我试图弄清楚如何仅根据信用卡号码来检测信用卡的类型。有谁知道找到这个的明确，可靠的方法？
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信用卡/借记卡号称为PAN或主帐号。PAN 的前六位数字取自属于发行银行的IIN或发行人标识号（IIN 以前称为 BIN — 银行标识号 — 因此您可能会在某些文件中看到对该术语的引用）。这六位数字受国际标准ISO/IEC 7812的约束，可用于根据数字确定卡的类型。
不幸的是，实际的 ISO/IEC 7812 数据库并未公开，但是，有非官方的列表，包括商业和免费的，包括在 Wikipedia 上。
无论如何，要从数字中检测类型，您可以使用如下所示的正则表达式：Credit for original expressions
Visa： ^4[0-9]{6,}$ Visa卡号以4开头。
MasterCard： ^5[1-5][0-9]{5,}|222[1-9][0-9]{3,}|22[3-9][0-9]{4,}|2[3-6][0-9]{5,}|27[01][0-9]{4,}|2720[0-9]{3,}$ 2016 年之前，MasterCard 号码以数字 51 到 55 开头，但这只会检测 MasterCard 信用卡；使用 MasterCard 系统发行的其他卡不属于此 IIN 范围。2016 年，他们将在 (222100-272099) 范围内添加数字。
美国运通： ^3[47][0-9]{5,}$美国运通卡号以 34 或 37 开头。
Diners Club： ^3(?:0[0-5]|[68][0-9])[0-9]{4,}$ Diners Club 卡号以 300 到 305、36 或 38 开头。有些 Diners Club 卡以 5 开头，有 16 位数字。这些是大来卡和万事达卡的合资企业，应该像万事达卡一样处理。
Discover： ^6(?:011|5[0-9]{2})[0-9]{3,}$ Discover 卡号以 6011 或 65 开头。
JCB： ^(?:2131|1800|35[0-9]{3})[0-9]{3,}$ JCB 卡以 2131、1800 或 35 开头。
不幸的是，万事达卡系统处理的许多卡类型不在万事达卡的 IIN 范围内（数字从 51...55 开始）；最重要的案例是 Maestro 卡，其中许多是从其他银行的 IIN 范围发行的，因此遍布数字空间。因此，最好假设任何不是您接受的其他类型的卡都必须是 MasterCard。
重要提示：卡号的长度确实不同；例如，Visa 过去曾发行具有 13 位 PAN 的卡和具有 16 位 PAN 的卡。Visa 的文件目前表明它可能发布或可能已经发布了 12 到 19 位数字之间的号码。 因此，您不应该检查卡号的长度，而是验证它至少有 7 位数字（对于完整的 IIN 加上一个校验位，它应该与Luhn 算法预测的值匹配）。
进一步的提示：在处理持卡人 PAN 之前，从输入中删除所有空格和标点符号。为什么？因为按组输入数字通常要容易得多，类似于它们在实际信用卡正面的显示方式，即
4444 4444 4444 4444
比正确输入要容易得多
4444444444444444
责备用户确实没有任何好处，因为他们在这里输入了您意想不到的字符。
这也意味着确保您的输入字段至少有24 个字符的空间，否则输入空格的用户将用完空间。 我建议您使字段足够宽以显示 32 个字符并最多允许 64 个字符；这为扩展提供了充足的空间。
这是一个提供更多洞察力的图像：
更新（2016 年）：万事达卡将从Ach Payment开始实施新的 BIN 范围。
于 2008-09-16T14:18:30.457 回答
84
在 JavaScript 中：
function detectCardType(number) {
var re = {
electron: /^(4026|417500|4405|4508|4844|4913|4917)\d+$/,
maestro: /^(5018|5020|5038|5612|5893|6304|6759|6761|6762|6763|0604|6390)\d+$/,
dankort: /^(5019)\d+$/,
interpayment: /^(636)\d+$/,
unionpay: /^(62|88)\d+$/,
visa: /^4[0-9]{12}(?:[0-9]{3})?$/,
mastercard: /^5[1-5][0-9]{14}$/,
amex: /^3[47][0-9]{13}$/,
diners: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/,
discover: /^6(?:011|5[0-9]{2})[0-9]{12}$/,
jcb: /^(?:2131|1800|35\d{3})\d{11}$/
}
for(var key in re) {
if(re[key].test(number)) {
return key
}
}
}
单元测试：
describe('CreditCard', function() {
describe('#detectCardType', function() {
var cards = {
'8800000000000000': 'UNIONPAY',
'4026000000000000': 'ELECTRON',
'4175000000000000': 'ELECTRON',
'4405000000000000': 'ELECTRON',
'4508000000000000': 'ELECTRON',
'4844000000000000': 'ELECTRON',
'4913000000000000': 'ELECTRON',
'4917000000000000': 'ELECTRON',
'5019000000000000': 'DANKORT',
'5018000000000000': 'MAESTRO',
'5020000000000000': 'MAESTRO',
'5038000000000000': 'MAESTRO',
'5612000000000000': 'MAESTRO',
'5893000000000000': 'MAESTRO',
'6304000000000000': 'MAESTRO',
'6759000000000000': 'MAESTRO',
'6761000000000000': 'MAESTRO',
'6762000000000000': 'MAESTRO',
'6763000000000000': 'MAESTRO',
'0604000000000000': 'MAESTRO',
'6390000000000000': 'MAESTRO',
'3528000000000000': 'JCB',
'3589000000000000': 'JCB',
'3529000000000000': 'JCB',
'6360000000000000': 'INTERPAYMENT',
'4916338506082832': 'VISA',
'4556015886206505': 'VISA',
'4539048040151731': 'VISA',
'4024007198964305': 'VISA',
'4716175187624512': 'VISA',
'5280934283171080': 'MASTERCARD',
'5456060454627409': 'MASTERCARD',
'5331113404316994': 'MASTERCARD',
'5259474113320034': 'MASTERCARD',
'5442179619690834': 'MASTERCARD',
'6011894492395579': 'DISCOVER',
'6011388644154687': 'DISCOVER',
'6011880085013612': 'DISCOVER',
'6011652795433988': 'DISCOVER',
'6011375973328347': 'DISCOVER',
'345936346788903': 'AMEX',
'377669501013152': 'AMEX',
'373083634595479': 'AMEX',
'370710819865268': 'AMEX',
'371095063560404': 'AMEX'
};
Object.keys(cards).forEach(function(number) {
it('should detect card ' + number + ' as ' + cards[number], function() {
Basket.detectCardType(number).should.equal(cards[number]);
});
});
});
});
于 2013-10-02T14:04:21.543 回答
49
更新时间：2016 年 6 月 15 日（目前作为最终解决方案）
请注意，我什至投票赞成票数最高的那个，但为了清楚起见，这些是真正有效的正则表达式，我用数千个真实的 BIN 代码对其进行了测试。最重要的是使用起始字符串 (^) 否则它会在现实世界中给出错误的结果！
JCB ^(?:2131|1800|35)[0-9]{0,}$开头：2131、1800、35 (3528-3589)
美国运通 ^3[47][0-9]{0,}$开头：34、37
