我有 C++ 类及其用于 boost::python 的包装器：
class CApp
{
public:
virtual bool FOOs (){}; //does not matter for now
bool Run( const char * First,const char * Last)
{
...
return "Running..."
};
struct pyApp : CApp, wrapper<CApp> //derived class
{
... // wrappers for virtual methods
}
#include <boost/python.hpp>
using namespace boost::python;
BOOST_PYTHON_MODULE( myApp )
{
class_<pyApp, boost::noncopyable>("CApp", init<>() )
...
.def("Run",&pyMOOSApp::Run);
}
编译就OK了。但是当我调用 Python 代码时
from myApp import *
class pyApp(CApp):
def __init__(self):
print "INIT-->"
CClass = CApp()
pyClass = pyApp()
CClass.Run('myApp','bar')
pyClass.Run('myApp','bar')
我有一个错误：
INIT-->
Running... // this is from CClass.Run
Traceback (most recent call last):
File "./pytest.py", line 18, in <module>
pyClass.Run('myApp','bar')
Boost.Python.ArgumentError: Python argument types in
CApp.Run(pyApp, str, str)
did not match C++ signature:
Run(CApp {lvalue}, char const*, char const*)
因此，我尝试为 Run 方法编写一个包装器，该方法将 str 转换为 char 放置在派生类 c++ 代码中：
bool Run(std::string a, std::string b) {
char * cstrA;
char * cstrB;
cstrA = new char[a.size()+1];
cstrB = new char[b.size()+1];
strcpy(cstrA,a.c_str());
strcpy(cstrB,b.c_str());
return this -> CApp::Run(cstrA, cstrB);
}
但唯一的变化是在最后一击：
did not match C++ signature:
Run(pyApp {lvalue}, std::string, std::string)
我很确定 Run 方法的包装不好，所以任何帮助都将不胜感激。谢谢你。