0

第二个 while 循环在第二次迭代时在 xstring 第 1441 行抛出异常，它不应该这样做。这是因为在第一遍：

Testthis->NAME[n] = 'B'
Testthis->NAME[n+1] = 'O'
Testthis->NAME = "BOD MQL"

都是从调试cout语句中验证的。我被这个难住了。

struct Node * ProbableMatch(struct Node * Look_in, int MaxNodes, char Findthis[64]){
system("cls");
int i=0,proba=100,CurrentHigh=100;
size_t pos1=1,n1=0,n2=0,pos2=1;
//char s[64];
struct Node * CurrentHighProb;
struct Node * Testthis;
CurrentHighProb=new(Node);
Testthis=new(Node);
Testthis=Look_in;
//for(i=0;i==MaxNodes;i++)
while(!Testthis || i!=ccounter)
{
    gotoxy(0,0);
    int n=0;
    n1=sizeof(Look_in->NAME);
    n2=sizeof(Findthis);
    string str1;
    char str2[64];
    cout<<Testthis->NAME[n]<<endl<<Testthis->NAME<<endl;
    cout<<Testthis->NAME[n+1]<<endl;

    while(Testthis->NAME[n]!='\0'){  //mannually coverts the strings since I am having hell with the inbuilt functions
        cout<<Testthis->NAME[n];
        str1[n]=Testthis->NAME[n];
        if(Testthis->NAME[n+1]=='\0'){str1[n+1]='\0';}//makes NULL terminated strings
        n++;
    }//end of while

    //strcpy_s(cstr, str1.length());
    //strcpy_s(str1,sizeof(Look_in->NAME),Look_in->NAME);
    //strcpy_s(str2,sizeof(Findthis),Findthis);
    //char * cstr1 = new char[str1.length()+1];
    cout<<str1.compare(pos1,n1,Findthis,0,n2)<<" is the value of the string compare "<<endl;
    proba=str1.compare(pos1,n1,Findthis,0,n2);//compares Findthis to the varibles read from the database from string matches

    //DEBUG STUFF
    cout<<endl<<sizeof(Look_in->NAME)<<" sizeof(Look_in->NAME)"<<Look_in->NAME<<endl;
    cout<<sizeof(Findthis)<<" sizeof(Findthis)"<<Findthis<<endl;
    cout<<sizeof(str1)<<" "<<str1<<" string1   string2 "<<str2<<" "<<sizeof(str2)<<endl;
    //cout<<sizeof(str1)<<" reinterpret_cast< char *>(str1)"<<endl;
    system("PAUSE");
    cout<<"\n Probability of "<<Look_in->NAME<<" matching "<<Findthis<<" is "<<proba<<" ."<<endl;
    //ENDOFDEBUG FOR FUNCTION
    Testthis->prob=proba;
    if(proba==0)
    {
        cout<<"proba equals zero, match found returning "<<Look_in<<endl;
        //delete[] cstr1;
        return Testthis;  // returns the pointer of the varible that best matched the search
    }
    if(proba<CurrentHigh){
        CurrentHigh=proba;
        CurrentHighProb=Testthis;
    }
    i++;
    Testthis=Testthis->next;
}
cout<<"Perfect match not found after "<<i<<" number of searches, returning this highest probable match "<<CurrentHighProb<<" "<<proba<<endl;

system("PAUSE");
//delete[] cstr1;
return CurrentHighProb;
}
4

1 回答 1

1 
string str1;

声明一个零长度std::string。

str1[n]=Testthis->NAME[n];

引用 的（不存在的）第 n 个元素str1。

也许您的意思是创建一个string具有确定长度的：

string str1(n1, ' ');

或者，也许您的意思是在复制期间分配字符串数据：

str1.push_back(Testthis->NAME[n]);

您的代码中还有其他错误，但这可能会产生您描述的异常。

您可以简单地避免所有这些错误。用这个替换内部while循环：

str1 = Testthis->NAME;
于 2012-01-03T19:18:00.120 回答