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我正在尝试查询表并使用结果列表重新渲染 LoadableDetachableModel。页面初始化时表为空。在 onSubmit 方法调用之后,表格从页面中移除并且模型消失了。我得到的只是JS错误。我可以看到该属性尚未呈现,但不知道为什么。

Uncaught TypeError: Cannot read properties of null (reading 'nextSibling')
    at Object.Wicket.replaceOuterHtmlSafari (wicket-ajax.js:214)
    at Object.Wicket.replaceOuterHtml (wicket-ajax.js:222)
    at wicket-ajax.js:931
    at Object.<anonymous> (wicket-ajax.js:91)

以下是相关代码:

final WebMarkupContainer listViewContainerForLogTable = new WebMarkupContainer("listViewContainerForLogTable");
        listViewContainerForLogTable.setOutputMarkupId(true);


final LoadableDetachableModel<List<BufferLogs>> bufferLogList = new LoadableDetachableModel<List<BufferLogs>>() {
            @Override
            protected List<BufferLogs> load() {
                return bufferLogsService.getAllLogs();
            };

        };


final PageableListView<BufferLogs> listViewForLogTable = new PageableListView<BufferLogs>("listViewForLogTable", bufferLogList,10) {

            @Override
            protected void populateItem(ListItem<BufferLogs> item) {

                final BufferLogs mobject = item.getModelObject();

                SimpleDateFormat formatter = new SimpleDateFormat("dd-M-yyyy");
                String date = formatter.format(mobject.getcDate());

                formatter = new SimpleDateFormat("HH:mm:ss");
                String time = formatter.format(mobject.getcDate());

                item.add(new Label("id", String.valueOf(mobject.getRowNum()) ));
                item.add(new Label("lineName", mobject.getLineName()));
                item.add(new Label("date", date));
                item.add(new Label("time", time));
                item.add(new Label("short", String.valueOf(mobject.getShortBuffer())));
                item.add(new Label("full", String.valueOf(mobject.getFullBuffer())));
                item.add(new Label("bufferOffset", String.valueOf(mobject.getBufferOffset() == null ? "" : mobject.getBufferOffset() ) ));

            }

        };

        listViewContainerForLogTable.add(listViewForLogTable);


AjaxButton submit = new AjaxButton("submit") {
            @Override
            protected void onSubmit(AjaxRequestTarget target, Form<?> form) {
                target.addComponent(listViewContainerForLogTable);
            }

            @Override
            protected void onError(AjaxRequestTarget target, Form<?> form) {
                target.addComponent(feedbackPanel);

            }

        };

listViewContainerForLogTable.add(navigator);
        add(listViewContainerForLogTable);
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1 回答 1

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该 JS 代码从 Wicket 1.6 之前的版本开始已有 10 年的历史。您应该升级到 Wicket 9(或至少 Wicket 8)。

于 2021-12-31T19:07:13.707 回答