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我最近问了一个关于鼠标记录的问题。现在我需要弄清楚如何重播它。

最近的问题：https ://stackoverflow.com/questions/8129723/record-mouse-movement-with-javascript

我将使用 PHP 制作当前页面的相同副本，然后我将在其中插入重播脚本。该脚本将根据多个 x 和 y 坐标相对于时间添加和移动绝对定位图像（以说明鼠标移动）。

有没有什么好的方法（比下面更好）来重放多个鼠标移动？

<input style="width:100%" type="text" name="onlyforstackoverflow1" value="0" size="4"><br>
<input style="width:100%" type="text" name="onlyforstackoverflow2" value="0" size="4">



<script>

// I want this (a very long array with x-cordinates, y-cordinates and time from pageload)

var very_long_array = [1,2,1000,2,22,2000,3,33,3645,4,44,3456];

// To become the same as this

setTimeout("document.Show.onlyforstackoverflow1.value = 1;document.Show.onlyforstackoverflow2.value = 11;",100)
setTimeout("document.Show.onlyforstackoverflow1.value = 2;document.Show.onlyforstackoverflow2.value = 22;",200)
setTimeout("document.Show.onlyforstackoverflow1.value = 3;document.Show.onlyforstackoverflow2.value = 33;",364)
setTimeout("document.Show.onlyforstackoverflow1.value = 4;document.Show.onlyforstackoverflow2.value = 44;",453)


// in the real script it will be moving around an image instead...

</script>
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1 回答 1

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var dataList = [ 1, 2, 1000, 2, 22, 2000 ], // the long big array 
    preTime = 0;

function run() {
    var parts = dataList.splice( 0, 3 ), // after splice, dataList will be auto updated
        nowTime;

    if ( parts.length ==  3 ) {
         nowTime = parts[ 2 ];

         setTimeout( function() {
             replay( parts[ 0 ], parts[ 1 ] ); // x = parts[ 0 ], y = parts[ 1 ]

             preTime = nowTime;
             // continue run next replay
             run();
         }, nowTime - preTime );
    } 
}

function replay( x, y ) {
    // do something with x, y;
    // document.Show.onlyforstackoverflow1.value = x;
    // document.Show.onlyforstackoverflow2.value = y;
}

// start
run();

只需使用 setTimeout 来完成任务，您无需将每个任务都写成语句 :-)

于 2011-11-15T02:44:22.863 回答