我编写了一个调用 Web 服务的 Android 代码。我现在想在我的实际手机而不是模拟器上运行该应用程序。当我使用 Android Emulator 和 url http://10.0.2.2/test/Service1.asmx运行应用程序时,我可以看到我的输出,但是当我将 url 更改为http://192.168.56.1/test/Service1.asmx,我在我的 Android 智能手机上看不到相同的输出。它给出了一个错误,说连接被拒绝。
请有人可以帮我解决这个问题
这是安卓代码:
package projects.ksoap2sample;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.*;
import android.os.*;
import android.widget.TextView;
public class ksoap2sample extends Activity {
/** Called when the activity is first created. */
private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld";
private static final String METHOD_NAME = "HelloWorld";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://192.168.56.1/test/Service1.asmx";
TextView tv;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
tv=(TextView)findViewById(R.id.text1);
call();
}
public void call()
{
try {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet=true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
Object result = (Object)envelope.getResponse();
tv.setText(result.toString());
} catch (Exception e) {
tv.setText(e.getMessage());
}
}
}