Diners Club ^3(?:0[0-59]{1}|[689])[0-9]{0,}$开始：300-305、309、36、38-39
签证 ^4[0-9]{0,}$起始：4
万事达卡 ^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$开头：2221-2720、51-55
Maestro ^(5[06789]|6)[0-9]{0,}$ Maestro 始终在以下范围内增长：60-69，以/不是其他东西开头，但无论如何，从 5 开始必须编码为万事达卡。必须在代码末尾检测到 Maestro 卡，因为其他一些卡在 60-69 范围内。请看代码。
发现 ^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$发现很难编码，从：6011、622126-622925、644-649、65开始
在javascript中我使用这个函数。当您将其分配给 onkeyup 事件并尽快给出结果时，这很好。
function cc_brand_id(cur_val) {
// the regular expressions check for possible matches as you type, hence the OR operators based on the number of chars
// regexp string length {0} provided for soonest detection of beginning of the card numbers this way it could be used for BIN CODE detection also
//JCB
jcb_regex = new RegExp('^(?:2131|1800|35)[0-9]{0,}$'); //2131, 1800, 35 (3528-3589)
// American Express
amex_regex = new RegExp('^3[47][0-9]{0,}$'); //34, 37
// Diners Club
diners_regex = new RegExp('^3(?:0[0-59]{1}|[689])[0-9]{0,}$'); //300-305, 309, 36, 38-39
// Visa
visa_regex = new RegExp('^4[0-9]{0,}$'); //4
// MasterCard
mastercard_regex = new RegExp('^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$'); //2221-2720, 51-55
maestro_regex = new RegExp('^(5[06789]|6)[0-9]{0,}$'); //always growing in the range: 60-69, started with / not something else, but starting 5 must be encoded as mastercard anyway
//Discover
discover_regex = new RegExp('^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$');
////6011, 622126-622925, 644-649, 65
// get rid of anything but numbers
cur_val = cur_val.replace(/\D/g, '');
// checks per each, as their could be multiple hits
//fix: ordering matter in detection, otherwise can give false results in rare cases
var sel_brand = "unknown";
if (cur_val.match(jcb_regex)) {
sel_brand = "jcb";
} else if (cur_val.match(amex_regex)) {
sel_brand = "amex";
} else if (cur_val.match(diners_regex)) {
sel_brand = "diners_club";
} else if (cur_val.match(visa_regex)) {
sel_brand = "visa";
} else if (cur_val.match(mastercard_regex)) {
sel_brand = "mastercard";
} else if (cur_val.match(discover_regex)) {
sel_brand = "discover";
} else if (cur_val.match(maestro_regex)) {
if (cur_val[0] == '5') { //started 5 must be mastercard
sel_brand = "mastercard";
} else {
sel_brand = "maestro"; //maestro is all 60-69 which is not something else, thats why this condition in the end
}
}
return sel_brand;
}
在这里你可以玩它：
对于 PHP 使用这个函数，它也会检测到一些子 VISA/MC 卡：
/**
* Obtain a brand constant from a PAN
*
* @param string $pan Credit card number
* @param bool $include_sub_types Include detection of sub visa brands
* @return string
*/
public static function getCardBrand($pan, $include_sub_types = false)
{
//maximum length is not fixed now, there are growing number of CCs has more numbers in length, limiting can give false negatives atm
//these regexps accept not whole cc numbers too
//visa
$visa_regex = "/^4[0-9]{0,}$/";
$vpreca_regex = "/^428485[0-9]{0,}$/";
$postepay_regex = "/^(402360|402361|403035|417631|529948){0,}$/";
$cartasi_regex = "/^(432917|432930|453998)[0-9]{0,}$/";
$entropay_regex = "/^(406742|410162|431380|459061|533844|522093)[0-9]{0,}$/";
$o2money_regex = "/^(422793|475743)[0-9]{0,}$/";
// MasterCard
$mastercard_regex = "/^(5[1-5]|222[1-9]|22[3-9]|2[3-6]|27[01]|2720)[0-9]{0,}$/";
$maestro_regex = "/^(5[06789]|6)[0-9]{0,}$/";
$kukuruza_regex = "/^525477[0-9]{0,}$/";
$yunacard_regex = "/^541275[0-9]{0,}$/";
// American Express
$amex_regex = "/^3[47][0-9]{0,}$/";
// Diners Club
$diners_regex = "/^3(?:0[0-59]{1}|[689])[0-9]{0,}$/";
//Discover
$discover_regex = "/^(6011|65|64[4-9]|62212[6-9]|6221[3-9]|622[2-8]|6229[01]|62292[0-5])[0-9]{0,}$/";
//JCB
$jcb_regex = "/^(?:2131|1800|35)[0-9]{0,}$/";
//ordering matter in detection, otherwise can give false results in rare cases
if (preg_match($jcb_regex, $pan)) {
return "jcb";
}
if (preg_match($amex_regex, $pan)) {
return "amex";
}
if (preg_match($diners_regex, $pan)) {
return "diners_club";
}
//sub visa/mastercard cards
if ($include_sub_types) {
if (preg_match($vpreca_regex, $pan)) {
return "v-preca";
}
if (preg_match($postepay_regex, $pan)) {
