8

我在 TCP 客户端中收到了一个字节 [] 数组。该数组包含一个 24 位 RGB 位图文件。如何创建具有给定宽度、高度和数据的位图文件?

在 C++ 中我使用这个

int WriteBitmapFile(const char *filename, int width, int height, unsigned char *imageData)
{
FILE             *filePtr;        // file pointer
BITMAPFILEHEADER bitmapFileHeader;    // bitmap file header
BITMAPINFOHEADER bitmapInfoHeader;    // bitmap info header
DWORD                 imageIdx;    // used for swapping RGB->BGR
unsigned char     tempRGB;            // used for swapping

// open file for writing binary mode
filePtr = fopen(filename, "wb");
if (!filePtr)
    return 0;

// define the bitmap file header
bitmapFileHeader.bfSize = sizeof(BITMAPFILEHEADER);
bitmapFileHeader.bfType = 0x4D42;
bitmapFileHeader.bfReserved1 = 0;
bitmapFileHeader.bfReserved2 = 0;
bitmapFileHeader.bfOffBits = sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER);

// define the bitmap information header
bitmapInfoHeader.biSize = sizeof(BITMAPINFOHEADER);
bitmapInfoHeader.biPlanes = 1;
bitmapInfoHeader.biBitCount = 32;                        // 24-bit
bitmapInfoHeader.biCompression = BI_RGB;                // no compression
bitmapInfoHeader.biSizeImage = width * abs(height) * 4;    // width * height * (RGB bytes)
bitmapInfoHeader.biXPelsPerMeter = 0;
bitmapInfoHeader.biYPelsPerMeter = 0;
bitmapInfoHeader.biClrUsed = 0;
bitmapInfoHeader.biClrImportant = 0;
bitmapInfoHeader.biWidth = width;                        // bitmap width
bitmapInfoHeader.biHeight = height;                    // bitmap height

// switch the image data from RGB to BGR
for(imageIdx = 0; imageIdx < bitmapInfoHeader.biSizeImage; imageIdx+=4)
{
    tempRGB = imageData[imageIdx];
    imageData[imageIdx] = imageData[imageIdx + 2];
    imageData[imageIdx + 2] = tempRGB;
}

// write the bitmap file header
fwrite(&bitmapFileHeader, 1, sizeof(BITMAPFILEHEADER), filePtr);

// write the bitmap info header
fwrite(&bitmapInfoHeader, 1, sizeof(BITMAPINFOHEADER), filePtr);

// write the image data
fwrite(imageData, 1, bitmapInfoHeader.biSizeImage, filePtr);

// close our file
fclose(filePtr);

// Success
return 1;
}

我怎么能在 C# 中做到这一点?

4

4 回答 4

12

If the array actually contains a bitmap file, then you can just save the bytes as a file:

File.WriteAllBytes(fileName, imageData);

If the array contains only raw pixel data, you can create a Bitmap object using the data:

unsafe {
   fixed (byte* ptr = imageData) {
      using (Bitmap image = new Bitmap(width, height, stride, PixelFormat.Format24bppRgb, new IntPtr(ptr))) {
         image.Save(fileName);
      }
   }
}

The stride value is the number of bytes between the scan lines. If there is no padding between the scan lines, it's width * 3 for a 24bpp format.

This method uses the data in the array without creating another copy of the entire image in memory (which is why it needs the stride value).

If the bitmap data is stored upside down in the array, the stride value should be negative, and the pointer should be the start of the last scan line in memory (ptr + stride * (height - 1)).

于 2009-04-12T20:38:04.820 回答
10

我无法使用您将收到的流对其进行测试,但这应该可以。

int WriteBitmapFile(string filename, int width, int height, byte[] imageData)
{
  using (var stream = new MemoryStream(imageData))
  using (var bmp = new Bitmap(width, height, PixelFormat.Format24bppRgb))
  {
    BitmapData bmpData = bmp.LockBits(new Rectangle(0, 0,
                                                    bmp.Width,
                                                    bmp.Height),
                                      ImageLockMode.WriteOnly,
                                      bmp.PixelFormat);

    Marshal.Copy(imageData, 0, bmpData.Scan0, imageData.Length);

    bmp.UnlockBits(bmpData);

    bmp.Save(filename);
  }

  return 1;
}
于 2009-04-12T19:23:02.270 回答
6

我建议在 C# 中制作一个位图,并让它自己保存。

例如,请参阅这篇文章。(特别是最后的回答是正确的。)

于 2009-04-12T19:15:42.037 回答
2

这是一种方法,在这里我创建了一个自定义事件参数,其中包含图像存储为字节数组的大小。您可能不需要为此烦恼,这是我创建的代码,用于从 gige 相机存储的字节数组中检索图像,因此对我来说这很有意义。

public Bitmap ShowImage(byte[] sender, EventImageParams e)
    {
        Bitmap bitmap = new Bitmap(e.width, e.height, PixelFormat.Format24bppRgb);
        BitmapData bmData = bitmap.LockBits(new Rectangle(0, 0, bitmap.Width, bitmap.Height),
                                            ImageLockMode.ReadWrite, bitmap.PixelFormat);
        IntPtr pNative = bmData.Scan0;

        Marshal.Copy(sender, 0, pNative, (e.width  * e.height * 3));
     //    
        bitmap.UnlockBits(bmData);

        return bitmap;
    }
于 2013-06-27T13:26:52.083 回答