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我是 SQL 中的 XQuery 新手，但我了解获取节点和查询值的基础知识。我现在的问题是处理未知深度的层次结构。

关系是Contract -> Project -> Lines；看起来像这样：

<ZEstimateContract xmlns="http://schemas.datacontract.org/2004/07/Zeller.Gp" xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:z="http://schemas.microsoft.com/2003/10/Serialization/" z:Id="i1">
  <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">QGPET0000000218</Name>
  <_projects>
    <ZEstimateProject z:Id="i10">
      <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">Project A</Name>
      <_lines>
        <ZEstimateLine z:Id="i41">
          <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">00008813</Name>
          <_lines>
            <ZEstimateLine z:Id="i43">
              <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">002-2075-4  MAIN COLUMN</Name>
              <_lines />
            </ZEstimateLine>
          </_lines>
        </ZEstimateLine>
        <ZEstimateLine z:Id="i44">
          <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">0.080 Aluminum 2ft x 4ft</Name>
          <_lines />
        </ZEstimateLine>
      </_lines>
      <_projects>
        <ZEstimateProject z:Id="i101">          
          <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">Project A1</Name>
          <_lines>
            <ZEstimateLine z:Id="i132">              
              <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy" />
              <_lines />
            </ZEstimateLine>
          </_lines>
          <_projects />
        </ZEstimateProject>
      </_projects>
    </ZEstimateProject>
    <ZEstimateProject z:Id="i189">
      <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">Project B</Name>
      <_lines>
        <ZEstimateLine z:Id="i205">          
          <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">#8X8SPOOL</Name>
          <_lines />
        </ZEstimateLine>
      </_lines>
      <_projects />
    </ZEstimateProject>
  </_projects>
  <_rebateSources />
</ZEstimateContract>

因此，合同可以有任意数量的项目，可以有任意数量的行和任意数量的子项目。这些行可以有任意数量的子行。

我正在编写一个 SQL 查询来返回结果集中的所有行（编辑：在其他数据中）。这是我到目前为止所拥有的：

-- TEST DATA
DECLARE @QuoteDate DATETIME = '12/12/2011'
DECLARE @QuoteNumber VARCHAR(15) = 'QGPET0000000218'
DECLARE @RevLevel VARCHAR(50) = '0'

;WITH XMLNAMESPACES('http://schemas.datacontract.org/2004/07/Zeller.Gp' AS ZC, 
    'http://schemas.datacontract.org/2004/07/Zynergy' AS ZYN,
    'http://schemas.microsoft.com/2003/10/Serialization/' AS Z)

SELECT CM.Contract, CM.RevisionLevel, CM.CustomerGpId,
    p.value('(./ZYN:Name)[1]', 'varchar(50)') as ProjectName,
    l.value('(./ZYN:Name)[1]', 'varchar(50)') as ItemNumber
FROM dbo.tblContractMaster AS CM
CROSS APPLY CM.FullContract.nodes('/ZC:ZEstimateContract/ZC:_projects/ZC:ZEstimateProject') as Proj(p)
CROSS APPLY Proj.p.nodes('./ZC:_lines/ZC:ZEstimateLine') as Line(l) 
WHERE CM.[Contract] = @QuoteNumber AND CM.RevisionLevel = @RevLevel
-- Order by the default "ID" that gets assigned to the XML element.  
-- This is the same order that the object is in when in a collection in GPET
ORDER BY p.value('(./@Z:Id)[1]', 'varchar(50)'), l.value('(./@Z:Id)[1]', 'varchar(50)')

正如你所看到的，这只会让我获得“1级”，但我需要更深入（想想Inception！......一个项目中的一个项目......你明白了）

有任何想法吗？

编辑添加了部分解决方案。这让我得到了子项目（注意“//”），而不是子行：

CROSS APPLY CM.FullContract.nodes('/ZC:ZEstimateContract//ZC:_projects/ZC:ZEstimateProject') as Proj(p) 
CROSS APPLY Proj.p.nodes('./ZC:_lines/ZC:ZEstimateLine') as Line(l) LEFT OUTER JOIN