return "postepay";
}
if (preg_match($cartasi_regex, $pan)) {
return "cartasi";
}
if (preg_match($entropay_regex, $pan)) {
return "entropay";
}
if (preg_match($o2money_regex, $pan)) {
return "o2money";
}
if (preg_match($kukuruza_regex, $pan)) {
return "kukuruza";
}
if (preg_match($yunacard_regex, $pan)) {
return "yunacard";
}
}
if (preg_match($visa_regex, $pan)) {
return "visa";
}
if (preg_match($mastercard_regex, $pan)) {
return "mastercard";
}
if (preg_match($discover_regex, $pan)) {
return "discover";
}
if (preg_match($maestro_regex, $pan)) {
if ($pan[0] == '5') { //started 5 must be mastercard
return "mastercard";
}
return "maestro"; //maestro is all 60-69 which is not something else, thats why this condition in the end
}
return "unknown"; //unknown for this system
}
于 2014-02-07T01:21:26.007 回答
25
public string GetCreditCardType(string CreditCardNumber)
{
Regex regVisa = new Regex("^4[0-9]{12}(?:[0-9]{3})?$");
Regex regMaster = new Regex("^5[1-5][0-9]{14}$");
Regex regExpress = new Regex("^3[47][0-9]{13}$");
Regex regDiners = new Regex("^3(?:0[0-5]|[68][0-9])[0-9]{11}$");
Regex regDiscover = new Regex("^6(?:011|5[0-9]{2})[0-9]{12}$");
Regex regJCB = new Regex("^(?:2131|1800|35\\d{3})\\d{11}$");
if (regVisa.IsMatch(CreditCardNumber))
return "VISA";
else if (regMaster.IsMatch(CreditCardNumber))
return "MASTER";
else if (regExpress.IsMatch(CreditCardNumber))
return "AEXPRESS";
else if (regDiners.IsMatch(CreditCardNumber))
return "DINERS";
else if (regDiscover.IsMatch(CreditCardNumber))
return "DISCOVERS";
else if (regJCB.IsMatch(CreditCardNumber))
return "JCB";
else
return "invalid";
}
这是使用 Regex , c# 检查信用卡类型的功能
于 2012-12-12T14:55:41.057 回答
20
看一下这个：
http://www.breakpar.com/bkp/home.nsf/0/87256B280015193F87256CC70060A01B
function isValidCreditCard(type, ccnum) {
/* Visa: length 16, prefix 4, dashes optional.
Mastercard: length 16, prefix 51-55, dashes optional.
Discover: length 16, prefix 6011, dashes optional.
American Express: length 15, prefix 34 or 37.
Diners: length 14, prefix 30, 36, or 38. */
var re = new Regex({
"visa": "/^4\d{3}-?\d{4}-?\d{4}-?\d",
"mc": "/^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/",
"disc": "/^6011-?\d{4}-?\d{4}-?\d{4}$/",
"amex": "/^3[47]\d{13}$/",
"diners": "/^3[068]\d{12}$/"
}[type.toLowerCase()])
if (!re.test(ccnum)) return false;
// Remove all dashes for the checksum checks to eliminate negative numbers
ccnum = ccnum.split("-").join("");
// Checksum ("Mod 10")
// Add even digits in even length strings or odd digits in odd length strings.
var checksum = 0;
for (var i = (2 - (ccnum.length % 2)); i <= ccnum.length; i += 2) {
checksum += parseInt(ccnum.charAt(i - 1));
}
// Analyze odd digits in even length strings or even digits in odd length strings.
for (var i = (ccnum.length % 2) + 1; i < ccnum.length; i += 2) {
var digit = parseInt(ccnum.charAt(i - 1)) * 2;
if (digit < 10) { checksum += digit; } else { checksum += (digit - 9); }
}
if ((checksum % 10) == 0) return true;
else return false;
}
于 2010-03-09T11:21:12.957 回答
15
最近我需要这样的功能，我正在将 Zend Framework Credit Card Validator 移植到 ruby。ruby gem：https ://github.com/Fivell/credit_card_validations zend 框架：https ://github.com/zendframework/zf2/blob/master/library/Zend/Validator/CreditCard.php
他们都使用 INN 范围来检测类型。在这里您可以阅读有关 INN 的信息
根据这个，您可以选择检测信用卡（没有正则表达式，但声明一些关于前缀和可能长度的规则）
所以我们对最常用的卡片有下一个规则
######## most used brands #########
visa: [
{length: [13, 16], prefixes: ['4']}
],
mastercard: [
{length: [16], prefixes: ['51', '52', '53', '54', '55']}
],
amex: [
{length: [15], prefixes: ['34', '37']}
],
######## other brands ########
diners: [
{length: [14], prefixes: ['300', '301', '302', '303', '304', '305', '36', '38']},
],
#There are Diners Club (North America) cards that begin with 5. These are a joint venture between Diners Club and MasterCard, and are processed like a MasterCard
# will be removed in next major version
diners_us: [
{length: [16], prefixes: ['54', '55']}
],
discover: [
{length: [16], prefixes: ['6011', '644', '645', '646', '647', '648',
'649', '65']}
],
jcb: [
{length: [16], prefixes: ['3528', '3529', '353', '354', '355', '356', '357', '358', '1800', '2131']}
