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我正在开发一个 Django 应用程序，我遇到了一个我想评估的棘手的聚合查询。

在demo我的项目的应用程序中，我声明了以下模型类来表示图书馆的馆藏：

from django.db import models

class Book(models.Model):
    interesting = models.BooleanField()

class Library(models.Model):
    books = models.ManyToManyField(Book)

我想查询的是单个图书馆中“有趣”书籍的最大数量，这是每个图书馆中“有趣”的书籍数量的最大值。

在 SQL 中，这是：

select max(a.num_interesting_books) as max
from (select count(demo_book.id) as num_interesting_books
      from demo_book
      inner join demo_library_books on (demo_book.id = demo_library_books.book_id)
      where demo_book.interesting=TRUE
      group by demo_library_books.library_id) as a

 

使用以下测试数据：

insert into demo_library(id) values (1), (2), (3);
insert into demo_book(id, interesting) values
(1, FALSE), (2, FALSE), (3, TRUE),
(4, TRUE), (5, TRUE),
(6, TRUE), (7, TRUE), (8, TRUE), (9, FALSE);
insert into demo_library_books(library_id, book_id) values
(1, 1), (1, 2), (1, 3),
(2, 4), (2, 5),
(3, 6), (3, 7), (3, 8), (3, 9), (3, 3);

上述SELECT语句导致：

 max
-----
   4
(1 row)

正如预期的那样。

是否可以使用 Django 的查询 API 来计算这个值？

4

1 回答 1

9

我想我想通了：

Library.objects.filter(books__interesting=True).annotate(num_interesting_books=Count('pk')).aggregate(max=Max('num_interesting_books'))

翻译成SQL，这是：

select max(a.num_interesting_books) as max
from (select demo_library.*, count(demo_library.id) as num_interesting_books
      from demo_library
      inner join demo_library_books on (demo_library.id = demo_library_books.library_id)
      inner join demo_book on (demo_library_books.book_id = demo_book.id)
      where demo_book.interesting=TRUE
      group by demo_library.id) as a
于 2011-08-18T22:30:08.107 回答