目标:我想使用 Sympy 实现傅里叶-莫茨金消除。第一步是解决一些不平等问题。
问题:使用 Sympy 解决不等式的工具,如 solveset、solve_poly_inequality 或 reduce_inequalities 似乎不起作用。
数据:
from sympy import *
u1, u2, x1, x2 = symbols('u1 u2 x1 x2')
y1, y2, y3, y4, y5 = symbols('y1 y2 y3 y4 y5')
list_of_inequalities = [50*u2 - y5, -x2 + y5, 0, -u2 + 1, -35*u2 + y4 + y5, 35*u2 + x1 + x2 - y4 - y5 - 35, 35*u2 - y4 - y5, -35*u2 - x1 - x2 + y4 + y5 + 35, 50*y1 - y4, 50*u1 - x1 - 50*y1 + y4, -50*y1 + y4, -50*u1 + x1 + 50*y1 - y4, u2 - y1, -u1 - u2 + y1 + 1, 50*u2 - y5, -50*u2 - x2 + y5 + 50, 65*y1, 65*u1 - 65*y1, 35*u2 + 65*y1 - y4 - y5]
这些都是表达式>=0
。我想用傅里叶-莫茨金消除法去除所有的 y 变量。所以,第一步我想从y1
.
所需的解决方案:
例如list_of_inequalites[8]
,50*y1 - y4
我应该得到什么y1>=y4/50
或类似的。最后我想要两个列表。一种具有小于y1
which 将包含y4/50
的表达式,另一种具有大于 的表达式y1
。在傅里叶-莫茨金消除法的下一步中,我将需要这些列表。
我的尝试:
y_1=[]
for eq in list_of_equations:
expr= eq>=0
if y1 in eq.free_symbols:
y_1.append(solveset(expr.lhs>=0,y1,domain=S.Reals))
这样我得到一个这样的列表:
[ConditionSet(y1, 50*y1 - y4 >= 0, Reals), ConditionSet(y1, 50*u1 - x1 - 50*y1 + y4 >= 0, Reals), ConditionSet(y1, -50*y1 + y4 >= 0, Reals), ConditionSet(y1, -50*u1 + x1 + 50*y1 - y4 >= 0, Reals), ConditionSet(y1, u2 - y1 >= 0, Reals), ConditionSet(y1, -u1 - u2 + y1 + 1 >= 0, Reals), Interval(0, oo), ConditionSet(y1, 65*u1 - 65*y1 >= 0, Reals), ConditionSet(y1, 35*u2 + 65*y1 - y4 - y5 >= 0, Reals)]
我不明白如何处理这些条件集。它们当然不是我问题的解决方案。
另一种方法是使用solve_poly_inequality:
for eq in list_of_equations:
expr= eq>=0
if y1 in eq.free_symbols:
y_1.append(solve_poly_inequality(Poly(expr.lhs,y1),'>='))
这样我得到一个
NotImplementedError Traceback (most recent call last)
<ipython-input-269-686426e9455b> in <module>
9 expr= eq>=0
10 if y1 in eq.free_symbols:
---> 11 y_1.append(solve_poly_inequality(Poly(expr.lhs,y1),'>='))
~\Anaconda3\lib\site-packages\sympy\solvers\inequalities.py in solve_poly_inequality(poly, rel)
56 "could not determine truth value of %s" % t)
57
---> 58 reals, intervals = poly.real_roots(multiple=False), []
59
60 if rel == '==':
~\Anaconda3\lib\site-packages\sympy\polys\polytools.py in real_roots(f, multiple, radicals)
3498
3499 """
-> 3500 reals = sympy.polys.rootoftools.CRootOf.real_roots(f, radicals=radicals)
3501
3502 if multiple:
~\Anaconda3\lib\site-packages\sympy\polys\rootoftools.py in real_roots(cls, poly, radicals)
385 def real_roots(cls, poly, radicals=True):
386 """Get real roots of a polynomial. """
--> 387 return cls._get_roots("_real_roots", poly, radicals)
388
389 @classmethod
~\Anaconda3\lib\site-packages\sympy\polys\rootoftools.py in _get_roots(cls, method, poly, radicals)
717 raise PolynomialError("only univariate polynomials are allowed")
718
--> 719 coeff, poly = cls._preprocess_roots(poly)
720 roots = []
721
~\Anaconda3\lib\site-packages\sympy\polys\rootoftools.py in _preprocess_roots(cls, poly)
696 if not dom.is_ZZ:
697 raise NotImplementedError(
--> 698 "sorted roots not supported over %s" % dom)
699
700 return coeff, poly
NotImplementedError: sorted roots not supported over ZZ[x1,y4,u1]
导致此错误的不等式是50*u1 - x1 - 50*y1 + y4 >= 0
。
我发现解决不等式的最后一种方法是 reduce_inequalities:
for eq in list_of_equations:
expr= eq>=0
if y1 in eq.free_symbols:
y_1.append(reduce_inequalities(expr>=0,[y1]))
但是,这次我收到以下错误:
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-266-50cdf532f9fa> in <module>
22 expr= eq>=0
23 if y1 in eq.free_symbols:
---> 24 y_1.append(reduce_inequalities(expr>=0,[y1]))
25 # print(y_1[-1])
26
~\Anaconda3\lib\site-packages\sympy\solvers\inequalities.py in reduce_inequalities(inequalities, symbols)
985
986 # solve system
--> 987 rv = _reduce_inequalities(inequalities, symbols)
988
989 # restore original symbols and return
~\Anaconda3\lib\site-packages\sympy\solvers\inequalities.py in _reduce_inequalities(inequalities, symbols)
900 if len(common) == 1:
901 gen = common.pop()
--> 902 other.append(_solve_inequality(Relational(expr, 0, rel), gen))
903 continue
904 else:
~\Anaconda3\lib\site-packages\sympy\core\relational.py in __new__(cls, lhs, rhs, rop, **assumptions)
87 Eq and Ne; all other relationals expect
88 real expressions.
---> 89 '''))
90 # \\\
91 return rv
TypeError:
A Boolean argument can only be used in Eq and Ne; all other
relationals expect real expressions.
你有什么想法我可以解决这个问题吗?