0

我有一个包含 2 列的表，ContactName 和 Usertype。我有一个下拉列表，其中包含来自 ContactName 的数据。当我在下拉列表中选择任何值时，其用户类型应根据选择的内容显示。请帮我。到目前为止，我已经做了很多。当我在下拉列表中选择任何值时，会显示相同的值，但我想要用户类型。

<?php
    if(!isset($_SESSION)) {
        session_start(); 
    }

    $dingo=$_SESSION['dingo'];
    $query11="Select ISO3,Notify,Dingoid from rahul_tbl_users where Dingoid=$dingo";
    $query123=mysql_query($query11);
    $query1234=mysql_fetch_array($query123);
    $fetch=mysql_query("SELECT tdd.Dingoid,tc.Dingoid,tc.A_End,tbidd.OpportunityNumber,        tbidd.Status,tbidd.Country,tbidd.OpportunityName,tbidd.Allocatedto,tbidd.Email,tbidd.Customer,tbidd.Country,tbidd.ContactName,tc.Usertype,tbidd.G1_OPPID
        FROM  scott123.rahul_tbl_users tdd inner join scott123.rahul_user_opps tc on
        tdd.Dingoid=tc.Dingoid Inner Join scott123.rahul_tbl_opportunities tbidd
        on tc.A_End=tbidd.OpportunityNumber
        WHERE tc.Dingoid =$dingo");
    $fetch_result=mysql_fetch_array($fetch);
?>

<form method="post" action="">

<?php
    $SQLString="SELECT distinct(G1_OPPID),ContactName from rahul_tbl_opportunities where G1_OPPID IS NOT NULL and ContactName!='' ";
    $result1 = mysql_query($SQLString); 
    $select_box='<select name="select1"  id="select1" onchange="javascript:load_value(this.value);">';
    $input="";

    while($rows1 = mysql_fetch_array($result1)) {  
        $select_box .='<option id="user_name" value="'.$rows1["ContactName"].'">'.$rows1['ContactName'].'</option>';  
    }

    $input ='<input type="text" name="test" id="test" value="" />';

    echo $select_box."</select>";
    echo $input;
?>

<input type="submit" name="submit_name11" value="Add Permission"/>
<input type="submit" name="submit_name12" value="Edit Permission"/>   
</form>
4

1 回答 1

0

我收集的是您只想让文本框显示选择框中当前选择的内容吗？

将选择框中的 onchange 事件更改为：

onchange="transferValue();"

并添加此脚本标签：

<script type="text/javascript">
    function transferValue(){
        var selectBox = document.getElementById("select1");
        var selectedOption = selectBox.options[selectBox.selectedIndex].value;
        var textBox = document.getElementById("test");
        textBox.value = selectedOption;
    }

    window.onload = function(){
        transferValue();
    };
</script>
于 2013-05-25T21:18:20.333 回答