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我正在努力使用 JavaScript 函数从 2 个不同的查询中获取数据。如果我执行在函数中分离的查询,我只能从第二个查询中的第一个得到最后一个结果。我得出的结论是,我必须对这 2 个查询进行子查询,这样该函数才能正常运行。

以下是两个查询 ( popt.products_options_id = prodOpId):

tx.executeSql('
SELECT DISTINCT
popt.products_options_id, 
popt.products_options_name 
FROM
products_options popt, 
products_attributes patrib 
WHERE
patrib.products_id="1" 
AND
patrib.options_id = popt.products_options_id 
AND
popt.language_id = "1"  
ORDER BY 
popt.products_options_name',
[], function (tx, results) {


tx.executeSql('
SELECT
pov.products_options_values_id,
pov.products_options_values_name, 
patrib.options_values_price, 
patrib.price_prefix 
FROM
products_attributes patrib, 
products_options_values pov 
WHERE
patrib.products_id = "1" 
AND
patrib.options_id ='+ prodOpId + ' 
AND
patrib.options_values_id = pov.products_options_values_id 
AND
pov.language_id = "1"', 
[], function (tx, results) {
4

1 回答 1

0

我解决了当前查询的问题:

tx.executeSql('
SELECT 
popt.products_options_id, 
popt.products_options_name,
pov.products_options_values_id, 
pov.products_options_values_name, 
patrib.options_values_price,
patrib.price_prefix 

FROM
products_options popt, 
products_attributes patrib, 
products_options_values pov 

WHERE 
patrib.products_id="1"

AND 
patrib.options_id = popt.products_options_id 

AND 
patrib.options_values_id = pov.products_options_values_id

AND 
popt.language_id = "1"

ORDER BY 
popt.products_options_name',

[], function (tx, results) {
于 2011-09-18T19:05:47.433 回答