3

我有数据库“db2”和表“menjava”

在表 menjava 中有“id”、“author”和“date_submitted”字段

  • id - auto_increment
  • 作者 - int(11)
  • date_submitted - 日期时间

我想根据名为“date_submitted”的 DATETIME 字段计算今天日期的所有行和昨天日期的所有行(因此将有两个带有条件的代码),该字段包含每条记录的创建日期和时间。

在文件 result.php 中,显示了这个计数,但它不起作用。在同一个文件(result.php)中,我有一些其他代码来显示来自不同数据库的数据,所以我认为 povezava.php 工作正常。

我的代码:

 <?
    require "povezava.php";
    $q=mysql_query(" SELECT COUNT(*) AS total_number FROM menjava 
WHERE date_submitted >= DATE_SUB(CURRENT_DATE(), INTERVAL 1 DAY)",$link2);
// now you can 
if ( $nt = mysql_fetch_array($q)){
echo $nt["total_number"];
$q=mysql_query($nt) or die(mysql_error());
}

    ?>

我的文件 povezava.php 看起来像这样:

<?
$servername='localhost';

$dbusername='user';
$dbpassword='pass';

$dbname1='db1';
$dbname2='db2';

$link1 = connecttodb($servername,$dbname1,$dbusername,$dbpassword);
$link2 = connecttodb($servername,$dbname2,$dbusername,$dbpassword);

function connecttodb($servername,$dbname,$dbusername,$dbpassword)
{
    $link=mysql_connect ("$servername","$dbusername","$dbpassword",TRUE);
    if(!$link){die("Could not connect to MySQL");}
    mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());
    return $link;
}
    ?>

我得到的错误:

A PHP Error was encountered

Severity: NoticeMessage: Array to string conversionFilename: templates/master.phpLine Number: 231 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Array' at line 1

固定的:

<?
    require "povezava.php";
    $q=mysql_query("SELECT COUNT(*) AS total_number FROM menjava WHERE date_submitted >= DATE_SUB(CURRENT_DATE(), INTERVAL 0 DAY)",$link2);
// working 
if ( $nt = mysql_fetch_array($q)){
echo $nt["total_number"];
}

    ?>

谢谢!

4

2 回答 2

1

尝试 :

$q = 'SELECT COUNT(*) FROM menjava
          WHERE date_submitted >= DATE_SUB(CURRENT_DATE(), INTERVAL 1 DAY)';
$result = mysql_query($q);
$total_rows = mysql_fetch_row($result);
print $total_rows[0] . ' authors have been submitted today and yesterday.'; 
于 2011-12-25T13:35:12.457 回答
0

请尝试以下 SQL 命令:

$sqlToday = "Select COUNT(*) FROM menjava WHERE DATE(date_submitted) = CURRENT_DATE()";

$sqlYesterday = "Select COUNT(*) FROM menjava WHERE DATE(dc_created) = CURDATE() - INTERVAL 1 DAY";
于 2017-07-06T11:54:12.607 回答