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解密加密消息时出现此错误。我从 django 视图中的数据库中获取加密消息,pw = donator.objects.filter(emai=email).values('passw')并在 decrypt_message() 函数中传递 pw 对象。decrypt_messag() 函数是:

def decrypt_message(encrypted_message,key):
    """
    Decrypts an encrypted message
    """
    f = Fernet(key)
    decrypted_message = f.decrypt(encrypted_message)
    return decrypted_message.decode()

错误信息是:

File "C:\Users\Neelesh Singh\workspace\BookHouse\donatorapp\views.py", line 129, in decrypt_message
    f = Fernet(key)
  File "C:\Users\Neelesh Singh\AppData\Local\Programs\Python\Python39\lib\site-packages\cryptography\fernet.py", line 37, in __init__
    key = base64.urlsafe_b64decode(key)
  File "C:\Users\Neelesh Singh\AppData\Local\Programs\Python\Python39\lib\base64.py", line 131, in urlsafe_b64decode
    s = _bytes_from_decode_data(s)
  File "C:\Users\Neelesh Singh\AppData\Local\Programs\Python\Python39\lib\base64.py", line 45, in _bytes_from_decode_data
    raise TypeError("argument should be a bytes-like object or ASCII "
TypeError: argument should be a bytes-like object or ASCII string, not 'dict'
4

1 回答 1

0

您应该将与关联的项目传递passw给函数,因此:

pws = donator.objects.filter(emai=email).values('passw')
for pw in pws:
    #               use pw['passw'], not pw ↓
    decrypt_message(encrypted_message, pw['passw'])
于 2021-11-06T14:51:44.607 回答