],
laser: [
{length: [16, 17, 18, 19], prefixes: ['6304', '6706', '6771']}
],
solo: [
{length: [16, 18, 19], prefixes: ['6334', '6767']}
],
switch: [
{length: [16, 18, 19], prefixes: ['633110', '633312', '633304', '633303', '633301', '633300']}
],
maestro: [
{length: [12, 13, 14, 15, 16, 17, 18, 19], prefixes: ['5010', '5011', '5012', '5013', '5014', '5015', '5016', '5017', '5018',
'502', '503', '504', '505', '506', '507', '508',
'6012', '6013', '6014', '6015', '6016', '6017', '6018', '6019',
'602', '603', '604', '605', '6060',
'677', '675', '674', '673', '672', '671', '670',
'6760', '6761', '6762', '6763', '6764', '6765', '6766', '6768', '6769']}
],
# Luhn validation are skipped for union pay cards because they have unknown generation algoritm
unionpay: [
{length: [16, 17, 18, 19], prefixes: ['622', '624', '625', '626', '628'], skip_luhn: true}
],
dankrot: [
{length: [16], prefixes: ['5019']}
],
rupay: [
{length: [16], prefixes: ['6061', '6062', '6063', '6064', '6065', '6066', '6067', '6068', '6069', '607', '608'], skip_luhn: true}
]
}
然后通过搜索前缀和比较长度可以检测信用卡品牌。也不要忘记 luhn 算法（在此处描述http://en.wikipedia.org/wiki/Luhn）。
更新
可以在此处找到更新的规则列表https://raw.githubusercontent.com/Fivell/credit_card_validations/master/lib/data/brands.yaml
于 2013-03-19T12:15:48.060 回答
13
这是codeproject 上各种 CC 相关内容的完整 C# 或 VB 代码。
- IsValidNumber
- GetCardTypeFromNumber
- GetCardTestNumber
- 通过卢恩测试
这篇文章已经发布了几年，没有任何负面评论。
于 2009-11-22T23:20:02.573 回答
8
这是一个 php 类函数，通过 CCnumber 返回 CCtype。
此代码不验证卡或不运行 Luhn 算法仅尝试根据此页面
中的表查找信用卡类型。基本使用CCnumber长度和CCcard前缀来确定CCcard类型。
<?php
class CreditcardType
{
public static $creditcardTypes = [
[
'Name' => 'American Express',
'cardLength' => [15],
'cardPrefix' => ['34', '37'],
], [
'Name' => 'Maestro',
'cardLength' => [12, 13, 14, 15, 16, 17, 18, 19],
'cardPrefix' => ['5018', '5020', '5038', '6304', '6759', '6761', '6763'],
], [
'Name' => 'Mastercard',
'cardLength' => [16],
'cardPrefix' => ['51', '52', '53', '54', '55'],
], [
'Name' => 'Visa',
'cardLength' => [13, 16],
'cardPrefix' => ['4'],
], [
'Name' => 'JCB',
'cardLength' => [16],
'cardPrefix' => ['3528', '3529', '353', '354', '355', '356', '357', '358'],
], [
'Name' => 'Discover',
'cardLength' => [16],
'cardPrefix' => ['6011', '622126', '622127', '622128', '622129', '62213','62214', '62215', '62216', '62217', '62218', '62219','6222', '6223', '6224', '6225', '6226', '6227', '6228','62290', '62291', '622920', '622921', '622922', '622923','622924', '622925', '644', '645', '646', '647', '648','649', '65'],
], [
'Name' => 'Solo',
'cardLength' => [16, 18, 19],
'cardPrefix' => ['6334', '6767'],
], [
'Name' => 'Unionpay',
'cardLength' => [16, 17, 18, 19],
'cardPrefix' => ['622126', '622127', '622128', '622129', '62213', '62214','62215', '62216', '62217', '62218', '62219', '6222', '6223','6224', '6225', '6226', '6227', '6228', '62290', '62291','622920', '622921', '622922', '622923', '622924', '622925'],
], [
'Name' => 'Diners Club',
'cardLength' => [14],
'cardPrefix' => ['300', '301', '302', '303', '304', '305', '36'],
], [
'Name' => 'Diners Club US',
'cardLength' => [16],
'cardPrefix' => ['54', '55'],
], [
'Name' => 'Diners Club Carte Blanche',
'cardLength' => [14],
'cardPrefix' => ['300', '305'],
], [
'Name' => 'Laser',
'cardLength' => [16, 17, 18, 19],
'cardPrefix' => ['6304', '6706', '6771', '6709'],
],
];
public static function getType($CCNumber)
{
$CCNumber = trim($CCNumber);
$type = 'Unknown';
foreach (CreditcardType::$creditcardTypes as $card) {
if (! in_array(strlen($CCNumber), $card['cardLength'])) {
continue;
}
$prefixes = '/^(' . implode('|', $card['cardPrefix']) . ')/';
if (preg_match($prefixes, $CCNumber) == 1) {
$type = $card['Name'];
break;
}
}
return $type;
}
}
于 2013-08-13T18:29:04.110 回答
8
紧凑的 JavaScript 版本
var getCardType = function (number) {
var cards = {
visa: /^4[0-9]{12}(?:[0-9]{3})?$/,
mastercard: /^5[1-5][0-9]{14}$/,
amex: /^3[47][0-9]{13}$/,
diners: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/,
discover: /^6(?:011|5[0-9]{2})[0-9]{12}$/,
jcb: /^(?:2131|1800|35\d{3})\d{11}$/
};
for (var card in cards) {
if (cards[card].test(number)) {
