我有一个 tidygraph 对象的列表。在节点数据中，我有两列，即name和frequency。我想要做的是删除任何重复多次的列表元素（即tidygraph 对象）。希望我的例子可以解释更多：
首先，我创建了一些节点/边缘数据，将它们转换为 tidygraph 对象并将它们放在一个列表中：
library(tidygraph)
library(dplyr)
library(tidyr)
library(purrr)
library(stringr)
# create some node and edge data for the tbl_graph
nodes <- data.frame(name = c("x4", NA, NA),
val = c(1, 5, 2))
nodes2 <- data.frame(name = c("x4", NA, NA),
val = c(3, 2, 2))
nodes3 <- data.frame(name = c("x4", NA, NA),
val = c(5, 6, 7))
nodes4 <- data.frame(name = c("x4", "x2", NA, NA, "x1", NA, NA),
val = c(3, 2, 2, 1, 1, 2, 7))
nodes5 <- data.frame(name= c("x1", "x2", NA),
val = c(7, 4, 2))
nodes6 <- data.frame(name = c("x1", "x2", NA),
val = c(2, 1, 3))
edges <- data.frame(from = c(1,1), to = c(2,3))
edges1 <- data.frame(from = c(1, 2, 2, 1, 5, 5),
to = c(2, 3, 4, 5, 6, 7))
# create the tbl_graphs
tg <- tbl_graph(nodes = nodes, edges = edges)
tg_1 <- tbl_graph(nodes = nodes2, edges = edges)
tg_2 <- tbl_graph(nodes = nodes2, edges = edges)
tg_3 <- tbl_graph(nodes = nodes4, edges = edges1)
tg_4 <- tbl_graph(nodes = nodes5, edges = edges)
tg_5 <- tbl_graph(nodes = nodes6, edges = edges)
# put into list
myList <- list(tg, tg_1, tg_2, tg_3, tg_4, tg_5)
然后，我有一个小函数，它可以根据name列告诉我每个列表元素的频率。也就是说，如果列name在多个列表元素中重复/相同，则频率会增加。因此，在我上面的示例中，name列在我的列表中tg出现了 3 次（在tg、tg_1和中相同tg_2）......所以它的频率为 3。
然后，我向每个列表元素添加一frequency列并更改我的原始myList对象。例如：
freqs <- lapply(myList, function(x){
x %>%
pull(name) %>%
replace_na("..") %>%
paste0(collapse = "")
}) %>%
unlist(use.names = F) %>%
as_tibble() %>%
group_by(value) %>%
mutate(val = n():1) %>%
pull(val)
newList <- purrr::imap(myList, ~.x %>%
mutate(frequency = freqs[.y]) %>%
select(name, frequency))
现在查看newList返回：
> newList
[[1]]
# A tbl_graph: 3 nodes and 2 edges
#
# A rooted tree
#
# Node Data: 3 × 2 (active)
name frequency
<chr> <int>
1 x4 3
2 NA 3
3 NA 3
#
# Edge Data: 2 × 2
from to
<int> <int>
1 1 2
2 1 3
[[2]]
# A tbl_graph: 3 nodes and 2 edges
#
# A rooted tree
#
# Node Data: 3 × 2 (active)
name frequency
<chr> <int>
1 x4 2
2 NA 2
3 NA 2
#
# Edge Data: 2 × 2
from to
<int> <int>
1 1 2
2 1 3
[[3]]
# A tbl_graph: 3 nodes and 2 edges
#
# A rooted tree
#
# Node Data: 3 × 2 (active)
name frequency
<chr> <int>
1 x4 1
2 NA 1
3 NA 1
#
# Edge Data: 2 × 2
from to
<int> <int>
1 1 2
2 1 3
[[4]]
# A tbl_graph: 7 nodes and 6 edges
#
# A rooted tree
#
# Node Data: 7 × 2 (active)
name frequency
<chr> <int>
1 x4 1
2 x2 1
3 NA 1
4 NA 1
5 x1 1
6 NA 1
# … with 1 more row
#
# Edge Data: 6 × 2
from to
<int> <int>
1 1 2
2 2 3
3 2 4
# … with 3 more rows
[[5]]
# A tbl_graph: 3 nodes and 2 edges
#
# A rooted tree
#
# Node Data: 3 × 2 (active)
name frequency
<chr> <int>
1 x1 2
2 x2 2
3 NA 2
#
# Edge Data: 2 × 2
from to
<int> <int>
1 1 2
2 1 3
[[6]]
# A tbl_graph: 3 nodes and 2 edges
#
# A rooted tree
#
# Node Data: 3 × 2 (active)
name frequency
<chr> <int>
1 x1 1
2 x2 1
3 NA 1
#
# Edge Data: 2 × 2
from to
<int> <int>
1 1 2
2 1 3
所以我们可以看到该name列x4, NA, NA出现了 3 次......但不是将频率添加到每个......我似乎在倒数频率（不是故意的）......所以，x4, NA, NA说它的频率是 3，然后2 然后 1。
我正在尝试删除任何重复的列表元素并仅保留频率最高的元素。例如，我想要的输出如下所示：
> newList
[[1]]
# A tbl_graph: 3 nodes and 2 edges
#
# A rooted tree
#
# Node Data: 3 × 2 (active)
name frequency
<chr> <int>
1 x4 3
2 NA 3
3 NA 3
#
# Edge Data: 2 × 2
from to
<int> <int>
1 1 2
2 1 3
[[2]]
# A tbl_graph: 7 nodes and 6 edges
#
# A rooted tree
#
# Node Data: 7 × 2 (active)
name frequency
<chr> <int>
1 x4 1
2 x2 1
3 NA 1
4 NA 1
5 x1 1
6 NA 1
# … with 1 more row
#
# Edge Data: 6 × 2
from to
<int> <int>
1 1 2
2 2 3
3 2 4
# … with 3 more rows
[[3]]
# A tbl_graph: 3 nodes and 2 edges
#
# A rooted tree
#
# Node Data: 3 × 2 (active)
name frequency
<chr> <int>
1 x1 2
2 x2 2
3 NA 2
#
# Edge Data: 2 × 2
from to
<int> <int>
1 1 2
2 1 3
在这里，我们可以看到具有重复频率的元素已被删除......关于我如何做到这一点的任何建议？