在下面的场景中,Java async-profiler 是否是在比较 ArrayBlockingQueue 和 LinkedBlockingQueue 的性能时查看时间花费的正确工具?
在我的机器上,当消费者和生产者之间共享 50M 条目时,ABQ 的总执行时间总是比 LBQ 快 25%。两者的火焰图“几乎”相同,除了 LBQ 仅显示少数来自 JVM 对象分配代码的样本,但这并不能证明 25% 的增长是合理的。正如预期的那样,LBQ 中的 TLAB 分配要高得多。
我想知道,我怎样才能看到哪个活动(无论是代码还是硬件)正在花费时间?
亚军:
import java.util.*;
import java.util.concurrent.ArrayBlockingQueue;
import java.util.concurrent.BlockingQueue;
import java.util.concurrent.LinkedBlockingQueue;
public class Runner {
public static void main(String[] args) throws InterruptedException {
int size = 50_000_000;
BlockingQueue<Long> queue = new LinkedBlockingQueue<>(size);
Producer producer = new Producer(queue, size);
Thread t = new Thread(producer);
t.setName("ProducerItIs");
Consumer consumer = new Consumer(queue, size);
Thread t2 = new Thread(consumer);
t2.setName("ConsumerItIs");
t.start();
t2.start();
Thread.sleep(8000);
System.out.println("done");
queue.forEach(System.out::println);
System.out.println(queue.size());
}
}
制片人:
import java.util.Queue;
import java.util.Random;
import java.util.concurrent.BlockingQueue;
public class Producer implements Runnable {
public Producer(BlockingQueue<Long> blockingQueue, int size) {
this.queue = blockingQueue;
this.size = size;
}
private final BlockingQueue<Long> queue;
private final int size;
public void run() {
System.out.println("Started to produce...");
long nanos = System.nanoTime();
Long ii = (long) new Random().nextInt();
for (int j = 0; j < size; j++) {
queue.add(ii);
}
System.out.println("producer Time taken :" + ((System.nanoTime() - nanos) / 1e6));
}
}
消费者:
import java.util.concurrent.BlockingQueue;
public class Consumer implements Runnable {
private final BlockingQueue<Long> blockingQueue;
private final int size;
private Long value;
public Consumer(BlockingQueue<Long> blockingQueue, int size) {
this.blockingQueue = blockingQueue;
this.size = size;
}
public void run() {
long nanos = System.nanoTime();
System.out.println("Starting to consume...");
int i = 1;
try {
while (true) {
value = blockingQueue.take();
i++;
if (i >= size) {
break;
}
}
System.out.println("Consumer Time taken :" + ((System.nanoTime() - nanos)/1e6));
} catch (Exception exp) {
System.out.println(exp);
}
}
public long getValue() {
return value;
}
}