return card;
}
}
};
于 2014-03-25T10:33:22.867 回答
8
Anatoliy 在 PHP 中的回答：
public static function detectCardType($num)
{
$re = array(
"visa" => "/^4[0-9]{12}(?:[0-9]{3})?$/",
"mastercard" => "/^5[1-5][0-9]{14}$/",
"amex" => "/^3[47][0-9]{13}$/",
"discover" => "/^6(?:011|5[0-9]{2})[0-9]{12}$/",
);
if (preg_match($re['visa'],$num))
{
return 'visa';
}
else if (preg_match($re['mastercard'],$num))
{
return 'mastercard';
}
else if (preg_match($re['amex'],$num))
{
return 'amex';
}
else if (preg_match($re['discover'],$num))
{
return 'discover';
}
else
{
return false;
}
}
于 2015-06-20T17:58:57.837 回答
7
信用卡的第一个数字可用于近似供应商：
- 签证：49,44 或 47
- 电子签证：42、45、48、49
- 万事达卡：51
- 美国运通：34
- 食客：30、36、38
- 捷豹路虎：35
于 2008-09-16T14:56:31.973 回答
6
请勿在处理付款过程中尝试检测信用卡类型。您有拒绝有效交易的风险。
如果您需要向您的支付处理器提供信息（例如 PayPal 信用卡对象需要命名卡类型），请从可用的最少信息中猜测它，例如
$credit_card['pan'] = preg_replace('/[^0-9]/', '', $credit_card['pan']);
$inn = (int) mb_substr($credit_card['pan'], 0, 2);
// @see http://en.wikipedia.org/wiki/List_of_Bank_Identification_Numbers#Overview
if ($inn >= 40 && $inn <= 49) {
$type = 'visa';
} else if ($inn >= 51 && $inn <= 55) {
$type = 'mastercard';
} else if ($inn >= 60 && $inn <= 65) {
$type = 'discover';
} else if ($inn >= 34 && $inn <= 37) {
$type = 'amex';
} else {
throw new \UnexpectedValueException('Unsupported card type.');
}
这种实现（仅使用前两位数字）足以识别所有主要的（在 PayPal 的情况下是所有受支持的）卡方案。事实上，您可能希望完全跳过该例外并默认使用最流行的卡片类型。让支付网关/处理器告诉您响应您的请求时是否存在验证错误。
现实情况是您的支付网关并不关心您提供的价值。
于 2014-02-26T07:05:25.627 回答
6
在卡片范围识别 (CRR) 中，使用一系列正则表达式或其他硬编码范围的算法的一个缺点是，根据我的经验，BIN/IIN 确实会随着时间而变化。卡的联合品牌是一个持续的复杂性。不同的卡收单机构/商家可能需要您以不同的方式对待同一张卡，具体取决于地理位置。
此外，在过去几年中，例如银联卡在更广泛的流通中，现有模型无法应对有时与它们所取代的更广泛范围交错的新范围。
了解您的系统需要覆盖的地理位置可能会有所帮助，因为某些范围仅限于在特定国家/地区使用。例如，范围 62 包括美国的一些 AAA 子范围，但如果您的商户基地在美国以外，您可以将所有 62 视为银联。
您可能还会被要求根据商家位置区别对待卡片。例如，将某些英国卡在国内视为借记卡，但在国际上视为信用卡。
一个主要的收单银行维护着一套非常有用的规则。例如https://www.barclaycard.co.uk/business/files/BIN-Rules-EIRE.pdf和https://www.barclaycard.co.uk/business/files/BIN-Rules-UK.pdf。（截至 2017 年 6 月的有效链接，感谢提供更新参考链接的用户。）但请注意，虽然这些 CRR 规则可能代表发卡领域，因为它适用于该实体收购的商家，它不包括例如标识为 CUP/UPI 的范围。
这些注释适用于磁条 (MagStripe) 或 PKE（Pan Key Entry）方案。ICC/EMV 世界的情况又有所不同。
更新：此页面上的其他答案（以及链接的 WikiPedia 页面）的 JCB 始终为 16 长。但是，在我的公司，我们有一个专门的工程师团队，他们在多个收单银行和地区对我们的 POS 设备和软件进行认证。该团队从 JCB 获得的最新认证卡包有一个 19 长 PAN 的通行证。
于 2014-12-22T10:36:54.180 回答
5
Usman Y 的答案的 Swift 2.1 版本。使用 print 语句通过某个字符串值验证 so 调用
print(self.validateCardType(self.creditCardField.text!))
func validateCardType(testCard: String) -> String {
let regVisa = "^4[0-9]{12}(?:[0-9]{3})?$"
let regMaster = "^5[1-5][0-9]{14}$"
let regExpress = "^3[47][0-9]{13}$"
let regDiners = "^3(?:0[0-5]|[68][0-9])[0-9]{11}$"
let regDiscover = "^6(?:011|5[0-9]{2})[0-9]{12}$"
let regJCB = "^(?:2131|1800|35\\d{3})\\d{11}$"
let regVisaTest = NSPredicate(format: "SELF MATCHES %@", regVisa)
let regMasterTest = NSPredicate(format: "SELF MATCHES %@", regMaster)
let regExpressTest = NSPredicate(format: "SELF MATCHES %@", regExpress)
let regDinersTest = NSPredicate(format: "SELF MATCHES %@", regDiners)
let regDiscoverTest = NSPredicate(format: "SELF MATCHES %@", regDiscover)
let regJCBTest = NSPredicate(format: "SELF MATCHES %@", regJCB)
if regVisaTest.evaluateWithObject(testCard){
return "Visa"
}
else if regMasterTest.evaluateWithObject(testCard){
return "MasterCard"
}
else if regExpressTest.evaluateWithObject(testCard){
return "American Express"
}
else if regDinersTest.evaluateWithObject(testCard){
return "Diners Club"
}
else if regDiscoverTest.evaluateWithObject(testCard){
return "Discover"
}
else if regJCBTest.evaluateWithObject(testCard){
return "JCB"
}
return ""
}
于 2016-04-07T17:54:27.407 回答
4
Stripe为卡片方案检测提供了这个奇妙的javascript库。让我添加一些代码片段并向您展示如何使用它。
首先将其包含到您的网页中
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery.payment/1.2.3/jquery.payment.js " ></script>
其次使用函数 cardType 来检测卡片方案。
$(document).ready(function() {
var type = $.payment.cardType("4242 4242 4242 4242"); //test card number
console.log(type);
});
以下是更多示例和演示的参考链接。
于 2015-04-29T07:36:08.187 回答
4
您可以快速创建一个枚举来检测信用卡类型。
enum CreditCardType: Int { // Enum which encapsulates different card types and method to find the type of card.
