我需要将日期与今天进行比较。基本上我输入了 2/17/13,它会输出“昨天”。我已经尝试过echo date('l jS F', strtotime('2/15/13'));
,但它只会显示该日期而不是与今天进行比较。
问问题
153 次
5 回答
0
来自http://www.highlystructured.com/comparing_dates_php.html
$exp_date = "2006-01-16";
$todays_date = date("Y-m-d");
$today = strtotime($todays_date);
$expiration_date = strtotime($exp_date);
if ($expiration_date > $today) {
$valid = "yes";
} else {
$valid = "no";
}
于 2013-02-18T16:10:57.987 回答
0
这是一个示例,可以帮助您入门:
$when = '2/17/13';
$now = new DateTime();
// I append $now's time to $then, to make sure we compare
// the two dates using the same time of the day
// if you want to compare to $then at 00:00:00, leave it out
$then = new DateTime( $when . ' ' . $now->format( 'H:i:s' ) );
$diff = $now->diff( $then );
switch( $diff->days )
{
case 0:
echo 'today';
break;
case 1:
echo $diff->invert ? 'yesterday' : 'tomorrow';
break;
default:
echo $diff->invert ? $diff->days . ' days ago' : $diff->days . ' days from now';
break;
}
于 2013-02-18T16:23:56.377 回答
0
Drupal 附带了一个非常好的format_interval($interval, $granularity = 2, $langcode = NULL)
功能。
<?php
function format_interval($interval, $granularity = 2, $langcode = NULL) {
$units = array(
'1 year|@count years' => 31536000,
'1 month|@count months' => 2592000,
'1 week|@count weeks' => 604800,
'1 day|@count days' => 86400,
'1 hour|@count hours' => 3600,
'1 min|@count min' => 60,
'1 sec|@count sec' => 1,
);
$output = '';
foreach ($units as $key => $value) {
$key = explode('|', $key);
if ($interval >= $value) {
$output .= ($output ? ' ' : '') . format_plural(floor($interval / $value), $key[0], $key[1], array(), array('langcode' => $langcode));
$interval %= $value;
$granularity--;
}
if ($granularity == 0) {
break;
}
}
return $output ? $output : t('0 sec', array(), array('langcode' => $langcode));
}
?>
您无需运行 Drupal 即可使用它。只需在某处包含上述功能。但是,上面的函数也调用了format_plural()
- 调用t()
(两个自定义 Drupal 函数),所以你需要修改上面的函数或者包含所有的函数。
您的用例:
<?php
$today = date();
$compare = strtotime('2/15/13');
$interval = ($today - $compare);
print format_interval($interval, 1);
// Outputs '1 day'
?>
于 2013-02-18T16:29:32.303 回答
0
function checkDate($todaysDate,$expirationDate){
$today = strtotime($todays_date);
$expiration_date = strtotime($exp_date);
if ($expiration_date > $today) {
$valid = "yes";
} else {
$valid = "no";
}
return $valid
}
$expirationDate = "2006-01-16";
$todaysDate = date("Y-m-d");
$valid=checkDate($todaysDate,$expirationDate)
在函数中执行此操作,然后您可以将其与任何日期组合一起使用。然后,您可以使用一些条件扩展该函数,以确定它是否“昨天”。
于 2013-02-18T16:34:23.357 回答
0
function relativeTime($time) {
$d[0] = array(1,"second");
$d[1] = array(60,"minute");
$d[2] = array(3600,"hour");
$d[3] = array(86400,"day");
$d[4] = array(604800,"week");
$d[5] = array(2592000,"month");
$d[6] = array(31104000,"year");
$w = array();
$return = "";
$now = time();
$diff = ($now-$time);
$secondsLeft = $diff;
for($i=6;$i>-1;$i--)
{
$w[$i] = intval($secondsLeft/$d[$i][0]);
$secondsLeft -= ($w[$i]*$d[$i][0]);
if($w[$i]!=0)
{
$return.= abs($w[$i]) . " " . $d[$i][1] . (($w[$i]>1)?'s':'') ." ";
}
}
$return .= ($diff>0)?"ago":"left";
return $return;
}
于 2013-02-18T16:42:54.887 回答