编辑：这是一个更好的示例： 

<ZEstimateContract xmlns="http://schemas.datacontract.org/2004/07/Zeller.Gp" xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:z="http://schemas.microsoft.com/2003/10/Serialization/" z:Id="i1">
  <_key xmlns="http://schemas.datacontract.org/2004/07/Zynergy">ZynergyDefault</_key>
  <_dataStoreGuid xmlns="http://schemas.datacontract.org/2004/07/Zynergy">88381fa0-5901-4513-9ccb-b2f576341db1</_dataStoreGuid>
  <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">QGPET0000000218</Name>
  <_projects>
    <ZEstimateProject z:Id="i10">
      <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">Project A</Name>
      <Parent i:nil="true" />
      <_lines>
        <ZEstimateLine z:Id="i41">
          <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">00008813</Name>
          <Description>Epic circular connector w/ 12 inserts.</Description>
          <Parent i:nil="true" />
          <_lines>
            <ZEstimateLine z:Id="i43">
              <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">002-2075-4  MAIN COLUMN</Name>
              <Description>CUSTOM JBOX, PER DWG REV -, PUNCHED, TAPPED, CUT OUTS, PBT4-70003 TEXTURE BLACK INSIDE AND OUTSIDE</Description>
              <Parent z:Id="i44">
                <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">00008813</Name>
                <Description>Epic circular connector w/ 12 inserts.</Description>
                <Parent i:nil="true" />
                <_lines>
                  <ZEstimateLine z:Id="i46">
                    <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">002-2075-4  MAIN COLUMN</Name>
                    <Description>CUSTOM JBOX, PER DWG REV -, PUNCHED, TAPPED, CUT OUTS, PBT4-70003 TEXTURE BLACK INSIDE AND OUTSIDE</Description>
                    <Parent z:Ref="i44" />
                    <_lines />
                  </ZEstimateLine>
                </_lines>
              </Parent>
              <_lines />
            </ZEstimateLine>
          </_lines>
        </ZEstimateLine>
        <ZEstimateLine z:Id="i47">
          <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">AG30</Name>
          <Description>480V 30A CLASS G FUSE</Description>
          <Parent i:nil="true" />
          <_lines />
        </ZEstimateLine>
      </_lines>
      <_projects>
        <ZEstimateProject z:Id="i105">
          <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">Project A1</Name>
          <_lines>
            <ZEstimateLine z:Id="i136">
              <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">0026153</Name>
              <Description>Olflex 810 16awg 7cond</Description>
              <_lines />
            </ZEstimateLine>
          </_lines>
          <_projects>
            <ZEstimateProject z:Id="i193">
              <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">&lt;BOM&gt;</Name>
              <Parent z:Ref="i105" />
              <_lines>
                <ZEstimateLine z:Id="i224">
                  <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">PROSINE 1000</Name>
                  <Parent i:nil="true" />
                  <_lines />
                </ZEstimateLine>
              </_lines>
              <_projects />
              <_savedBudgets />
            </ZEstimateProject>
          </_projects>
          <_savedBudgets />
        </ZEstimateProject>
      </_projects>
    </ZEstimateProject>
    <ZEstimateProject z:Id="i281">
      <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">Project B</Name>
      <Parent i:nil="true" />
      <_lines>
        <ZEstimateLine z:Id="i297">
          <Name xmlns="http://schemas.datacontract.org/2004/07/Zynergy">#8X8SPOOL</Name>
          <Description>1-8"x14.05" flg x flg. DIP, Black</Description>
          <Parent i:nil="true" />
          <_lines />
        </ZEstimateLine>
      </_lines>
      <_projects />
    </ZEstimateProject>
  </_projects>
</ZEstimateContract>
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1 回答 1

2

你很亲密。我认为您需要做的就是使用评论中的更新版本并将您的第二个 CROSS APPLY 更改为此：

CROSS APPLY Proj.p.nodes('.//ZC:_lines/ZC:ZEstimateLine') as Line(l)

这使用您之前发现的相同的额外斜线来递归并找到所有行。

您需要针对您的数据进行测试，但针对您的样本，它似乎可以正常工作。

编辑：

好的，我想我现在有了。它要复杂得多，尽管我尝试使用递归 CTE 来实现，但我无法找到一种方法来直接链接两个递归 CTE，也无法使用单个 CTE 来实现。一个更大师的人可能能够改善这一点。

我最终得到的是两个表值 UDF，一个用于递归地分解所有项目，另一个用于每个项目并递归地分解所有行：

CREATE FUNCTION fn_explode_projects (@xdata xml)
RETURNS TABLE
AS
RETURN
WITH XMLNAMESPACES('http://schemas.datacontract.org/2004/07/Zeller.Gp' AS ZC, 
    'http://schemas.datacontract.org/2004/07/Zynergy' AS ZYN,
    'http://schemas.microsoft.com/2003/10/Serialization/' AS Z),
ProjList (ProjectName, ChildProjects, ChildLines)
AS
(
    SELECT CAST(NULL as varchar(50)) AS ProjectName,
        @xdata.query('/ZC:ZEstimateContract/ZC:_projects') AS ChildProjects,
        CAST(NULL AS xml) AS ChildLines

    UNION ALL

    SELECT CP.ChildProject.value('(./ZYN:Name)[1]', 'varchar(50)') AS ProjectName,
        CP.ChildProject.query('./ZC:_projects') AS ChildProjects,
        CP.ChildProject.query('./ZC:_lines') AS ChildLines

    FROM ProjList
        CROSS APPLY ProjList.ChildProjects.nodes('/ZC:_projects/ZC:ZEstimateProject') AS CP(ChildProject)
)
SELECT ProjectName, ChildProjects, ChildLines
FROM ProjList

GO


CREATE FUNCTION fn_explode_lines (@xdata xml)
RETURNS TABLE
AS
RETURN
WITH XMLNAMESPACES('http://schemas.datacontract.org/2004/07/Zeller.Gp' AS ZC, 
    'http://schemas.datacontract.org/2004/07/Zynergy' AS ZYN,
    'http://schemas.microsoft.com/2003/10/Serialization/' AS Z),
ItemList (ItemNumber, ChildLines)
AS
(
    SELECT CAST(NULL as varchar(50)) AS ItemNumber,
        @xdata.query('/ZC:_lines') AS ChildLines

    UNION ALL

    SELECT CL.ChildLine.value('(./ZYN:Name)[1]', 'varchar(50)') AS ItemNumber,
        CL.ChildLine.query('./ZC:_lines') AS ChildLines

    FROM ItemList
        CROSS APPLY ItemList.ChildLines.nodes('/ZC:_lines/ZC:ZEstimateLine') AS CL(ChildLine)
)
SELECT ItemNumber, ChildLines
FROM ItemList
GO

然后，您可以使用这些来执行您的查询：

SELECT CM.Contract, CM.RevisionLevel, CM.CustomerGpId,
    Proj.ProjectName,
    Line.ItemNumber
FROM dbo.tblContractMaster AS CM
    CROSS APPLY dbo.fn_explode_projects(CM.FullContract) Proj
    CROSS APPLY dbo.fn_explode_lines(Proj.ChildLines) Line
WHERE Proj.ProjectName IS NOT NULL AND Line.ItemNumber IS NOT NULL

这假定合同不直接包含行——所有行都必须包含在项目或另一行中。

于 2011-12-13T14:41:52.270 回答