我有以下 MySQL:
select `car`.`ID` AS `ID`,
`title`,`text`
from `car`
LEFT JOIN `truck` as bigcar ON bigcar.`ID` = `car`.`truckID`
WHERE `ID` ='1';
出于某种原因,我得到
where 子句中的列“ID”不明确
由于复杂的代码原因,我没有将别名重命名为其他名称(例如 ID2)
这不应该吗?
您需要id在 where 子句中指定要用于的表。否则查询将不知道使用哪一个,因为您在两个表中具有相同的列名
SELECT
`car`.`ID` AS `ID`, `title`,`text`
FROM `car`
LEFT JOIN `truck` as bigcar ON bigcar.`ID` = `car`.`truckID`
WHERE `car`.`ID` ='1';
或者,如果您想要bigcarID,则必须使用:
WHERE `bigcar`.`ID` ='1'; // not truck but bigcar which is the alias you created
关于什么:
select `car`.`ID` AS `ID`,
`title`,`text`
from `car`
LEFT JOIN `truck` as bigcar ON bigcar.`ID` = `car`.`truckID`
WHERE `car`.`ID` ='1';
该错误意味着该字段ID存在于两个表中。要修复它,您应该在 WHERE 子句中添加一个表别名,例如 - bigcar.ID = 1 或 car.ID = 1 ...根据需要。