") { $0 + String(format: "%02.2hhx", arguments: [$1]) })")
}
于 2014-11-26T05:09:19.410 回答
1

在 Swift 3 中获取设备令牌

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {

    let deviceTokenString = deviceToken.reduce("", {$0 + String(format: "%02X", $1)})

    print("Device token: \(deviceTokenString)")

}
于 2016-11-29T22:09:22.220 回答
0

Swift 4 这对我有用：

第 1 步进入TARGETS单击添加功能并选择推送通知

第 2 步在 AppDelegate.swift 中添加以下代码：

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
     
        UNUserNotificationCenter.current().requestAuthorization(options: [.alert,.sound]) { (didAllow, error) in
            
        }
        UIApplication.shared.registerForRemoteNotifications()
        
        return true
    }
    
    //Get device token
    func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data)
    {
        let tokenString = deviceToken.reduce("", {$0 + String(format: "%02X", $1)})
        
        print("The token: \(tokenString)")
    }
于 2020-08-18T00:22:37.000 回答
0

对于 Objective-C

iOS 13 推送令牌有一些变化

- (void)application:(UIApplication *)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken {
NSString *token = @"";
        if (@available(iOS 13, *)) {
        NSUInteger length = deviceToken.length;
        if (length == 0) {
            token = @"";
        }
        const unsigned char *buffer = deviceToken.bytes;
        NSMutableString *actualToken  = [NSMutableString stringWithCapacity:(length * 2)];
        for (int i = 0; i < length; ++i) {
            [actualToken appendFormat:@"%02x", buffer[i]];
        }
        token = [actualToken copy];
        } else {
            token = [[deviceToken description] stringByTrimmingCharactersInSet: [NSCharacterSet characterSetWithCharactersInString:@"<>"]];
                token = [token stringByReplacingOccurrencesOfString:@" " withString:@""];
        }
        NSLog(@"My token is: %@", token);
}
于 2021-03-31T09:45:49.037 回答
-1

在构建设置集代码签名配置配置文件中，如果您有 APN 启用证书，那么您肯定会获得令牌 ID。并删除

配置文件：自动

并设置为

配置文件：您的配置文件证书。

于 2015-10-31T14:04:37.150 回答
-2 
func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {

    let tokenParts = deviceToken.map { data -> String in
        return String(format: "%02.2hhx", data)
        }
    let token = tokenParts.joined()

    print("Token\(token)")
}
于 2020-02-03T10:15:16.670 回答
-4

为了获取设备令牌，请使用以下代码，但您只能使用物理设备获取设备令牌。如果您必须发送设备令牌，那么在使用模拟器时，您可以设置以下条件。

  if(!(TARGET_IPHONE_SIMULATOR))
    {
        [infoDict setValue:[[NSUserDefaults standardUserDefaults] valueForKey:@"DeviceToken"] forKey:@"device_id"];
    }
    else
    {
        [infoDict setValue:@"e79c2b66222a956ce04625b22e3cad3a63e91f34b1a21213a458fadb2b459385" forKey:@"device_id"];
    }



- (void)application:(UIApplication*)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData*)deviceToken
{
    NSLog(@"My token is: %@", deviceToken);
    NSString * deviceTokenString = [[[[deviceToken description] stringByReplacingOccurrencesOfString: @"<" withString: @""] stringByReplacingOccurrencesOfString: @">" withString: @""]   stringByReplacingOccurrencesOfString: @" " withString: @""];
    NSLog(@"the generated device token string is : %@",deviceTokenString);
    [[NSUserDefaults standardUserDefaults] setObject:deviceTokenString forKey:@"DeviceToken"];
}
于 2017-12-28T13:29:22.580 回答