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如何在 Cassandra 中获取给定行键的前 N ​​列?

cqlsh> select FIRST 5 from Daily_Domain_Stats where KEY = '20111110:1';
Bad Request: line 1:15 no viable alternative at input 'from'
cqlsh> select 'FIRST' 5 from Daily_Domain_Stats where KEY = '20111110:1';
Bad Request: line 1:15 no viable alternative at input '5'
cqlsh> select 'FIRST 5' from Daily_Domain_Stats where KEY = '20111110:1';
cqlsh> select FIRST '5' from Daily_Domain_Stats where KEY = '20111110:1';
Internal application error
cqlsh> select 5 from Daily_Domain_Stats where KEY = '20111110:1';
cqlsh> select [FIRST 5] from Daily_Domain_Stats where KEY = '20111110:1';
Bad Request: line 1:15 no viable alternative at character ']'

我尝试了所有这些方法,但都没有给我正确的结果。我使用 cql 1.0.5 Python 客户端

帮助问候,泰米尔语

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1 回答 1

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找到了解决办法,

cqlsh> select first 5 '0'..'9' from Daily_Customer_Stats;

这有效

参考http://www.slideshare.net/jericevans/cql20

于 2011-11-10T16:50:31.980 回答