我收到了来自https://rapidapi.com/的回复,我在网络上检索了类似的数据:
{1 item
"data":[1 item
0:{2 items
"screen_ID":"76"
"screen_data":{1 item
"icoData":{3 items
"data":[...
]3 items
"tabname":"ongoing"
"categories":[...
]13 items
}
}
}
]
}
当我尝试从https://json2csharp.com/将 JSON 转换为 C# 对象时,我收到:
Exception: Invalid character after parsing property name. Expected ':' but got: i. Path '', line 1, position 3.
有没有办法用这些数据快速创建对象?
我需要“数据”内容。