2

我有以下代码:

   NSMutableSet* localSet = [[NSMutableSet alloc] initWithArray:symbols];
NSMutableArray* fetchedSymbolsArray = [NSMutableArray array];

for (NSDictionary* symbol in fetchedSymbols) {
    [fetchedSymbolsArray addObject:[NSDictionary dictionaryWithObject:[symbol valueForKey:@"symbol"] forKey:@"symbol"]];
}

NSMutableSet* serverSet = [[NSMutableSet alloc] initWithArray:fetchedSymbolsArray];

[localSet unionSet:serverSet];

for (NSDictionary* symbol in localSet) {
    NSLog(@"%@",[symbol valueForKey:@"symbol"]);
}

我希望 serverSet 中的所有内容都在 localSet 中。此代码没有反映这一点。

如果没有将任何重复项添加到 localSet 中,这也是更可取的。

编辑:这是我的日志:

2011-08-16 17:46:28.887 Stream[94612:207] YHOO
2011-08-16 17:46:28.887 Stream[94612:207] GOOG
2011-08-16 17:46:28.887 Stream[94612:207] INTC
2011-08-16 17:46:28.888 Stream[94612:207] BIDU
2011-08-16 17:46:28.888 Stream[94612:207] INTC
2011-08-16 17:46:28.888 Stream[94612:207] BIDU
2011-08-16 17:46:28.888 Stream[94612:207] AAPL
2011-08-16 17:46:28.888 Stream[94612:207] AAPL
2011-08-16 17:46:28.889 Stream[94612:207] AMD
2011-08-16 17:46:28.889 Stream[94612:207] GMCR
4

2 回答 2

6

尝试[localSet unionSet:serverSet]

编辑

这是只使用符号而不是NSDictionarys 的代码:

NSArray *symbols = [NSArray arrayWithObjects:@"AAPL",@"GOOG",@"INTC",@"YHOO",nil];

NSArray *fetchedSymbols = [NSArray arrayWithObjects:@"AMD",@"BIDU",@"GOOG",@"GMCR",@"INTC",@"YHOO",nil];


NSMutableSet* localSet = [[NSMutableSet alloc] initWithArray:symbols];
NSMutableSet* serverSet = [[NSMutableSet alloc] initWithArray:fetchedSymbols];

[localSet unionSet:serverSet];

for (id symbol in localSet) {
    NSLog(@"%@",symbol);
}

2011-08-16 18:25:22.107 so7086790[39810:a0f] YHOO
2011-08-16 18:25:22.116 so7086790[39810:a0f] AMD
2011-08-16 18:25:22.116 so7086790[39810:a0f] AAPL
2011-08-16 18:25:22.116 so7086790[39810:a0f] INTC
2011-08-16 18:25:22.117 so7086790[39810:a0f] GMCR
2011-08-16 18:25:22.117 so7086790[39810:a0f] GOOG
2011-08-16 18:25:22.118 so7086790[39810:a0f] BIDU
于 2011-08-17T00:45:06.450 回答
0

您的 serverSet 和 localSet 在联合中的方式错误 - 正在修改的集合是方法“unionSet:”的接收者,而不是参数。

NSMutableSet* localSet = [[NSMutableSet alloc] initWithArray:symbols];
NSMutableArray* fetchedSymbolsArray = [NSMutableArray array];

for (NSDictionary* symbol in fetchedSymbols) {
    [fetchedSymbolsArray addObject:[NSDictionary dictionaryWithObject:[symbol valueForKey:@"symbol"] forKey:@"symbol"]];
}

NSMutableSet* serverSet = [[NSMutableSet alloc] initWithArray:fetchedSymbolsArray];

[localSet unionSet:serverSet];

for (NSDictionary* symbol in localSet) {
    NSLog(@"%@",[symbol valueForKey:@"symbol"]);
}

请注意,根据定义,集合不允许重复条目。但这并不意味着您不会在字典中重复值,这意味着您不会两次拥有相同的“相等”字典(如果两个字典各自包含相同数量的条目,则它们是相等的,并且,对于给定的键,每个字典中对应的值对象满足 isEqual: 测试)。

为了避免特定字典值的重复,您必须自己添加它们。我建议您创建一个临时集,其中包含“符号”键的实际值,并使用该集来测试它是否已被添加。

NSMutableSet *localSetValues = [[NSMutableSet alloc] init];

// Add local set values
for (NSDictionary *symbol in localSet) {
    [localSetValues addObject:[symbol valueForKey:@"symbol"]];
}
// Add server set, conditionally
for (NSDictionary *symbol in serverSet) {
    if (![localSetValues containsObject:[symbol valueForKey:@"symbol"]]) {
        [localSet addObject:symbol];
    }
}

// Cleanup
[localSetValues release];

代替

[localSet unionSet:serverSet];
于 2011-08-17T00:47:00.927 回答