case Visa
case Master
case Amex
case Discover
func validationRegex() -> String {
var regex = ""
switch self {
case .Visa:
regex = "^4[0-9]{6,}$"
case .Master:
regex = "^5[1-5][0-9]{5,}$"
case .Amex:
regex = "^3[47][0-9]{13}$"
case .Discover:
regex = "^6(?:011|5[0-9]{2})[0-9]{12}$"
}
return regex
}
func validate(cardNumber: String) -> Bool {
let predicate = NSPredicate(format: "SELF MATCHES %@", validationRegex())
return predicate.evaluateWithObject(cardNumber)
}
// Method returns the credit card type for given card number
static func cardTypeForCreditCardNumber(cardNumber: String) -> CreditCardType? {
var creditCardType: CreditCardType?
var index = 0
while let cardType = CreditCardType(rawValue: index) {
if cardType.validate(cardNumber) {
creditCardType = cardType
break
} else {
index++
}
}
return creditCardType
}
}
调用方法 CreditCardType.cardTypeForCreditCardNumber("#card number") 返回 CreditCardType 枚举值。
于 2016-06-01T05:15:22.440 回答
3
我使用 jQuery 的解决方案：
function detectCreditCardType() {
var type = new Array;
type[1] = '^4[0-9]{12}(?:[0-9]{3})?$'; // visa
type[2] = '^5[1-5][0-9]{14}$'; // mastercard
type[3] = '^6(?:011|5[0-9]{2})[0-9]{12}$'; // discover
type[4] = '^3[47][0-9]{13}$'; // amex
var ccnum = $('.creditcard').val().replace(/[^\d.]/g, '');
var returntype = 0;
$.each(type, function(idx, re) {
var regex = new RegExp(re);
if(regex.test(ccnum) && idx>0) {
returntype = idx;
}
});
return returntype;
}
如果返回 0，则未检测到信用卡类型。
“信用卡”类应添加到信用卡输入字段。
于 2014-07-07T16:13:31.770 回答
3
我搜索了很多信用卡格式和电话号码格式。找到了很多好的技巧，但没有什么真正适合我的确切愿望，所以我创建了这段代码。你像这样使用它：
var sf = smartForm.formatCC(myInputString);
var cardType = sf.cardType;
于 2015-07-30T21:35:48.597 回答
3
@Anatoliy 答案的 javascript 改进
function getCardType (number) {
const numberFormated = number.replace(/\D/g, '')
var patterns = {
VISA: /^4[0-9]{12}(?:[0-9]{3})?$/,
MASTER: /^5[1-5][0-9]{14}$/,
AMEX: /^3[47][0-9]{13}$/,
ELO: /^((((636368)|(438935)|(504175)|(451416)|(636297))\d{0,10})|((5067)|(4576)|(4011))\d{0,12})$/,
AURA: /^(5078\d{2})(\d{2})(\d{11})$/,
JCB: /^(?:2131|1800|35\d{3})\d{11}$/,
DINERS: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/,
DISCOVERY: /^6(?:011|5[0-9]{2})[0-9]{12}$/,
HIPERCARD: /^(606282\d{10}(\d{3})?)|(3841\d{15})$/,
ELECTRON: /^(4026|417500|4405|4508|4844|4913|4917)\d+$/,
MAESTRO: /^(5018|5020|5038|5612|5893|6304|6759|6761|6762|6763|0604|6390)\d+$/,
DANKORT: /^(5019)\d+$/,
INTERPAYMENT: /^(636)\d+$/,
UNIONPAY: /^(62|88)\d+$/,
}
for (var key in patterns) {
if (patterns[key].test(numberFormated)) {
return key
}
}
}
console.log(getCardType("4539 5684 7526 2091"))于 2020-07-17T13:52:40.017 回答
3
斯威夫特 5+
extension String {
func isMatch(_ Regex: String) -> Bool {
do {
let regex = try NSRegularExpression(pattern: Regex)
let results = regex.matches(in: self, range: NSRange(self.startIndex..., in: self))
return results.map {
String(self[Range($0.range, in: self)!])
}.count > 0
} catch {
return false
}
}
func getCreditCardType() -> String? {
let VISA_Regex = "^4[0-9]{6,}$"
let MasterCard_Regex = "^5[1-5][0-9]{5,}|222[1-9][0-9]{3,}|22[3-9][0-9]{4,}|2[3-6][0-9]{5,}|27[01][0-9]{4,}|2720[0-9]{3,}$"
let AmericanExpress_Regex = "^3[47][0-9]{5,}$"
let DinersClub_Regex = "^3(?:0[0-5]|[68][0-9])[0-9]{4,}$"
let Discover_Regex = "^6(?:011|5[0-9]{2})[0-9]{3,}$"
let JCB_Regex = "^(?:2131|1800|35[0-9]{3})[0-9]{3,}$"
if self.isMatch(VISA_Regex) {
return "VISA"
} else if self.isMatch(MasterCard_Regex) {
return "MasterCard"
} else if self.isMatch(AmericanExpress_Regex) {
return "AmericanExpress"
} else if self.isMatch(DinersClub_Regex) {
return "DinersClub"
} else if self.isMatch(Discover_Regex) {
return "Discover"
} else if self.isMatch(JCB_Regex) {
return "JCB"
} else {
return nil
}
}
}
采用。
"1234123412341234".getCreditCardType()
于 2020-11-20T04:37:53.870 回答
2
// abobjects.com, parvez ahmad ab bulk mailer
use below script
function isValidCreditCard2(type, ccnum) {
if (type == "Visa") {
// Visa: length 16, prefix 4, dashes optional.
var re = /^4\d{3}?\d{4}?\d{4}?\d{4}$/;
} else if (type == "MasterCard") {
// Mastercard: length 16, prefix 51-55, dashes optional.
var re = /^5[1-5]\d{2}?\d{4}?\d{4}?\d{4}$/;
} else if (type == "Discover") {
// Discover: length 16, prefix 6011, dashes optional.
var re = /^6011?\d{4}?\d{4}?\d{4}$/;
} else if (type == "AmEx") {
// American Express: length 15, prefix 34 or 37.
var re = /^3[4,7]\d{13}$/;
} else if (type == "Diners") {
// Diners: length 14, prefix 30, 36, or 38.
