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我已经在我的应用程序中实现了一个地址簿框架，我正在创建一个新联系人并在其中设置一些信息，然后稍后再显示。但是当我实际显示视图时，当我点击相应的按钮时，我无法打开电话应用程序或电子邮件应用程序。以下是我创建和保存信息的方式：

ABRecordRef record = ABPersonCreate();   

ABMutableMultiValueRef phoneMulti = ABMultiValueCreateMutable(kABMultiStringPropertyType);
ABMutableMultiValueRef address = ABMultiValueCreateMutable(kABDictionaryPropertyType);
ABMutableMultiValueRef emailMultiValue = ABMultiValueCreateMutable(kABPersonEmailProperty);
ABMultiValueAddValueAndLabel(emailMultiValue, @"someone_somewhere@abc.com", (CFStringRef)@"email", NULL);

CFStringRef keys[5];
CFStringRef values[5];
keys[0] = kABPersonAddressStreetKey;
keys[1] = kABPersonAddressCityKey;
keys[2] = kABPersonAddressStateKey;
keys[3] = kABPersonAddressZIPKey;
keys[4] = kABPersonAddressCountryKey;

values[0] = CFSTR("ABC way"); 
values[1] = CFSTR("Toronto");       
values[2] = CFSTR("ON");                
values[3] = CFSTR("L1A2B3");            
values[4] = CFSTR("Canada");            //This is static
CFDictionaryRef aDict = CFDictionaryCreate(
                                           kCFAllocatorDefault,
                                           (void *)keys,
                                           (void *)values,
                                           5,
                                           &kCFCopyStringDictionaryKeyCallBacks,
                                           &kCFTypeDictionaryValueCallBacks
                                           );


ABMultiValueAddValueAndLabel(address, aDict, kABHomeLabel, NULL);
CFRelease(aDict);

// Set up Phone Number
ABMultiValueAddValueAndLabel(phoneMulti, @"12345678910", kABWorkLabel, NULL);


ABRecordSetValue(record, kABPersonFirstNameProperty, firstName, NULL);
ABRecordSetValue(record, kABPersonLastNameProperty, lastName, NULL);
ABRecordSetValue(record, kABPersonNoteProperty, (CFStringRef)@" ", NULL);
ABRecordSetValue(record, kABPersonAddressProperty, address, NULL);
ABRecordSetValue(record, kABPersonEmailProperty, emailMultiValue, NULL);
ABRecordSetValue(record, kABPersonPhoneProperty, phoneMulti, nil);

我正在使用 anUnknownPersonViewController在另一个视图中访问记录。

ABUnknownPersonViewController *contactDetailsView = [[ABUnknownPersonViewController alloc]init];

contactDetailsView.allowsActions = YES;
contactDetailsView.displayedPerson = record;

[[self navigationController] pushViewController:contactDetailsView animated:YES];

为什么我不能做任何事情（打电话、发邮件、写便条）当我在我的contactDetailsView? 我该如何解决？我正在使用 iOS 5。

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1 回答 1

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放

contactDetailsView.unknownPersonViewDelegate = self;

然后实施

- (BOOL)unknownPersonViewController:(ABUnknownPersonViewController *)personViewController shouldPerformDefaultActionForPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier
{
    return YES;
}

当然 .h 文件应该有：

MyClass : <ABUnknownPersonViewControllerDelegate>

确保在设备上而不是在模拟器上测试行为

于 2012-06-22T08:21:07.820 回答