0

我创建了一个按钮，当按下它时，它会在表格中显示单个数据库记录，它在桌面版本上完美运行，但是当我为 android 编译时它不起作用，你能帮我吗？

这是代码：

"""
O aplicativo de teste
"""
import toga
from toga.style import Pack
from toga.style.pack import COLUMN, ROW
import sqlite3
import asyncio

class KaiqueTeste(toga.App):

    def startup(self):

        main_box = toga.Box()
        self.label = toga.Label(text="Kaique Teste")
        self.lista = toga.Table(['Cod', 'Nome', 'CPF/CNPJ', 'RG/IE', 'Endereço', 'Cplt/Ende', 'Pont Ref', 'Bairro', 'Cidade', 'UF'], missing_value="")
        self.lista.MIN_HEIGHT = 180
        self.btn = toga.Button('CONFIRMA', style=Pack(padding=5), on_press=self.confirmar_cli)
        pasta = toga.Box(style=Pack(direction=COLUMN, padding=5))
        pasta.add(self.label)
        pasta.add(self.lista)
        pasta.add(self.btn)
        main_box.add(pasta)

        self.main_window = toga.MainWindow(title=self.formal_name)
        self.main_window.content = main_box
        self.main_window.show()

    async def confirmar_cli(self, widget):
        try:
            conn = sqlite3.connect(self.paths.app/'banco.db')
            c = conn.cursor()
            c.execute("SELECT cod, nome, cpf_cnpj, rg_ie, endereco, cplt_ende, pont_ref, bairro, cidade, uf FROM clientes WHERE cod = 1")
            dados_lidos = c.fetchall()
            await asyncio.sleep(0.1)

            self.lista.data = dados_lidos
            
        except Exception as ERROR:
            print(ERROR)


def main():
    return KaiqueTeste()
4

0 回答 0