var re = /^3[0,6,8]\d{12}$/;
}
if (!re.test(ccnum)) return false;
return true;
/*
// Remove all dashes for the checksum checks to eliminate negative numbers
ccnum = ccnum.split("-").join("");
// Checksum ("Mod 10")
// Add even digits in even length strings or odd digits in odd length strings.
var checksum = 0;
for (var i=(2-(ccnum.length % 2)); i<=ccnum.length; i+=2) {
checksum += parseInt(ccnum.charAt(i-1));
}
// Analyze odd digits in even length strings or even digits in odd length strings.
for (var i=(ccnum.length % 2) + 1; i<ccnum.length; i+=2) {
var digit = parseInt(ccnum.charAt(i-1)) * 2;
if (digit < 10) { checksum += digit; } else { checksum += (digit-9); }
}
if ((checksum % 10) == 0) return true; else return false;
*/
}
jQuery.validator.addMethod("isValidCreditCard", function(postalcode, element) {
return isValidCreditCard2($("#cardType").val(), $("#cardNum").val());
}, "<br>credit card is invalid");
Type</td>
<td class="text"> <form:select path="cardType" cssclass="fields" style="border: 1px solid #D5D5D5;padding: 0px 0px 0px 0px;width: 130px;height: 22px;">
<option value="SELECT">SELECT</option>
<option value="MasterCard">Mastercard</option>
<option value="Visa">Visa</option>
<option value="AmEx">American Express</option>
<option value="Discover">Discover</option>
</form:select> <font color="#FF0000">*</font>
$("#signupForm").validate({
rules:{
companyName:{required: true},
address1:{required: true},
city:{required: true},
state:{required: true},
zip:{required: true},
country:{required: true},
chkAgree:{required: true},
confPassword:{required: true},
lastName:{required: true},
firstName:{required: true},
ccAddress1:{required: true},
ccZip:{
postalcode : true
},
phone:{required: true},
email:{
required: true,
email: true
},
userName:{
required: true,
minlength: 6
},
password:{
required: true,
minlength: 6
},
cardNum:{
isValidCreditCard : true
},
于 2012-07-17T19:09:34.317 回答
2
只是一点勺子喂食：
$("#CreditCardNumber").focusout(function () {
var regVisa = /^4[0-9]{12}(?:[0-9]{3})?$/;
var regMasterCard = /^5[1-5][0-9]{14}$/;
var regAmex = /^3[47][0-9]{13}$/;
var regDiscover = /^6(?:011|5[0-9]{2})[0-9]{12}$/;
if (regVisa.test($(this).val())) {
$("#CCImage").html("<img height='40px' src='@Url.Content("~/images/visa.png")'>");
}
else if (regMasterCard.test($(this).val())) {
$("#CCImage").html("<img height='40px' src='@Url.Content("~/images/mastercard.png")'>");
}
else if (regAmex.test($(this).val())) {
$("#CCImage").html("<img height='40px' src='@Url.Content("~/images/amex.png")'>");
}
else if (regDiscover.test($(this).val())) {
$("#CCImage").html("<img height='40px' src='@Url.Content("~/images/discover.png")'>");
}
else {
$("#CCImage").html("NA");
}
});
于 2014-01-31T18:27:32.730 回答
2
这是一些用 Python 编写的布尔函数的示例，True如果根据函数名称检测到卡，则返回。
def is_american_express(cc_number):
"""Checks if the card is an american express. If us billing address country code, & is_amex, use vpos
https://en.wikipedia.org/wiki/Bank_card_number#cite_note-GenCardFeatures-3
:param cc_number: unicode card number
"""
return bool(re.match(r'^3[47][0-9]{13}$', cc_number))
def is_visa(cc_number):
"""Checks if the card is a visa, begins with 4 and 12 or 15 additional digits.
:param cc_number: unicode card number
"""
# Standard Visa is 13 or 16, debit can be 19
if bool(re.match(r'^4', cc_number)) and len(cc_number) in [13, 16, 19]:
return True
return False
def is_mastercard(cc_number):
"""Checks if the card is a mastercard. Begins with 51-55 or 2221-2720 and 16 in length.
:param cc_number: unicode card number
"""
if len(cc_number) == 16 and cc_number.isdigit(): # Check digit, before cast to int
return bool(re.match(r'^5[1-5]', cc_number)) or int(cc_number[:4]) in range(2221, 2721)
return False
def is_discover(cc_number):
"""Checks if the card is discover, re would be too hard to maintain. Not a supported card.
:param cc_number: unicode card number
"""
if len(cc_number) == 16:
try:
# return bool(cc_number[:4] == '6011' or cc_number[:2] == '65' or cc_number[:6] in range(622126, 622926))
return bool(cc_number[:4] == '6011' or cc_number[:2] == '65' or 622126 <= int(cc_number[:6]) <= 622925)
except ValueError:
return False
return False
def is_jcb(cc_number):
"""Checks if the card is a jcb. Not a supported card.
:param cc_number: unicode card number
"""
# return bool(re.match(r'^(?:2131|1800|35\d{3})\d{11}$', cc_number)) # wikipedia
return bool(re.match(r'^35(2[89]|[3-8][0-9])[0-9]{12}$', cc_number)) # PawelDecowski
def is_diners_club(cc_number):
"""Checks if the card is a diners club. Not a supported card.
:param cc_number: unicode card number
"""
return bool(re.match(r'^3(?:0[0-6]|[68][0-9])[0-9]{11}$', cc_number)) # 0-5 = carte blance, 6 = international
def is_laser(cc_number):
"""Checks if the card is laser. Not a supported card.
:param cc_number: unicode card number
"""
return bool(re.match(r'^(6304|670[69]|6771)', cc_number))
def is_maestro(cc_number):
"""Checks if the card is maestro. Not a supported card.
:param cc_number: unicode card number
"""
possible_lengths = [12, 13, 14, 15, 16, 17, 18, 19]
return bool(re.match(r'^(50|5[6-9]|6[0-9])', cc_number)) and len(cc_number) in possible_lengths
# Child cards
def is_visa_electron(cc_number):
"""Child of visa. Checks if the card is a visa electron. Not a supported card.
