7

我是 NHibernate 的新手,我正在尝试学习如何查询我的数据。

下面是配置xml。仅显示配方。

我希望能够从输入的关键字和成分名称的成分中按配方标题查询食谱。

例如,您可以输入“pasta wine”。

这是我尝试过的,但给了我一个错误。

    hql = "from Recipe r " +
    "left join r.Images " +
    "inner join r.User " +
    "inner join r.Ingredients i " +
    "where i.IngredientName Like '%pasta%' OR i.IngredientName Like '%wine%' OR r.RecipeTitle Like '%pasta' OR r.RecipeTitle Like '%wine%'";

我也想急切地加载收藏。

我要查询对吗?我需要能够根据我的搜索条件构建查询字符串。这在 SQL 中对我来说很容易。

马尔科姆

  <class name="Recipe" table="Recipes" xmlns="urn:nhibernate-mapping-2.2">
    <id name="RecipeID" type="Int32" column="RecipeID">
      <generator class="identity" />
    </id>
    <property name="RecipeTitle" type="String">
      <column name="RecipeTitle" />
    </property>
    <property name="Completed" type="Boolean">
      <column name="Completed" />
    </property>
    <property name="ModifiedOn" type="DateTime">
      <column name="ModifiedOn" />
    </property>
    <property name="Rating" type="Double">
      <column name="Rating" />
    </property>
    <property name="PrepTime" type="Int32">
      <column name="PrepTime" />
    </property>
    <property name="CookTime" type="Int32">
      <column name="CookTime" />
    </property>
    <property name="Method" type="String">
      <column name="Method" />
    </property>
    <bag name="Images" inverse="true" cascade="all">
      <key column="RecipeID" />
      <one-to-many class="OurRecipes.Domain.RecipeImage, OurRecipes.Domain, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null" />
    </bag>
    <many-to-one name="Category" column="CategoryID" />
    <bag name="Comments" inverse="true" cascade="all">
      <key column="RecipeID" />
      <one-to-many class="OurRecipes.Domain.Comment, OurRecipes.Domain, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null" />
    </bag>
    <many-to-one name="User" column="EnteredByID" />
    <bag name="Ingredients" inverse="true" cascade="all">
      <key column="RecipeID" />
      <one-to-many class="OurRecipes.Domain.Ingredient, OurRecipes.Domain, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null" />
    </bag>
  </class>
4

3 回答 3

22

要构建动态查询,我会使用条件 API。这使得动态查询更加稳定,因为您不需要字符串操作来构建它。

ICriteria query = Session.CreateCriteria(typeof(Recipe), "r")
  .CreateCriteria("Ingredients", "i", JoinType.InnerJoin)
  .Add(
    Expression.Disjunction() // OR
      .Add(Expression.Like("i.IngredientName", "%pasta%"))
      .Add(Expression.Like("i.IngredientName", "%wine%"))
      .Add(Expression.Like("r.RecipeTitle", "%pasta%"))
      .Add(Expression.Like("r.RecipeTitle", "%wine%")));

List<Recipe> result = query.List<Recipe>();

编辑:

对于急切加载,您可以设置获取模式:

ICriteria query = Session.CreateCriteria(typeof(Recipe), "r")
  .SetFetchMode("Images", FetchMode.Join)
  .SetFetchMode("Comments", FetchMode.Join)
  .SetFetchMode("Ingredients", FetchMode.Join)

但我不会这样做,因为你得到的结果乘以图像、评论和成分的数量。因此,如果您有 4 张图片、2 条评论和 12 种成分,您将获得 96 次您的食谱。您没有认识到这一点,因为 NHibernate 将这些东西重新组合在一起,但它会在应用程序和数据库之间产生流量。所以最好让 NHibernate 用单独的查询来加载它。


再进行一次编辑以显示动态查询组合。

// filter arguments, all are optional and should be omitted if null
List<string> keywords;
TimeSpan? minCookingTime;
TimeSpan? maxCookingTime;
int? minRating;
int? maxRating;

ICriteria query = Session.CreateCriteria(typeof(Recipe), "r");

if (keyword != null)
{
  // optional join
  query.CreateCriteria("Ingredients", "i", JoinType.InnerJoin);

  // add keyword search on ingredientName and RecipeTitle
  var disjunction = Expression.Disjunction();
  foreach (string keyword in keywords)
  {
    string pattern = String.Format("%{0}%", keyword);
    disjunction
      .Add(Expression.Like("i.IngredientName", pattern))
      .Add(Expression.Like("r.RecipeTitle", pattern)); 
  }
  query.Add(disjunction)
}

if (minCookingTime != null)
{
  query.Add(Expression.Ge(r.CookingTime, minCookingTime.Value));
}
if (maxCookingTime != null)
{
  query.Add(Expression.Le(r.CookingTime, maxCookingTime.Value));
}

if (minRating != null)
{
  query.Add(Expression.Ge(r.Rating, minRating.Value));
}
if (maxRating != null)
{
  query.Add(Expression.Le(r.Rating, maxRating.Value));
}
于 2009-05-08T08:31:28.327 回答
5

Stefan 和 Sathish 的示例都将 % 运算符连接到 SQL 中。这是不必要的,因为 Restrictions.Like(nhib 2.0+)和 Expression.Like(v2.0 之前)有 3 个带有 MatchMode 的参数版本。

Disjunction keywordsCriteria = Restrictions.Disjunction();
foreach (var keyword in keywords)
{
    keywordsCriteria.Add(Restrictions.Like("i.IngredientName", keyword, MatchMode.Anywhere));
    keywordsCriteria.Add(Restrictions.Like("r.RecipeTitle", keyword, MatchMode.Anywhere));
}

NHibernate Search 也提供全文查询。有关详细信息,请参阅Ayende 的示例。

于 2009-05-11T11:43:54.867 回答
1

这是带有动态关键字的上述条件

string searchQuery = "wine pasta";

ICriteria query = Session.CreateCriteria(typeof(Recipe), "r")
                    .CreateCriteria("Ingredients", "i", JoinType.InnerJoin)
                    .SetFetchMode("Images", FetchMode.Join)
                    .SetFetchMode("Comments", FetchMode.Join)
                    .SetFetchMode("Ingredients", FetchMode.Join)
                    .SetResultTransformer(new DistinctRootEntityResultTransformer());

var keywords = searchQuery.Split(' ');

Disjunction keywordsCriteria = Restrictions.Disjunction();
foreach (var keyword in keywords)
{
    keywordsCriteria.Add(Restrictions.Like("i.IngredientName", string.Format("%{0}%", keyword)));
    keywordsCriteria.Add(Restrictions.Like("r.RecipeTitle", string.Format("%{0}%", keyword)));
}

query.Add(keywordsCriteria);

List<Recipe> result = query.List<Recipe>();
于 2009-05-10T18:46:10.213 回答