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我正在尝试使用非常简单的 GUI 创建密码生成器。如果需要，我想为欧盟提供排除字符的能力。任何帮助都将不胜感激。

到目前为止，这是我所拥有的抛出“TypeError：只能将str（而不是“int”）连接到str”并且我无法终生处理为什么......

import os, random, string
from tkinter import *


# Password generation based on ascii letters, digits, and punctuation. 
def gen_password(password_length):
    initial_chars = string.ascii_letters + string.digits + string.punctuation
    characters = []
    for char in initial_chars:
        if char not in excluded_chars:
            characters += char
    else:
        print('Excluded characters: ' + char)
    
    # Seed the password with a random seed
    random.seed = (os.urandom(1024))
    random_str = ''.join(random.choice(characters) for _ in range(password_length))
    return random_str

# This will update the length of the password we generate based on whatever input number is entered
def update_password():
    try:
        count_chars = int(pass_len.get())
    except ValueError:
        return
    
    pass_box.config(state=NORMAL)
    pass_box.delete(0, 'end')
    pass_box.insert(0, gen_password(count_chars))
    pass_box.config(state=NORMAL)
    
mainWindow = Tk()
mainWindow.title('Griffin Password Generator 2.0')
mainWindow.resizable(0,0)

frame = Frame(mainWindow)

frame.pack(side=TOP, pady=10, padx=10, fill=X, expand=1)
Label(frame, text="Password Length: ", anchor=E).grid(row=0, column=0, sticky=E)
default_value = 16
pass_len = Entry(frame)
pass_len.insert(0, default_value)
pass_len.grid(row=0, column=1)

Label(frame, text="Excluded Characters: ", anchor=E).grid(row=1, column=0, sticky=E)
default_exclusions = ''
excluded_chars = Entry(frame)
excluded_chars.insert(0, default_exclusions)
excluded_chars.grid(row=1, column=1)

btn = Button(frame, text="Generate Password")
btn['command'] = lambda: update_password()
btn.grid(row=0, column=2, rowspan=2, padx=10, ipadx=10)

Label(frame, text="Generated Password: ", anchor=E).grid(row=2, column=0, sticky=E)
pass_box = Entry(frame)
pass_box.grid(row=2, column=1)

update_password()

# Open main window
mainWindow.mainloop()
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2 回答 2

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问题出在这行：

if char not in excluded_chars:

此时，excluded_chars是一个 Tkinter Entry 小部件。您可能想要参考小部件中显示的字符/文本。所以把上面的改成：

if char not in excluded_chars.get():

并且您的代码将运行而不会引发该异常。

于 2021-11-19T04:09:34.647 回答
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我终于找出了错误（在一些聪明的朋友的帮助下）：

该行excluded_chars = Entry(frame)似乎将条目保存为内存值或其他内容。因此，为了适应，我将第 10 行和第 13 行更改为 exclude_chars.get()，从而解决了这个问题。

于 2021-11-19T03:52:21.143 回答