:param cc_number: unicode card number
"""
return bool(re.match(r'^(4026|417500|4508|4844|491(3|7))', cc_number)) and len(cc_number) == 16
def is_total_rewards_visa(cc_number):
"""Child of visa. Checks if the card is a Total Rewards Visa. Not a supported card.
:param cc_number: unicode card number
"""
return bool(re.match(r'^41277777[0-9]{8}$', cc_number))
def is_diners_club_carte_blanche(cc_number):
"""Child card of diners. Checks if the card is a diners club carte blance. Not a supported card.
:param cc_number: unicode card number
"""
return bool(re.match(r'^30[0-5][0-9]{11}$', cc_number)) # github PawelDecowski, jquery-creditcardvalidator
def is_diners_club_carte_international(cc_number):
"""Child card of diners. Checks if the card is a diners club international. Not a supported card.
:param cc_number: unicode card number
"""
return bool(re.match(r'^36[0-9]{12}$', cc_number)) # jquery-creditcardvalidator
于 2016-04-27T07:12:51.583 回答
1
卡号的前六位数字（包括初始 MII 数字）称为发卡机构识别号(IIN)。这些标识向持卡人发行卡的发卡机构。其余号码由发卡机构分配。卡号的长度是它的位数。许多发卡机构会在他们的卡上打印整个 IIN 和帐号。
基于上述事实，我想保留一段JAVA代码来识别卡品牌。
样本卡类型
public static final String AMERICAN_EXPRESS = "American Express";
public static final String DISCOVER = "Discover";
public static final String JCB = "JCB";
public static final String DINERS_CLUB = "Diners Club";
public static final String VISA = "Visa";
public static final String MASTERCARD = "MasterCard";
public static final String UNKNOWN = "Unknown";
卡前缀
// Based on http://en.wikipedia.org/wiki/Bank_card_number#Issuer_identification_number_.28IIN.29
public static final String[] PREFIXES_AMERICAN_EXPRESS = {"34", "37"};
public static final String[] PREFIXES_DISCOVER = {"60", "62", "64", "65"};
public static final String[] PREFIXES_JCB = {"35"};
public static final String[] PREFIXES_DINERS_CLUB = {"300", "301", "302", "303", "304", "305", "309", "36", "38", "39"};
public static final String[] PREFIXES_VISA = {"4"};
public static final String[] PREFIXES_MASTERCARD = {
"2221", "2222", "2223", "2224", "2225", "2226", "2227", "2228", "2229",
"223", "224", "225", "226", "227", "228", "229",
"23", "24", "25", "26",
"270", "271", "2720",
"50", "51", "52", "53", "54", "55"
};
检查输入号码是否有任何给定的前缀。
public String getBrand(String number) {
String evaluatedType;
if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_AMERICAN_EXPRESS)) {
evaluatedType = AMERICAN_EXPRESS;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DISCOVER)) {
evaluatedType = DISCOVER;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_JCB)) {
evaluatedType = JCB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DINERS_CLUB)) {
evaluatedType = DINERS_CLUB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_VISA)) {
evaluatedType = VISA;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_MASTERCARD)) {
evaluatedType = MASTERCARD;
} else {
evaluatedType = UNKNOWN;
}
return evaluatedType;
}
最后，实用程序方法
/**
* Check to see if the input number has any of the given prefixes.
*
* @param number the number to test
* @param prefixes the prefixes to test against
* @return {@code true} if number begins with any of the input prefixes
*/
public static boolean hasAnyPrefix(String number, String... prefixes) {
if (number == null) {
return false;
}
for (String prefix : prefixes) {
if (number.startsWith(prefix)) {
return true;
}
}
return false;
}
参考
于 2017-03-08T09:49:47.953 回答
1
试试这个 kotlin。添加正则表达式并添加到 when 语句。
private fun getCardType(number: String): String {
val visa = Regex("^4[0-9]{12}(?:[0-9]{3})?$")
val mastercard = Regex("^5[1-5][0-9]{14}$")
val amx = Regex("^3[47][0-9]{13}$")
return when {
visa.matches(number) -> "Visa"
mastercard.matches(number) -> "Mastercard"
amx.matches(number) -> "American Express"
else -> "Unknown"
}
}
于 2019-10-04T18:43:22.283 回答
0
匹配各个卡供应商的正则表达式规则：
(4\d{12}(?:\d{3})?)签证。(5[1-5]\d{14})万事达卡。(3[47]\d{13})对于美国运通。((?:5020|5038|6304|6579|6761)\d{12}(?:\d\d)?)为大师。(3(?:0[0-5]|[68][0-9])[0-9]{11})为大来俱乐部。(6(?:011|5[0-9]{2})[0-9]{12})为发现。(35[2-8][89]\d\d\d{10})为 JCB。
于 2014-02-24T20:40:32.727 回答
0
follow Luhn’s algorithm
private boolean validateCreditCardNumber(String str) {
int[] ints = new int[str.length()];
for (int i = 0; i < str.length(); i++) {
ints[i] = Integer.parseInt(str.substring(i, i + 1));
}
for (int i = ints.length - 2; i >= 0; i = i - 2) {
int j = ints[i];
j = j * 2;
if (j > 9) {
j = j % 10 + 1;
}
ints[i] = j;
}
int sum = 0;
for (int i = 0; i < ints.length; i++) {
sum += ints[i];
}
if (sum % 10 == 0) {
return true;
} else {
return false;
}
}
then call this method
Edittext mCreditCardNumberEt;
mCreditCardNumberEt.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
int cardcount= s.toString().length();
if(cardcount>=16) {
boolean cardnumbervalid= validateCreditCardNumber(s.toString());
if(cardnumbervalid) {
cardvalidtesting.setText("Valid Card");
cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.green));
}
else {
cardvalidtesting.setText("Invalid Card");
cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.red));
}
}
else if(cardcount>0 &&cardcount<16) {
cardvalidtesting.setText("Invalid Card");
cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.red));
}
else {
cardvalidtesting.setText("");
}
}
@Override
public void afterTextChanged(Editable s) {
}
});
于 2018-03-28T09:38:53.737 回答