当单击提交输入按钮时，我正在尝试将其他参数（选定复选框的列表）传递给服务器处理的 DataTables-table #my_table ：
这可能意味着我必须将my_table.sAjaxSource设置为后端脚本以及已编译的复选框列表，然后调用my_table.fnDraw()？
我准备了一个非常简单的测试用例 - test.php：
<?php
error_log('QUERY_STRING: ' . $_SERVER['QUERY_STRING']);
?>
和index.html：
<html>
<head>
<style type="text/css" title="currentStyle">
@import "/css/demo_table_jui.css";
@import "http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.0/themes/redmond/jquery-ui.css";
</style>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>;
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jqueryui/1/jquery-ui.min.js"></script>;
<script type="text/javascript" src="/js/jquery.dataTables.min.js"></script>
<script type="text/javascript">
$(function() {
my_table = $('#my_table').dataTable( {
bJQueryUI: true,
bServerSide: true,
bProcessing: true,
sAjaxSource: '/test.php'
} );
});
var my_table;
function redrawTable() {
var str = '';
var boxes = new Array();
//loop through all checkboxes
$(':checkbox').each(function() {
if ($(this).is(':checked')) {
boxes.push($(this).attr('name') + '=' + $(this).val());
}
});
str = '/test.php?' + boxes.join('&');
// TODO: set my_table.sAjaxSource to str
my_table.fnDraw();
}
</script>
</head>
<body>
<p>Select fruit:</p>
<p><label><input type="checkbox" name="fruits" value="apple">apple</label></p>
<p><label><input type="checkbox" name="fruits" value="banana">banana</label></p>
<p><label><input type="checkbox" name="fruits" value="pear">pear</label></p>
<p>Select candy:</p>
<p><label><input type="checkbox" name="candy" value="toffee">toffee</label></p>
<p><label><input type="checkbox" name="candy" value="fudge">fudge</label></p>
<p><input type="button" onclick="redrawTable();" value="Submit"></p>
<table class="display" id="my_table">
<thead>
<tr>
<th>Column_1</th>
<th>Column_2</th>
<th>Column_3</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
</body>
</html>
请告诉我，如何实现这一点（将自定义参数传递给 DataTables AJAX 源脚本）。
更新：这段代码似乎对我很有效，谢谢 Nicola
<html>
<head>
<style type="text/css" title="currentStyle">
@import "/css/demo_table_jui.css";
@import "http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.0/themes/redmond/jquery-ui.css";
</style>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jqueryui/1/jquery-ui.min.js"></script>
<script type="text/javascript" src="/js/jquery.dataTables.min.js"></script>
<script type="text/javascript">
var my_table;
$(function() {
my_table = $('#my_table').dataTable( {
bJQueryUI: true,
bServerSide: true,
bProcessing: true,
sAjaxSource: '/test.php',
fnServerParams: function ( aoData ) {
$(':checkbox').each(function() {
if ($(this).is(':checked')) {
aoData.push( { name: $(this).attr('name'), value: $(this).val() } );
}
});
}
});
});
</script>
</head>
<body>
<p>Select fruit:</p>
<p><label><input type="checkbox" name="fruits" value="apple">apple</label></p>
<p><label><input type="checkbox" name="fruits" value="banana">banana</label></p>
<p><label><input type="checkbox" name="fruits" value="pear">pear</label></p>
<p>Select candy:</p>
<p><label><input type="checkbox" name="candy" value="toffee">toffee</label></p>
<p><label><input type="checkbox" name="candy" value="fudge">fudge</label></p>
<p><input type="button" onclick="my_table.fnDraw();" value="Submit"></p>
<table class="display" id="my_table">
<thead>
<tr>
<th>Column_1</th>
<th>Column_2</th>
<th>Column_3</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
</body>
</html>
在 error_log 我看到：
QUERY_STRING:
sEcho=2&
iColumns=3&
sColumns=&
iDisplayStart=0&
iDisplayLength=10&
mDataProp_0=0&
mDataProp_1=1&
mDataProp_2=2&
sSearch=&
bRegex=false&
sSearch_0=&
bRegex_0=false&
bSearchable_0=true&
sSearch_1=&
bRegex_1=false&
bSearchable_1=true&
sSearch_2=&
bRegex_2=false&
bSearchable_2=true&
iSortingCols=1&
iSortCol_0=0&
sSortDir_0=asc&
bSortable_0=true&
bSortable_1=true&
bSortable_2=true&
fruits=apple&
fruits=banana&
candy=toffee&
candy=fudge&
_=1317666289823