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我正在创建一个简单的便笺应用程序。JPopupMenu当我点击JTextArea. 因为它是一个便笺所以很明显整个应用程序将是一个textArea

短代码:

    //I've tried my best to follow SSCE

private JTextArea textArea = new JTextArea();
private JPopupMenu popup = new JPopupMenu("Popup Menu");
private JMenuItem hideBar = new JMenuItem("Hide Bar");
private JMenuItem hideTitle = new JMenuItem("Hide Item");

public mySticky(){

add(textArea); //Text Area is using the whole Frame "Sticky Note"
popup.add(hideBar);  //adding MenuItem
popup.add(hideTitle); //adding MenuItem
//addMouseListener(new popupTriggerListener());
textArea.addMouseListener(new popupTriggerListener());

}


private class popupTriggerListener extends MouseAdapter{
    public void MousePressed(MouseEvent e){
        if(e.isPopupTrigger())
            popup.show(textArea,e.getX(),e.getY()); //I've added texArea I'm not sure what to add inside.
    }

    public void MouseReleased(MouseEvent e){
        if(e.isPopupTrigger())
            popup.show(textArea,e.getX(),e.getY()); //I've added texArea I'm not sure what to add inside.
    }

    public void MouseClicked(MouseEvent e){

    }
}
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1 回答 1

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我已尽力关注 SSCE

鉴于代码甚至无法编译,这怎么可能是 SSCCE?尝试再次阅读链接。

我建议您首先阅读 Swing 教程中有关弹出弹出菜单的部分,以获取一个工作示例。

嗯,我在这里遗漏了一些东西

当您覆盖方法时,您缺少@Override应该在方法签名之前的语句。这将防止您输入错误。

于 2011-12-30T22:20:38.463 回答